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Re: A rectangular solid has a surface area of 94 square inches. What is it [#permalink]
I have a different answer to this. I find each of the information suffecient. Please hear me out

Let the sides be a, b and c.

2(ab+bc+ac) = 94
Therefore, ab+bc+ac = 47.

Now, statement 1 = lets assume ab, side is 12

therefore, bc+ac = 35
(b+a).c =35
Now either b+a = 7 and c = 5 or
b+a = 5, c = 7
If b+a= 7, possible values of abc are (5,2,5) (4,3,5) or (6,1,5). However, only 1 combination gives 1 side area as 12 which is the (4,3,5)

If b+a=5 possible values of abc are (3,2,7) ,(4,1,7) . Ans none of them give 12 as the area. b+a will not be 5.

Therefore, the only possible value is (3,4,5)

Similarly, I found the same value by Statement 2 and I think both are sufficient on their own.

Please help me understand where I am wrong.
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Re: A rectangular solid has a surface area of 94 square inches. What is it [#permalink]
Bunuel VeritasPrepKarishma
Could you please clarify, as even I feel that answer should be D.

l*b+b*w+w*l=47

From B: Assuming l*b=20, we have w(l+b)=27, only combination that satisfies is l & b equals 5 & 4, hence w=3.
Similarly answer can be derived from A as well.
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Re: A rectangular solid has a surface area of 94 square inches. What is it [#permalink]
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ravjai81 wrote:
Bunuel VeritasPrepKarishma
Could you please clarify, as even I feel that answer should be D.

l*b+b*w+w*l=47

From B: Assuming l*b=20, we have w(l+b)=27, only combination that satisfies is l & b equals 5 & 4, hence w=3.
Similarly answer can be derived from A as well.


We are not told that the dimensions of the solid are necessarily integers.
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Re: A rectangular solid has a surface area of 94 square inches. What is it [#permalink]
1) insufficient LB =12 H=?
2) insufficient BH = 20 L=?
combine 1&2
LB=12, BH=20
total area =94
2(LB+LB+LH) =94
LB+BH+LH=47
LB=12 BH=20 so LH=15
we dont require to calculate l,b,h
JUST MULTIPLY ALL
LBxBHxLH= (LBH)^2 = V^2
12x20x15 = V
Definite Ans C
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Re: A rectangular solid has a surface area of 94 square inches. What is it [#permalink]
Thanks Bunuel and Sahilvijay
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Re: A rectangular solid has a surface area of 94 square inches. What is it [#permalink]
Answer is C

We are given volume as 94
Let's assume a,b,c as the 3 sides. It implies that abc=94

Statement 1: one side area is 12
Let these two sides be a and b. Thus, a*b= 12
Statement 2: other area is 20.
Thus, let these sides be b*c=20(wouldn't make a difference if you choose a*c)

Now we have 3 equations and 3 variables. Which will help us fetch the 3 sides. Thus, we will have all the values to use the surface area formula, 2(ab+bc+ac)

Note: please don't waste time finding these variables. 3 unique equations will give you the values of 3 variables.

Sent from my DUK-L09 using GMAT Club Forum mobile app
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Re: A rectangular solid has a surface area of 94 square inches. What is it [#permalink]
GMATinsight,

Very nice explanation, But I want to add one thing...
After this step "lh= 47-12-20=15"

we need not find the value of l, b, h .
Volume = lbh = (lb*bh*hl)^0.5 and hence it can be calcualted to be 60 (thought we need not calculate).

Hence C is the answer.

GMATinsight wrote:
Bunuel wrote:
A rectangular solid has a surface area of 94 square inches. What is its volume?

(1) The surface area of one side of the rectangular solid is 12.

(2) The surface area of one side of the rectangular solid is 20.


2(lb+BH+lh)=94
I.e. lb+BH+lh=47

Statement 1: lb=12
Not sufficient

Statement 2: bh=20
Not sufficient

Combining
lh= 47-12-20=15

Only possibility of l,b,h are 3,4,5
Hence volume = 60

Sufficient

Answer Option C
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Re: A rectangular solid has a surface area of 94 square inches. What is it [#permalink]
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