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Re: Quant Question of the Day Chat [#permalink]
My solving of this one. I am not sure gmat typically tests binomial expansion though.
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Re: Quant Question of the Day Chat [#permalink]
it has a basic trick like (a-b)^3 + (a+b)^3 = a3 + a3 = 2 a3. similarly (13-1)^91 & (13+1)^91 has odd powers, so only 13^x numbers will remain. where x < 2, so 13^x /13^2 will leave 0 as x >2.
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Re: Quant Question of the Day Chat [#permalink]
Quick DS question:
Is z even?
1) 3z = even
2) 5z = even
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Re: Quant Question of the Day Chat [#permalink]
T4Star wrote:
Quick DS question: Is z even? 1) 3z = even 2) 5z = even

Odd*even= even
3*z=even; 5*z=even

3and 5 are odd
For the product to be even Z must be even
Answer D

It isn’t the appropriate group
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Re: Quant Question of the Day Chat [#permalink]
Added a question on the DS forum :)

Edoua wrote:
Odd*even= even 3*z=even; 5*z=even 3and 5 are odd For the product to be even Z must be even Answer D It isn’t the appropriate group

Z can be a fraction too...
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Re: Quant Question of the Day Chat [#permalink]
T4Star wrote:
Z can be a fraction too...

True
Sorry I missed

T4Star wrote:
Z can be a fraction too...

But for the product to be even, Z must be even
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Re: Quant Question of the Day Chat [#permalink]
Edoua wrote:
But for the product to be even, Z must be even

True. Only way to reach the conclusion is by keeping Z as an even integer.
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Re: Quant Question of the Day Chat [#permalink]
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T4Star wrote:
Quick DS question:
Is z even?
1) 3z = even
2) 5z = even

­The answer is C, not D because we are don't know whether z is an integer when evaluating the options individually. This question is discussed here: 

https://gmatclub.com/forum/is-z-even-1- ... 13535.html

Hope this helps.
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Re: Quant Question of the Day Chat [#permalink]
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Data Sufficiency Butler: April 2024
April 17DS 1DS 2
­
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Re: Quant Question of the Day Chat [#permalink]
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Problem Solving Butler: April 2023
April 17PS 1PS 2
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Re: Quant Question of the Day Chat [#permalink]
Hi, I wanted to ask, is doing the OG, Quant Review and giving all of the Gmat Club Quant practice tests enough practice for the quant section??
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Re: Quant Question of the Day Chat [#permalink]
Can someone help pls with this ques
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Re: Quant Question of the Day Chat [#permalink]
I guess you forgot to subtract both AB and RH- .

4 + 17 - 1
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Re: Quant Question of the Day Chat [#permalink]
4+ 17-1 (because that one person who is AB and has RH -ve is double counted)!
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Re: Quant Question of the Day Chat [#permalink]
don’t even know where to start solving this ques
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Re: Quant Question of the Day Chat [#permalink]
Range of a function mean what all values can f(x) be. As it is X squared, and we are given "for all real numbers", lets say X is 0. Then f(0) = 1. Now on either side of zero no matter the value of x, squaring makes it positive. So 1/value greater than 1. That means, f(x) can be less than or equal to 1.
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Re: Quant Question of the Day Chat [#permalink]
The first step to solving is to understand what is given and what is asked.

We are given a certain function (1/(x2+1)). We are being asked - what all values can (1/(x2+1)) take?

Whatever the value of x, x2 has to be >=0.

- If x =0, then x2 is 0
- If x is negative or positive, then x2 is positive.

So, (1/(x2+1)) is either 1 (when x =0, (1/(x2+1)) = 1/1 = 1) or a positive fraction (greater than o, lesser than 1). Example - x = -3, (1/(x2+1)) = 1 /10 = 0.1

In essence, whatever the value of x, (1/(x2+1)) has a "range" 0<x <=1 (positive, real numbers <=1). So, choice E.
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Re: Quant Question of the Day Chat [#permalink]
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