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Re: A company has 540 employees, 40% of whom are employed part time. If it [#permalink]
Thanks - the wording isn't that clear.
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Re: A company has 540 employees, 40% of whom are employed part time. If it [#permalink]
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Atrain13gm wrote:
Thanks - the wording isn't that clear.


I can understand your confusion. The GMAT would likely make it crystal clear what was being asked:

By what percent did the number of part-time employees increase?
By what percent did the ratio of part time employees to the total number of employees decrease?

Hope this helps!
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Re: A company has 540 employees, 40% of whom are employed part time. If it [#permalink]
Hello !

I have just solved the problem and I wonder why there is a discrepancy between the actual answer and the answer choice D.

To me (9/216)*100 = 4,16666 which is not equal to 4 1/6 %

Or maybe it is because 4 1/6% actually means (4 + 1/6)% and not (4 * 1/6)% ? Is it an american way of writing decimal numbers (am foreigner) ?
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Re: A company has 540 employees, 40% of whom are employed part time. If it [#permalink]
Hi i have a small doubt it may be silly but iam confused,thanks to help me.

Actually 9 members were added to part time job.So the count has increased from 216 to 225(216+9).
So i thought 1st we should find 225 is what percent of 600 - 40%(the original) So that we can get the increase in the percent.
Can you plz tell me where did i go worng:(
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Re: A company has 540 employees, 40% of whom are employed part time. If it [#permalink]
yea i did the same mistake first... was getting 225/600 as 37% but since the question asked increase..

i reverted to the methods suggested above... if the overall percentage was asked.. i think we could have attempted such a method... but since the q asks percentage increase of part time employees, 9/216*100 i the approriate calc
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Re: A company has 540 employees, 40% of whom are employed part time. If it [#permalink]
With 540 of employees, part time employed are 40% - 216 and 60% are full time - 324.
After hiring 60 new employees, 15% are part time i.e. 9 and 51 are full time.

Percent increase in the part time employees are (9/216)*100 = 25/6

My answer is D.
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Re: A company has 540 employees, 40% of whom are employed part time. If it [#permalink]
Atrain13gm wrote:
A company has 540 employees, 40% of whom are employed part time. If it hires 60 new employees, 15% of whom are employed part time, what will be the percent increase in part time employees?

A) 1 2/3 %
B) 2 2/3 %
C) 4 %
D) 4 1/6 %
E) 9 %


Total employees = 540 ; Part time = 216 ; Full Time = 324
Quote:
If it hires 60 new employees, 15% of whom are employed part time,

Total employees = 60 ; Part time = 9 ; Full Time = 51

After recruitment of 60 New employees -

Total employees = 600 ; Part time = 225 ; Full Time = 375

Quote:
What will be the percent increase in part time employees?


% Increase = \(\frac{9}{216}*100\) = \(4\frac{1}{6}\)

Hence, answer will be (D)
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A company has 540 employees, 40% of whom are employed part time. If it [#permalink]
Atrain13gm wrote:
A company has 540 employees, 40% of whom are employed part time. If it hires 60 new employees, 15% of whom are employed part time, what will be the percent increase in part time employees?

A) 1 2/3 %
B) 2 2/3 %
C) 4 %
D) 4 1/6 %
E) 9 %


Total employees \(= 540\)

Part time employees \(= 40\)% of \(540 = \frac{40}{100}* 540 = 216\)

Total number of new hires \(= 60\)

Part time employees in new hires \(= 15\)% of \(60 = \frac{15}{100} * 60 = 9\)

% increase of part time employees \(= (\) Difference of part time employees \(/\) Original number of part time employee\() * 100\)

Difference of part time employees is the increase of part time employee. That is \(= 9\)

Therefore Required percentage \(= \frac{9}{216} * 100 = 4 \frac{1}{6}\) %

Answer D
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Re: A company has 540 employees, 40% of whom are employed part time. If it [#permalink]
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Re: A company has 540 employees, 40% of whom are employed part time. If it [#permalink]
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