Question: Average Speed = ?CONCEPT: Average Speed = Total Distance / Total Time however the question here is asking simply the average (Arithmetic Mean) of the speeds of shots fired at two different targets.
Statement 1: One target was 400 feet further away than the other target.
This information is useless as we don't have any information about the time it took the bullet to reach the targets and also we don't know the distance of targets from the gun
NOT SUFFICIENTStatement 2: The bullet reached the further target in 5 seconds.
This information is useless as we don't have any information about the distance of targets from gun
NOT SUFFICIENTCombining the two statementsLet the distance of the first target = d
so the distance of the Second target = d+400
Let, Speed = s
Distance, d = s*t
Also, (d+400) = s*5
i.e. st+400 = 5s
i.e. s(5-t) = 400
After combining we have two variables and there is one equation so can't be solved for unique solution hence
NOT SUFFICIENTAnswer: Option E
---Similar question LINKBunuel wrote:
An air-powered rifle was shot at 2 different targets. What was the average (arithmetic mean) speed of the bullet?
(1) One target was 400 feet further away than the other target.
(2) The bullet reached the further target in 5 seconds.