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Re: Quant Question of the Day Chat [#permalink]
gmatophobia, Can you teach concepts of circles,tangents,parabola teted in gmat
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Re: Quant Question of the Day Chat [#permalink]
A

Because SD always positive or zero. Never negative.
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Re: Quant Question of the Day Chat [#permalink]
as sd cant be negative
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Re: Quant Question of the Day Chat [#permalink]
But SD is zero only when all values are identical right?
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Re: Quant Question of the Day Chat [#permalink]
How to scroll up in this chat. Whenever I try to go up, it reloads the chat
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Re: Quant Question of the Day Chat [#permalink]
Shobhit28 wrote:
Yes. How?

2^3+2^0=3^2+0^2=9
Therefore 3-0=3
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Re: Quant Question of the Day Chat [#permalink]
gmatophobia wrote:
PS Question 1 - May 29 A farmer decides to plant a row of trees along one side of a road. He decides to plant one tree every 15 meters. If the road is 460 meters long what is the maximum number of trees the farmer could plant? A. 28 B. 29 C. 30 D. 31 E. 32 Source: GMATNinja | Difficulty: Medium



gmatophobia wrote:
DS Question 1 - May 29 If vertices of a triangle have coordinates (-1,0), (4,0), and (0,A), is the area of the triangle greater than 15 ? (1) A < 3 (2) The triangle is right Source: GMAT Club Test | Difficulty: Hard



DS Question 1 - May 31

Is p > q ?

(1) p^2 > q

(2) p^3 < q

Source: Expert’s Global | Difficulty: Hard

PS Question 1 - May 31

Let x be a two-digit number. If the sum of the digits of x is 9, then the sum of the digits of the number (x + 10) is

(A) 1

(B) 8

(C) 10

(D) either 8 or 10

(E) either 1 or 10

Source: Others | Difficulty: Hard

Originally posted by gmatophobia on 31 May 2023, 04:01.
Last edited by gmatophobia on 31 May 2023, 04:04, edited 2 times in total.
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Re: Quant Question of the Day Chat [#permalink]
gmatophobia wrote:
PS Question 1 - May 31 Let x be a two-digit number. If the sum of the digits of x is 9, then the sum of the digits of the number (x + 10) is (A) 1 (B) 8 (C) 10 (D) either 8 or 10 (E) either 1 or 10 Source: Others | Difficulty: Hard

Option D
1. When x is negative: sum will be 8
2. When x is positive: sum will be 10
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Re: Quant Question of the Day Chat [#permalink]
sg_mba wrote:
Option D 1. When x is negative: sum will be 8 2. When x is positive: sum will be 10

But intial statement states that sum of digits is 9.. how can negative number have sum of digits as 9?
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Re: Quant Question of the Day Chat [#permalink]
gmatophobia wrote:
PS Question 1 - May 31 Let x be a two-digit number. If the sum of the digits of x is 9, then the sum of the digits of the number (x + 10) is (A) 1 (B) 8 (C) 10 (D) either 8 or 10 (E) either 1 or 10 Source: Others | Difficulty: Hard

Consider the case of x=18
In this case, x+10=28, which means sum of digits 10.
Consider the case of x=90
x+10=100
the sum of digits is 1.
E
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Re: Quant Question of the Day Chat [#permalink]
Shobhit28 wrote:
Yes

Then what would be the answer?
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Re: Quant Question of the Day Chat [#permalink]
gmatophobia wrote:
PS Question 1 - May 31 Let x be a two-digit number. If the sum of the digits of x is 9, then the sum of the digits of the number (x + 10) is (A) 1 (B) 8 (C) 10 (D) either 8 or 10 (E) either 1 or 10 Source: Others | Difficulty: Hard

E

gmatophobia wrote:
DS Question 1 - May 31 Is p > q ? (1) p^2 > q (2) p^3 < q Source: Expert’s Global | Difficulty: Hard

E; -ve or fraction

Originally posted by wickedvikram on 01 Jun 2023, 00:50.
Last edited by wickedvikram on 01 Jun 2023, 00:53, edited 1 time in total.
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Re: Quant Question of the Day Chat [#permalink]
mysterymanrog wrote:
Consider the case of x=18 In this case, x+10=28, which means sum of digits 10. Consider the case of x=90 x+10=100 the sum of digits is 1. E

let the number be 10x+y , add 10 to it, it becomes 10x+(y+10), assume that after this operation , the two digit no is of form 10a+b, now compare 10x+10+y with 10a+b , we get , a=x+1 and y=b , so the sum of its digit i.e a+b =x+y+10 =9+1=10
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Re: Quant Question of the Day Chat [#permalink]
gmatophobia wrote:
DS Question 1 - May 31 Is p > q ? (1) p^2 > q (2) p^3 < q Source: Expert’s Global | Difficulty: Hard



gmatophobia wrote:
PS Question 1 - May 31 Let x be a two-digit number. If the sum of the digits of x is 9, then the sum of the digits of the number (x + 10) is (A) 1 (B) 8 (C) 10 (D) either 8 or 10 (E) either 1 or 10 Source: Others | Difficulty: Hard



DS Question 1 - June 6

For each landscaping job that takes more than 4 hours, a certain contractor charges a total of r dollars for the first 4 hours plus 0.2*r dollars for each additional hour or fraction of an hour, where r > 100, Did a particular landscaping job take more than 10 hours.

(1) The contractor charges a total of $288 for the job.
(2) The contractor charges a total of 2.4r dollars for the job.

Source: Official Guide | Difficulty: Hard

PS Question 1 - June 6

9 people, including 3 couples, are to be seated in a row of 9 chairs. What is the probability that only one couple is sitting together

A. 1/63
B. 1/6
C. 8/21
D. 61/126
E. 7/9

Source: Others | Difficulty: Hard

Originally posted by gmatophobia on 02 Jun 2023, 04:23.
Last edited by gmatophobia on 02 Jun 2023, 04:26, edited 2 times in total.
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Re: Quant Question of the Day Chat [#permalink]
gmatophobia wrote:
DS Question 1 - June 6 For each landscaping job that takes more than 4 hours, a certain contractor charges a total of r dollars for the first 4 hours plus 0.2*r dollars for each additional hour or fraction of an hour, where r > 100, Did a particular landscaping job take more than 10 hours. (1) The contractor charges a total of $288 for the job. (2) The contractor charges a total of 2.4r dollars for the job. Source: Official Guide | Difficulty: Hard

B

A is not sufficient because value of r is unknown

Originally posted by sg_mba on 02 Jun 2023, 04:54.
Last edited by sg_mba on 02 Jun 2023, 04:55, edited 1 time in total.
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Re: Quant Question of the Day Chat [#permalink]
gmatophobia wrote:
PS Question 1 - June 6 9 people, including 3 couples, are to be seated in a row of 9 chairs. What is the probability that only one couple is sitting together A. 1/63 B. 1/6 C. 8/21 D. 61/126 E. 7/9 Source: Others | Difficulty: Hard

Hi gmatphobia
I checked twice but I’m getting 11/63. Could you point out the error in below.
P(Only 1C) = P(T)-[p(0C)+P(2+ C)]
{9!-[(9!-8!*2!) + 6!*4!]} / 9! = 11/63
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Re: Quant Question of the Day Chat [#permalink]
Got it. It’s C - 8/21

P(only 1C) = 3{P(1+ C)-[2*P(only 2C)+P(only 3C)]}
P(only 3C) = 6!*2!*2!*2!/9!
P(only 2C) = P(2+ C)-P(only 3C)= (7!*2!*2!-6!*2!*2!*2!)/9! (for only 1 pair of 2couple, *3 for all )
P(1+ C)=2*8!/9! (for only 1 couple, *3 for all )
Substitute in first eqn to get 8/21

Originally posted by wickedvikram on 02 Jun 2023, 09:42.
Last edited by wickedvikram on 02 Jun 2023, 09:52, edited 1 time in total.
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