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In an event, only salesmen and guests participated.
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17 Mar 2019, 10:00
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In an event, only salesmen and guests participated. 80% of the salesmen and 40% of the guests participated in one-on-one information sessions. If each participating salesman involved in 5 such information sessions, what percentage of the attendees involved in the one-on-one information sessions?
A) 15% B) 33% C) 44% D) 48% E) More than 48%
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Re: In an event, only salesmen and guests participated.
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19 Mar 2019, 12:06
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eswarchethu135 wrote:
In an event, only salesmen and guests participated. 80% of the salesmen and 40% of the guests participated in one-on-one information sessions. If each participating salesman involved in 5 such information sessions, what percentage of the attendees involved in the one-on-one information sessions?
A) 15% B) 33% C) 44% D) 48% E) More than 48%
80*5 = 400 guests = 40 total attendes= 440 so total interactions per sales and guest = 40/400 = .1 .1*440 = 44 IMO C
Re: In an event, only salesmen and guests participated.
[#permalink]
16 Oct 2019, 06:38
eswarchethu135 wrote:
In an event, only salesmen and guests participated. 80% of the salesmen and 40% of the guests participated in one-on-one information sessions. If each participating salesman involved in 5 such information sessions, what percentage of the attendees involved in the one-on-one information sessions?
In my opinion, more information is needed. Can salesmen meet with other salesmen? Can guests meet with other guests? Can a salesman meet with a guest more than once?
For example, there could 5 salesmen and 5 guests, which means 4 salesmen (4/5 = 80%) and 2 guests (2/5 = 40%) went to the sessions. Let the 4 salesmen be A, B, C, and D Let the 2 guests be Y and Z
So, the meetings could have gone as follows: AY, AY, AY, AY, AZ BY, BZ, BY, BZ, BZ CY, CZ, CY, CZ, CZ DY, DZ, DY, DZ, DZ
This satisfies all parts of the question.
In this case, there are 10 attendees, and 6 of them attended sessions (6/10 = 60%)
In my opinion, more information is needed. Can salesmen meet with other salesmen? Can guests meet with other guests? Can a salesman meet with a guest more than once?
For example, there could 5 salesmen and 5 guests, which means 4 salesmen (4/5 = 80%) and 2 guests (2/5 = 40%) went to the sessions. Let the 4 salesmen be A, B, C, and D Let the 2 guests be Y and Z
So, the meetings could have gone as follows: AY, AY, AY, AY, AZ BY, BZ, BY, BZ, BZ CY, CZ, CY, CZ, CZ DY, DZ, DY, DZ, DZ
This satisfies all parts of the question.
In this case, there are 10 attendees, and 6 of them attended sessions (6/10 = 60%)
Cheers, Brent
Hi Brent,
Thanks for your care to answer my concern. I felt the same like you. However, the creator in his question put as follows :
Let number of salesmen = S, and guests =G
0.8 S * 5 = 0.4 G ...I do not understand the logic behind this step. Do you have any explanation that stems from the question above??
Re: In an event, only salesmen and guests participated.
[#permalink]
16 Oct 2019, 07:30
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Mo2men wrote:
Hi Brent,
Thanks for your care to answer my concern. I felt the same like you. However, the creator in his question put as follows :
Let number of salesmen = S, and guests =G
0.8 S * 5 = 0.4 G ...I do not understand the logic behind this step. Do you have any explanation that stems from the question above??
Again thanks
If S = number of salesmen, then 0.8S = number of salesmen who participated in sessions. Each of those 0.8S salesmen had 5 sessions. So, (5)(0.8S) = TOTAL number of sessions.
Likewise, 0.4G = number of guests who participated in sessions. We aren't told how many sessions each of these 0.4G guests attended. So, let k = number of sessions EACH guest attended So, (k)(0.4G) = TOTAL number of sessions.
Re: In an event, only salesmen and guests participated.
[#permalink]
16 Oct 2019, 07:51
GMATPrepNow wrote:
Mo2men wrote:
Hi Brent,
Thanks for your care to answer my concern. I felt the same like you. However, the creator in his question put as follows :
Let number of salesmen = S, and guests =G
0.8 S * 5 = 0.4 G ...I do not understand the logic behind this step. Do you have any explanation that stems from the question above??
Again thanks
If S = number of salesmen, then 0.8S = number of salesmen who participated in sessions. Each of those 0.8S salesmen had 5 sessions. So, (5)(0.8S) = TOTAL number of sessions.
Likewise, 0.4G = number of guests who participated in sessions. We aren't told how many sessions each of these 0.4G guests attended. So, let k = number of sessions EACH guest attended So, (k)(0.4G) = TOTAL number of sessions.
NOW, we can write: (5)(0.8S) = (k)(0.4G)
Thanks again Brent But is not total number of sessions = (k)(0.4G) + (5)(0.8S)...So it is still unclear to me established equation..
Can you please bear with with me and elaborate more?
Re: In an event, only salesmen and guests participated.
[#permalink]
16 Oct 2019, 08:19
1
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Expert Reply
Top Contributor
Mo2men wrote:
GMATPrepNow wrote:
Mo2men wrote:
Hi Brent,
Thanks for your care to answer my concern. I felt the same like you. However, the creator in his question put as follows :
Let number of salesmen = S, and guests =G
0.8 S * 5 = 0.4 G ...I do not understand the logic behind this step. Do you have any explanation that stems from the question above??
Again thanks
If S = number of salesmen, then 0.8S = number of salesmen who participated in sessions. Each of those 0.8S salesmen had 5 sessions. So, (5)(0.8S) = TOTAL number of sessions.
Likewise, 0.4G = number of guests who participated in sessions. We aren't told how many sessions each of these 0.4G guests attended. So, let k = number of sessions EACH guest attended So, (k)(0.4G) = TOTAL number of sessions.
NOW, we can write: (5)(0.8S) = (k)(0.4G)
Thanks again Brent But is not total number of sessions = (k)(0.4G) + (5)(0.8S)...So it is still unclear to me established equation..
Can you please bear with with me and elaborate more?
Thanks in advance
The problem is that we don't have enough information (in my opinion)
I'm going to assume that each Guest attends exactly ONE session. In other words, k = 1 Let's see what happens....
We get: If S = number of salesmen, then 0.8S = number of salesmen who participated in sessions. Each of those 0.8S salesmen had 5 sessions. So, (5)(0.8S) = TOTAL number of sessions.
Likewise, 0.4G = number of guests who participated in sessions. We aren't told how many sessions each of these 0.4G guests attended. IF we assume that each guest attends exactly one session, then (1)(0.4G) = TOTAL number of sessions.
NOW, we can write: (5)(0.8S) = (1)(0.4G) Simplify: 4S = 0.4G Divide both sides by 0.4 to get: 10S = G
At this point, we have all of the info we need. If there are G guests, and 40% of them participated in one-on-one information sessions Then the number of GUEST session attendees = 0.4G Since, 10S = G, we can also write: the number of GUEST session attendees = 0.4(10S) = 4S
From earlier, we also know that the number of SALESMEN session attendees = 0.8S
So, the TOTAL number of SESSION attendees 4S + 0.8S = 4.8S
Now the TOTAL number of PARTY attendees = G + S = 10S + S = 11S
So, the percentage of the attendees involved in the one-on-one information sessions = 4.8S/11S ≈ 43.6%
Okay, that's pretty much all the time I want to devote to this question.
Cheers, Brent
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Re: In an event, only salesmen and guests participated. [#permalink]