Last visit was: 26 Apr 2024, 13:54 It is currently 26 Apr 2024, 13:54

Close
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track
Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Close
Request Expert Reply
Confirm Cancel
SORT BY:
Date
Tags:
Show Tags
Hide Tags
Intern
Intern
Joined: 21 Mar 2016
Posts: 20
Own Kudos [?]: 16 [15]
Given Kudos: 200
Send PM
RC & DI Moderator
Joined: 02 Aug 2009
Status:Math and DI Expert
Posts: 11181
Own Kudos [?]: 31966 [1]
Given Kudos: 291
Send PM
Intern
Intern
Joined: 07 Jan 2014
Posts: 14
Own Kudos [?]: 15 [1]
Given Kudos: 29
Location: India
Send PM
Director
Director
Joined: 20 Sep 2016
Posts: 559
Own Kudos [?]: 933 [0]
Given Kudos: 632
Location: India
Concentration: Strategy, Operations
GPA: 3.6
WE:Operations (Consumer Products)
Send PM
Re: Two identical urns—black and white—each contain 5 blue, 5 red and 10 [#permalink]
deushyant wrote:
Are we expected to know values of quarters, dimes and nickles?

Posted from my mobile device


deushyant
Absolutely not . Nickel and Dime are not globally recognized US currencies .By glovally recognised i mean the currencies are not used in global transaction units

The only values you should know are "cents" and "dollars" ... This qustion seems as a self made. Choices B and C are flawed as probab9ility is never more than 1 . Please practice from GMAT trusted sources only. Use the tags for refining your question bank
VP
VP
Joined: 10 Jul 2019
Posts: 1392
Own Kudos [?]: 542 [0]
Given Kudos: 1656
Send PM
Two identical urns—black and white—each contain 5 blue, 5 red and 10 [#permalink]
A lot of words to get through, but not too hard if you take a little time to think about it.

There is only way one that she will not be able to afford a 25 cent chocolate bar: she must draw Green balls FOUR Times: two green from each urn. G-G-G-G ———> 5 + 5 + 5 + 5 = 20 cents

Any other combination of balls will allow her to buy the candy bar. The next lowest amount she could possibly get is: G-G-G-R ——-> 5 + 5 + 5 + 10 = 25 cents, which is enough.

To find the probability that she will be able to afford the candy bar, we can take:

1 - (Prob. of Unfavorable Outcome) = Prob. of Favorable Outcome


Probability of Pulling 2 Green balls from the Black urn, when the 1st ball is replaced is:

(10/20) * (10/20) = (1/2) * (1/2) = 1/4

AND

Probability of pulling 2 Green balls from the White urn when the balls are NOT replaced after taking one:

(10/20) * (9/19) = (1/2) * (9/19) = 9/38


Probability of the Unfavorable Outcome of pulling 2 green from the Black urn and pulling 2 green from the White urn therefore is = (1/4) * (9/38) = 9/152


1 - (9/152) = 143/152

(A)

Posted from my mobile device
Target Test Prep Representative
Joined: 14 Oct 2015
Status:Founder & CEO
Affiliations: Target Test Prep
Posts: 18767
Own Kudos [?]: 22062 [0]
Given Kudos: 283
Location: United States (CA)
Send PM
Re: Two identical urnsblack and whiteeach contain 5 blue, 5 red and 10 [#permalink]
Expert Reply
iiindiangirl wrote:
Two identical urns—black and white—each contain 5 blue, 5 red and 10 green balls. Every ball
selected from the black urn is immediately returned to the urn, while each ball selected from the white urn is
removed and placed on a table. If Jenny receives a quarter for every blue ball, a dime for every red ball and a
nickel for every green ball she selects, what is the probability that she will be able to buy a 25-cent candy bar
with the proceeds from drawing four balls—two from each urn?

A) 143/152
B) 143/154
C) 121/180
D) 271/965
E) 152/1000


We should notice that the only way Jenny will not be able to earn 25 cents after four draws is if she draws a green ball in each of the four draws. If she draws even a single blue ball, she receives a quarter, which is enough to buy the candy bar regardless of the remaining three draws. If she does not draw a blue ball but draws a red ball, then the minimum amount she will earn is 10 + 5 + 5 + 5 = 25 cents. Thus, if we can calculate the probability that she will draw a green ball all four draws, we can simply subtract that number from 1 to calculate the probability that she earns at least 25 cents.

Since the draws from the black urn are made with replacement, the probability that she will draw two green balls from the black urn is 10/20 * 10/20 = 1/4. Since the draws from the white urn are made without replacement, the probability that she will draw two green balls from the white urn is 10/20 * 9/19 = 9/38. Thus, the probability that she draws green balls in all her draws is 1/4 * 9/38 = 9/152. It follows that the probability that she draws at least one non-green ball is 1 - 9/152 = 143/152.

Answer: A
Intern
Intern
Joined: 03 Jul 2018
Posts: 11
Own Kudos [?]: 6 [0]
Given Kudos: 8
Send PM
Re: Two identical urnsblack and whiteeach contain 5 blue, 5 red and 10 [#permalink]
chetan2u wrote:
divyanshig wrote:
Two identical urns—black and white—each contain 5 blue, 5 red and 10 green balls. Every ball
selected from the black urn is immediately returned to the urn, while each ball selected from the white urn is
removed and placed on a table. If Jenny receives a quarter for every blue ball, a dime for every red ball and a
nickel for every green ball she selects, what is the probability that she will be able to buy a 25-cent candy bar
with the proceeds from drawing four balls—two from each urn?

A) 143/152
B) 143/76
C) 121/120
D) 271/965
E) 152/1000



Firstly the Probability can never be GREATER than 1, probability of 1 itself means that the event is sure to happen..
So choices B and C are flawed....
Of course the choices should be in some order...

Back to the question...
So we are looking at price equal to or more than 25 cents...
Only way it will be less than 25 will be when we get a nickel in each draw, so let us choose easier path with lesser calculations....
So first draw from black a will be 10/20 and the second too will be 10/20..
First draw in white urn will be 10/20 but the second will be 9/19 ..
Probability of not being able to buy... (10/20)(10/20)(10/20)(9/19)=(1/2)(1/2)(1/2)(9/19)=9/(2*2*2*19)=9/152..
So probability of buying is 1-(9/152)=143/152

A



Why are not considering two ways because in question it is not given he/she will start selection from which colour urn whether black or white. As there colour is different i think we should multiply by 2
Intern
Intern
Joined: 08 Dec 2020
Posts: 1
Own Kudos [?]: 3 [0]
Given Kudos: 2
Send PM
Re: Two identical urnsblack and whiteeach contain 5 blue, 5 red and 10 [#permalink]
iiindiangirl wrote:
Two identical urns—black and white—each contain 5 blue, 5 red and 10 green balls. Every ball
selected from the black urn is immediately returned to the urn, while each ball selected from the white urn is
removed and placed on a table. If Jenny receives a quarter for every blue ball, a dime for every red ball and a
nickel for every green ball she selects, what is the probability that she will be able to buy a 25-cent candy bar
with the proceeds from drawing four balls—two from each urn?

A) 143/152
B) 143/154
C) 121/180
D) 271/965
E) 152/1000


To calculate the probability that Jenny will be able to buy a 25-cent candy bar with the proceeds from drawing four balls (2 from each urn), we need to consider all possible combinations of balls that add up to 25 cents and divide that by the total number of combinations of drawing 4 balls (2 from each urn).

For Jenny to buy the candy bar, she needs 25 cents, which can be obtained by either selecting 2 blue balls (25 cents), or 1 blue and 1 red ball (15 cents), or 2 red balls (20 cents), or 1 red and 5 green balls (15 cents), or 1 blue and 10 green balls (15 cents), or 2 green balls (10 cents), or 5 green balls (25 cents).

From the black urn, there are 5 choose 2 = 10 combinations of blue balls, 5 choose 2 = 10 combinations of red balls, and 10 choose 2 = 45 combinations of green balls.

From the white urn, there are 5 choose 2 = 10 combinations of blue balls, 5 choose 2 = 10 combinations of red balls, and 10 choose 2 = 45 combinations of green balls.

Therefore, the number of combinations that result in 25 cents is 10 x 10 + 10 x 10 + 10 x 10 + 10 x 10 + 45 x 45 = 143.

The total number of combinations of drawing 4 balls (2 from each urn) is 20 choose 2 x 20 choose 2 = 19600.

So, the probability that she will be able to buy a 25-cent candy bar is 143/19600 = 143/152.
GMAT Club Bot
Re: Two identical urnsblack and whiteeach contain 5 blue, 5 red and 10 [#permalink]
Moderators:
Math Expert
92948 posts
Senior Moderator - Masters Forum
3137 posts

Powered by phpBB © phpBB Group | Emoji artwork provided by EmojiOne