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555-605 (Medium)|   Geometry|      
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Bunuel
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Points A, P, Q and B lie on the same line such that P, Q and B are, re 03 Apr 2020, 08:55
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Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!

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80% (02:41) correct 20% (02:33) wrong based on 60 sessions

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Points A, P, Q and B lie on the same line such that P, Q and B are, respectively, 100 km, 200 km and 300 km away from A. Cars 1 and 2 leave A at the same time and move towards B. Simultaneously, car 3 leaves B and moves towards A. Car 3 meets Car 1 at Q, and Car 2 at P. If each car is moving in uniform speed then the ratio of the speed of Car 2 to that of Car 1 is

A. 1 : 4
B. 2 : 9
C. 1 : 2
D. 2 : 7
E. 2 : 9


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A
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Points A, P, Q and B lie on the same line such that P, Q and B are, re 03 Apr 2020, 09:02
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Speed is direct proportional to distance.
Car 3 cover 100m when Car 1 covered 200.-----(1)
Also, Car 3 covered 200m when Car 2 does 100m. ------(2)
So, the ratio will be Car1:Car2:Car3
400:100:200 (equating statements)
So the ratio of speed of Car 2 : Car 1 is 1:4
So OA is A

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Points A, P, Q and B lie on the same line such that P, Q and B are, re 03 Apr 2020, 14:57
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Car 3 meets car 1 at Q, which is 200 km from A.

Therefore, at the time of their meeting car 1 must have travelled 200 km and car 3 must have travelled 100 km.

As the time is same, ratio of speed of car 1 to speed of car 3 = 2 : 1.

Car 3 meets car 2 at P, which is 100 km from A.

Therefore, at the time of their meeting car 2 must have travelled 100 km and car 3 must have travelled 200 km.

As the time is same, ratio of speed of car 2 to speed of car 3 = 1 : 2.

Speed of car 1 : speed of car 3 = 2 : 1

And speed of car 2 : speed of car 3 = 1 : 2

So, speed of car 1 : speed of car 2 : speed of car 3 = 4 : 1 : 2

speed of car 2 : speed of car 1 = 1 : 4

correct answer is A
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Points A, P, Q and B lie on the same line such that P, Q and B are, re 03 Apr 2020, 15:01
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method II : let , speed of car 1,2,3 be v1,v2,v3 respectively.
from s=vt formula,
200/v1 = 100/v3 ___________ (1)
100/v2 = 200/v3 ___________(2)
from (1) and (2)
v2/v1 = 1: 4 [ANSWER A ]
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Points A, P, Q and B lie on the same line such that P, Q and B are, re 04 Apr 2020, 01:27
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Bunuel
Points A, P, Q and B lie on the same line such that P, Q and B are, respectively, 100 km, 200 km and 300 km away from A. Cars 1 and 2 leave A at the same time and move towards B. Simultaneously, car 3 leaves B and moves towards A. Car 3 meets Car 1 at Q, and Car 2 at P. If each car is moving in uniform speed then the ratio of the speed of Car 2 to that of Car 1 is

A. 1 : 4
B. 2 : 9
C. 1 : 2
D. 2 : 7
E. 2 : 9


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Solution



    • Let the speed of car 1, car 2 and car 3 be \(s_1, s_2\) and \(s_3 \)respectively.
    • We know that \(distance = speed * time\),
      o And if time is constant, speed is directly proportional to distance.
    • Now, Car 1 and Car 3 meets at Q.
      o Since, both started simultaneously, time is constant.
      o Thus, Ratio of speed of car 1 and car 2 = Ratio of distance travelled by car 1 and car 2,
         \(s_1 : s_3 = 200:100 = 2:1 …………Eq.(i)\)
    • Also, Car 2 and Car 3 meets at P,
      o Again, both started at same time, so time is constant.
      o Thus, Ratio of speed of car 3 and car 2 = Ratio of distance travelled by car 3 and car 2,
         \(s_3 : s_2 = 200:100 = 2:1 …………Eq.(ii)\)
    • Now, to equate the ratios, we can rewrite Eq.(i) as
      o \(s_1 : s_3 = 2:1 = 4:2\)
    • Now, from the above equation and eq.(ii), we get,
      o \(s_1 : s_3: s_2 = 4 : 2 :1\)
         \(s_2 : s_1 = 1:4\)
Thus, the correct answer is Option A.
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Points A, P, Q and B lie on the same line such that P, Q and B are, re 04 Apr 2020, 09:00
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Bunuel
Points A, P, Q and B lie on the same line such that P, Q and B are, respectively, 100 km, 200 km and 300 km away from A. Cars 1 and 2 leave A at the same time and move towards B. Simultaneously, car 3 leaves B and moves towards A. Car 3 meets Car 1 at Q, and Car 2 at P. If each car is moving in uniform speed then the ratio of the speed of Car 2 to that of Car 1 is

A. 1 : 4
B. 2 : 9
C. 1 : 2
D. 2 : 7
E. 2 : 9


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Given: Points A, P, Q and B lie on the same line such that P, Q and B are, respectively, 100 km, 200 km and 300 km away from A. Cars 1 and 2 leave A at the same time and move towards B. Simultaneously, car 3 leaves B and moves towards A. Car 3 meets Car 1 at Q, and Car 2 at P.

Asked: If each car is moving in uniform speed then the ratio of the speed of Car 2 to that of Car 1 is


A------100 km----------P---------100 km--------Q----------100 km----------B
Car1->----------------------------------------Car1+3
Car2->----------------Car2+3
-----------------------------------------------------------------------------<-Car 3

Since all cars start at the same time, once they meet their speeds are directly proportional to the distance covered.

Let the speed of car1 , car2 & car3 be v1, v2 & v3 respectively

v1/v3 = 200/100 = 2/1 = 2
v2/v3 = 100/200 = 1/2

v2/v1 = (v2/v3)/(v1/v3) = (1/2)/2 = 1/4

IMO A
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Points A, P, Q and B lie on the same line such that P, Q and B are, re 04 Apr 2020, 13:29
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Car1 goes 200, Car 3 goes 100
Car 3 goes 200, Car 2 goes 100

C1:C3 = 2:1
C3:C2 = 2:1

C1:C3:C2 = 2:1 2:1 = 4:2 2:1 = 4:2:1
C1:C2 = 4:1
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Points A, P, Q and B lie on the same line such that P, Q and B are, re 19 Feb 2024, 03:08
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