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The data set above contains two unknown values, x and y, where x ≤ y.

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Bunuel
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The data set above contains two unknown values, x and y, where x ≤ y. [#permalink] New post   26 Oct 2021, 04:15
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87% (02:17) correct 13% (02:05) wrong based on 75 sessions
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4, 2, 15, 8, x, y

The data set above contains two unknown values, x and y, where x ≤ y. If the mean of the data set is 8 and the median is 7, what is the value of y?

(A) 12
(B) 13
(C) 15
(D) 18
(E) 19
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sanjitscorps18
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Re: The data set above contains two unknown values, x and y, where x ≤ y. [#permalink] New post   26 Oct 2021, 04:53
Median 7 and Mean 8 would imply x + y = 48 - 29 = 19

The placement of x and y becomes

2, 4, x, 8, y, 15

Now x + 8 = 7 x 2 => x = 6

x + y = 19 => y = 13.

Option B
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hardik0920
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Re: The data set above contains two unknown values, x and y, where x y. [#permalink] New post   25 Mar 2023, 00:09
sanjitscorps18 wrote:
Median 7 and Mean 8 would imply x + y = 48 - 29 = 19

The placement of x and y becomes

2, 4, x, 8, y, 15

Now x + 8 = 7 x 2 => x = 6

x + y = 19 => y = 13.

Option B



I did not understand how have you arranged x and y.
git until x + y = 19.
remaining arranging the sequence i have not understood.
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rudi0setyawan
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The data set above contains two unknown values, x and y, where x y. [#permalink] New post   06 Apr 2023, 14:59
4 + 2 + 15 + 8 + x + y = 48

29 + x + y = 48

x + y = 19

As median = 7 and there are six numbers, it means if they are ordered from the smallest, (#3 + #4) = 7*2 = 14

#3 and #4 must be two numbers closest to 7, where #3 < 7 and #4 > 7

From the numbers available, we can configure that #4 = 8

So #3 = 14 - 8 = 6

Since x+y = 19 and x<y, so x = 6

y = 13
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Re: The data set above contains two unknown values, x and y, where x y. [#permalink] New post   06 Apr 2023, 15:10
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Bunuel wrote:
4, 2, 15, 8, x, y

The data set above contains two unknown values, x and y, where x ≤ y. If the mean of the data set is 8 and the median is 7, what is the value of y?

(A) 12
(B) 13
(C) 15
(D) 18
(E) 19


The only ways for the median to be 7 would be either (i) both x and y are 7 or (ii) one of x and y is 6 and the other is 8 or greater. If they were both 7, the mean would not be 8. So, we know that one of them is 6 and the other is 8 or greater. Since x≤y, x must be 6 and y must be at least 8.

4+2+15+8+6+y = 8*6

y = 13

Answer choice B.
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Re: The data set above contains two unknown values, x and y, where x y. [#permalink]
06 Apr 2023, 15:10
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