Last visit was: 10 Jun 2024, 23:26 It is currently 10 Jun 2024, 23:26
Close
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track
Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Close
Request Expert Reply
Confirm Cancel
SORT BY:
Date
Tags:
Show Tags
Hide Tags
Intern
Intern
Joined: 28 Jul 2022
Posts: 36
Own Kudos [?]: 44 [5]
Given Kudos: 103
Send PM
Senior Manager
Senior Manager
Joined: 29 Jun 2020
Posts: 377
Own Kudos [?]: 488 [2]
Given Kudos: 220
Location: India
Send PM
GMAT Club Legend
GMAT Club Legend
Joined: 03 Jun 2019
Posts: 5228
Own Kudos [?]: 4059 [0]
Given Kudos: 160
Location: India
GMAT 1: 690 Q50 V34
WE:Engineering (Transportation)
Send PM
Intern
Intern
Joined: 28 Jul 2022
Posts: 36
Own Kudos [?]: 44 [0]
Given Kudos: 103
Send PM
Re: ­A certain café sells bagels for $1.10 and muffins for $1.50 [#permalink]
Kinshook wrote:
devashish2407
Given: A certain café sells bagels for $1.10 and muffins for $1.50. Last Wednesday, muffins accounted for M percent of all revenue from baked goods, and b percent of the baked goods sold were bagels.
Asked: If the café sold only muffins and bagels last Wednesday, which of the following expresses the value of M in terms of b ?
Let the number of bagels sold be x & number of muffins sold be y.

Revenue from baked goods = 1.1x + 1.5y
Revenue from muffins = 1.5y

M% = 1.5y/(1.1x + 1.5y) * 100%
(1.1x + 1.5y)*M = 150y
1.1Mx + 1.5My = 150y
1.1Mx = (150-1.5M)y
\(\frac{x}{y} = \frac{(150-1.5M)}{1.1M} = \frac{15}{11} * \frac{(100-M)}{M}\)

Baked goods sold = x+ y
b% = x/(x+y) *100%
(x + y)b = 100x
(100 - b)x = by 
\(\frac{x}{y} =\frac{ b}{(100-b)} = \frac{(150-1.5M)}{1.1M} = \frac{1.5}{1.1} *\frac{(100-M)}{M}= \frac{15}{11} * \frac{(100-M)}{M} \)
\(\frac{(100-M)}{M} = \frac{11b}{15(100-b)}\)
\(\frac{M}{100} = \frac{15(100-b)}{(1500-4b)}\)
\(M = \frac{1500(100-b)}{(1500-4b)} = \frac{375(100-b)}{(375-b)}\)

IMO E­

­Hello, Thank you for the explanation. 

I understood, but is there any other way to solve for this problem which is not time consuming?­
GMAT Club Bot
Re: ­A certain café sells bagels for $1.10 and muffins for $1.50 [#permalink]
Moderator:
Math Expert
93658 posts