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10 Dec 2012, 10:44
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C
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Difficulty:
5%
(low)
Question Stats:
93% (01:05) correct
7%
(01:28)
wrong
based on 5555
sessions
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Sixty percent of the members of a study group are women, and 45 percent of those women are lawyers. If one member of the study group is to be selected at random, what is the probability that the member selected is a woman lawyer?
(A) 0.10
(B) 0.15
(C) 0.27
(D) 0.33
(E) 0.45
(A) 0.10
(B) 0.15
(C) 0.27
(D) 0.33
(E) 0.45
10 Dec 2012, 10:47
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Walkabout
Say there are 100 people in that group, then there would be 0.6*0.45*100=27 women lawyers, which means that the probability that the member selected is a woman lawyer is favorable/total=27/100.
Answer: C.
General Discussion
10 Jun 2016, 11:33
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Walkabout
This is a two-part probability question. We should first notice that since our answer choices are in decimal form, we can use a real numerical value for the total number of members of the study group. A convenient number to use is 100.
We are first told that 60 percent of the members in the group are women. Thus we can say:
0.6 x 100 = 60 women
We are next told that 45 percent of these 60 women are lawyers. We can then say:
0.45 x 60 = 27 women lawyers
Finally, we need to determine the probability of selecting a woman lawyer from the group. Since there are 100 total members and 27 of them are women lawyers, the probability is 27/100 = 0.27.
Answer C.
