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# The above cube has sides of length . What is the area of the triangle

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The above cube has sides of length . What is the area of the triangle  [#permalink]

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12 Sep 2018, 00:27
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25% (medium)

Question Stats:

71% (01:11) correct 29% (02:33) wrong based on 30 sessions

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The above cube has sides of length $$8\sqrt{2}$$. What is the area of the triangle PQR?

A. $$32\sqrt{3}$$

B. $$64\sqrt{2}$$

C. $$64\sqrt{3}$$

D. $$128\sqrt{2}$$

E. $$128\sqrt{3}$$

Attachment:

image001.gif [ 705 Bytes | Viewed 597 times ]

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Re: The above cube has sides of length . What is the area of the triangle  [#permalink]

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12 Sep 2018, 03:26
Bunuel wrote:

The above cube has sides of length $$8\sqrt{2}$$. What is the area of the triangle PQR?

A. $$32\sqrt{3}$$

B. $$64\sqrt{2}$$

C. $$64\sqrt{3}$$

D. $$128\sqrt{2}$$

E. $$128\sqrt{3}$$

Attachment:
image001.gif

PQ=QR=RP=diagonal of the faces(square shaped by birth) of the cube=√2*(8√2)=16

Now, triangle PQR is an equilateral triangle with sides PQ,QR,and RP.

Area of triangle PQR=√3/4*$$PQ^2$$=√3/4*16*16=64√3

Ans. (C)
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Re: The above cube has sides of length . What is the area of the triangle  [#permalink]

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12 Sep 2018, 05:30
Bunuel wrote:

The above cube has sides of length $$8\sqrt{2}$$. What is the area of the triangle PQR?

A. $$32\sqrt{3}$$

B. $$64\sqrt{2}$$

C. $$64\sqrt{3}$$

D. $$128\sqrt{2}$$

E. $$128\sqrt{3}$$

Attachment:
image001.gif

Point to Note: The triangle PQR is made of the diagonals of faces of cube i.e. the triangle PQR is an equilateral triangle with dimension a√2 where a is the side of cube

$$a = 8√2$$
i.e. Side of equilateral triangle $$= a√2 = 8√2*√2 = 16$$

Area of equilateral triangle pQR $$= (√3/4)Side^2 = (√3/4)16^2 = 64√3$$

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The above cube has sides of length . What is the area of the triangle  [#permalink]

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12 Sep 2018, 05:58
The above cube has sides of length $$8\sqrt{2}$$. What is the area of the triangle PQR?

A. $$32\sqrt{3}$$

B. $$64\sqrt{2}$$

C. $$64\sqrt{3}$$

D. $$128\sqrt{2}$$

E. $$128\sqrt{3}$$

Attachment:
image001.gif

All the sides of the triangle are the diagonal of faces of the cube. Hence, Sides of the triangle are equal and are equal to diagonal of the face of the cube.

Therefore, For the equilateral triangle PQR, The area ==√3/4*side2

the side of the triangle= diagonal of the cube = a√2, Plugging value, we get, diagonal= side of the triangle PQR=8√2∗√2=16

Area of triangle PQR =(√3/4)Side2

(√3/4)16^2=64√3

Hence C is the correct answer
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Re: The above cube has sides of length . What is the area of the triangle  [#permalink]

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14 Sep 2018, 09:05
Bunuel wrote:

The above cube has sides of length $$8\sqrt{2}$$. What is the area of the triangle PQR?

A. $$32\sqrt{3}$$

B. $$64\sqrt{2}$$

C. $$64\sqrt{3}$$

D. $$128\sqrt{2}$$

E. $$128\sqrt{3}$$

Attachment:
image001.gif

Since the side length of each square face of the cube is 8√2, then the length
of each diagonal is 8√2 x √2 = 16.

The 3 diagonals create equilateral triangle PQR, with base 16 and height
8√3. Thus, the area is:

(1/2) x 16 x 8√3 = 64√3

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Re: The above cube has sides of length . What is the area of the triangle   [#permalink] 14 Sep 2018, 09:05
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