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Bunuel
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4 + 2 + 15 + 8 + x + y = 48

29 + x + y = 48

x + y = 19

As median = 7 and there are six numbers, it means if they are ordered from the smallest, (#3 + #4) = 7*2 = 14

#3 and #4 must be two numbers closest to 7, where #3 < 7 and #4 > 7

From the numbers available, we can configure that #4 = 8

So #3 = 14 - 8 = 6

Since x+y = 19 and x<y, so x = 6

y = 13
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Bunuel
4, 2, 15, 8, x, y

The data set above contains two unknown values, x and y, where x ≤ y. If the mean of the data set is 8 and the median is 7, what is the value of y?

(A) 12
(B) 13
(C) 15
(D) 18
(E) 19

The only ways for the median to be 7 would be either (i) both x and y are 7 or (ii) one of x and y is 6 and the other is 8 or greater. If they were both 7, the mean would not be 8. So, we know that one of them is 6 and the other is 8 or greater. Since x≤y, x must be 6 and y must be at least 8.

4+2+15+8+6+y = 8*6

y = 13

Answer choice B.
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