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In an event, only salesmen and guests participated.

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In an event, only salesmen and guests participated.  [#permalink]

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New post 17 Mar 2019, 10:00
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Difficulty:

  85% (hard)

Question Stats:

33% (02:32) correct 67% (02:22) wrong based on 33 sessions

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In an event, only salesmen and guests participated. 80% of the salesmen and 40% of the guests participated in one-on-one information sessions. If each participating salesman involved in 5 such information sessions, what percentage of the attendees involved in the one-on-one information sessions?

A) 15%
B) 33%
C) 44%
D) 48%
E) More than 48%

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if you like my explanation!!!
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Re: In an event, only salesmen and guests participated.  [#permalink]

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New post 19 Mar 2019, 12:06
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eswarchethu135 wrote:
In an event, only salesmen and guests participated. 80% of the salesmen and 40% of the guests participated in one-on-one information sessions. If each participating salesman involved in 5 such information sessions, what percentage of the attendees involved in the one-on-one information sessions?

A) 15%
B) 33%
C) 44%
D) 48%
E) More than 48%


80*5 = 400
guests = 40
total attendes= 440
so total interactions per sales and guest = 40/400 = .1
.1*440 = 44
IMO C
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Re: In an event, only salesmen and guests participated.  [#permalink]

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New post 16 Oct 2019, 06:38
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eswarchethu135 wrote:
In an event, only salesmen and guests participated. 80% of the salesmen and 40% of the guests participated in one-on-one information sessions. If each participating salesman involved in 5 such information sessions, what percentage of the attendees involved in the one-on-one information sessions?

A) 15%
B) 33%
C) 44%
D) 48%
E) More than 48%



Dear EMPOWERgmatRichC Kinshook GMATPrepNow

Can you please help understand this question?

Thanks in advance for your help
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Re: In an event, only salesmen and guests participated.  [#permalink]

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New post 16 Oct 2019, 06:54
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Mo2men wrote:
Dear EMPOWERgmatRichC Kinshook GMATPrepNow

Can you please help understand this question?

Thanks in advance for your help


In my opinion, more information is needed.
Can salesmen meet with other salesmen?
Can guests meet with other guests?
Can a salesman meet with a guest more than once?

For example, there could 5 salesmen and 5 guests, which means 4 salesmen (4/5 = 80%) and 2 guests (2/5 = 40%) went to the sessions.
Let the 4 salesmen be A, B, C, and D
Let the 2 guests be Y and Z

So, the meetings could have gone as follows:
AY, AY, AY, AY, AZ
BY, BZ, BY, BZ, BZ
CY, CZ, CY, CZ, CZ
DY, DZ, DY, DZ, DZ

This satisfies all parts of the question.

In this case, there are 10 attendees, and 6 of them attended sessions (6/10 = 60%)

Cheers,
Brent
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Re: In an event, only salesmen and guests participated.  [#permalink]

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New post 16 Oct 2019, 07:03
GMATPrepNow wrote:
Mo2men wrote:
Dear EMPOWERgmatRichC Kinshook GMATPrepNow

Can you please help understand this question?

Thanks in advance for your help


In my opinion, more information is needed.
Can salesmen meet with other salesmen?
Can guests meet with other guests?
Can a salesman meet with a guest more than once?

For example, there could 5 salesmen and 5 guests, which means 4 salesmen (4/5 = 80%) and 2 guests (2/5 = 40%) went to the sessions.
Let the 4 salesmen be A, B, C, and D
Let the 2 guests be Y and Z

So, the meetings could have gone as follows:
AY, AY, AY, AY, AZ
BY, BZ, BY, BZ, BZ
CY, CZ, CY, CZ, CZ
DY, DZ, DY, DZ, DZ

This satisfies all parts of the question.

In this case, there are 10 attendees, and 6 of them attended sessions (6/10 = 60%)

Cheers,
Brent



Hi Brent,

Thanks for your care to answer my concern. I felt the same like you. However, the creator in his question put as follows :

Let number of salesmen = S, and guests =G

0.8 S * 5 = 0.4 G ...I do not understand the logic behind this step. Do you have any explanation that stems from the question above??

Again thanks
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Re: In an event, only salesmen and guests participated.  [#permalink]

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New post 16 Oct 2019, 07:30
Top Contributor
Mo2men wrote:
Hi Brent,

Thanks for your care to answer my concern. I felt the same like you. However, the creator in his question put as follows :

Let number of salesmen = S, and guests =G

0.8 S * 5 = 0.4 G ...I do not understand the logic behind this step. Do you have any explanation that stems from the question above??

Again thanks


If S = number of salesmen, then 0.8S = number of salesmen who participated in sessions.
Each of those 0.8S salesmen had 5 sessions.
So, (5)(0.8S) = TOTAL number of sessions.

Likewise, 0.4G = number of guests who participated in sessions.
We aren't told how many sessions each of these 0.4G guests attended.
So, let k = number of sessions EACH guest attended
So, (k)(0.4G) = TOTAL number of sessions.

NOW, we can write: (5)(0.8S) = (k)(0.4G)
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Re: In an event, only salesmen and guests participated.  [#permalink]

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New post 16 Oct 2019, 07:51
GMATPrepNow wrote:
Mo2men wrote:
Hi Brent,

Thanks for your care to answer my concern. I felt the same like you. However, the creator in his question put as follows :

Let number of salesmen = S, and guests =G

0.8 S * 5 = 0.4 G ...I do not understand the logic behind this step. Do you have any explanation that stems from the question above??

Again thanks


If S = number of salesmen, then 0.8S = number of salesmen who participated in sessions.
Each of those 0.8S salesmen had 5 sessions.
So, (5)(0.8S) = TOTAL number of sessions.

Likewise, 0.4G = number of guests who participated in sessions.
We aren't told how many sessions each of these 0.4G guests attended.
So, let k = number of sessions EACH guest attended
So, (k)(0.4G) = TOTAL number of sessions.

NOW, we can write: (5)(0.8S) = (k)(0.4G)


Thanks again Brent But is not total number of sessions = (k)(0.4G) + (5)(0.8S)...So it is still unclear to me established equation..

Can you please bear with with me and elaborate more?

Thanks in advance
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Re: In an event, only salesmen and guests participated.  [#permalink]

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New post 16 Oct 2019, 08:19
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Mo2men wrote:
GMATPrepNow wrote:
Mo2men wrote:
Hi Brent,

Thanks for your care to answer my concern. I felt the same like you. However, the creator in his question put as follows :

Let number of salesmen = S, and guests =G

0.8 S * 5 = 0.4 G ...I do not understand the logic behind this step. Do you have any explanation that stems from the question above??

Again thanks


If S = number of salesmen, then 0.8S = number of salesmen who participated in sessions.
Each of those 0.8S salesmen had 5 sessions.
So, (5)(0.8S) = TOTAL number of sessions.

Likewise, 0.4G = number of guests who participated in sessions.
We aren't told how many sessions each of these 0.4G guests attended.
So, let k = number of sessions EACH guest attended
So, (k)(0.4G) = TOTAL number of sessions.

NOW, we can write: (5)(0.8S) = (k)(0.4G)


Thanks again Brent But is not total number of sessions = (k)(0.4G) + (5)(0.8S)...So it is still unclear to me established equation..

Can you please bear with with me and elaborate more?

Thanks in advance

The problem is that we don't have enough information (in my opinion)

I'm going to assume that each Guest attends exactly ONE session.
In other words, k = 1
Let's see what happens....

We get:
If S = number of salesmen, then 0.8S = number of salesmen who participated in sessions.
Each of those 0.8S salesmen had 5 sessions.
So, (5)(0.8S) = TOTAL number of sessions.

Likewise, 0.4G = number of guests who participated in sessions.
We aren't told how many sessions each of these 0.4G guests attended.
IF we assume that each guest attends exactly one session, then (1)(0.4G) = TOTAL number of sessions.

NOW, we can write: (5)(0.8S) = (1)(0.4G)
Simplify: 4S = 0.4G
Divide both sides by 0.4 to get: 10S = G

At this point, we have all of the info we need.
If there are G guests, and 40% of them participated in one-on-one information sessions
Then the number of GUEST session attendees = 0.4G
Since, 10S = G, we can also write: the number of GUEST session attendees = 0.4(10S) = 4S

From earlier, we also know that the number of SALESMEN session attendees = 0.8S

So, the TOTAL number of SESSION attendees 4S + 0.8S = 4.8S

Now the TOTAL number of PARTY attendees = G + S
= 10S + S
= 11S

So, the percentage of the attendees involved in the one-on-one information sessions = 4.8S/11S ≈ 43.6%

Okay, that's pretty much all the time I want to devote to this question.

Cheers,
Brent
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Re: In an event, only salesmen and guests participated.   [#permalink] 16 Oct 2019, 08:19
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