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# The above equation may be rewritten as which of the following?

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The above equation may be rewritten as which of the following? [#permalink]
Bunuel wrote:
$$\frac{x^{(-5)}*(x^4)^2*x^3}{x*x^{(-7)}*(x^{(-5)})^4}$$

The above equation may be rewritten as which of the following?

A. 1/x^25

B. 1/x^8

C. x^6

D. x^20

E. x^32

$$\frac{x^{(-5)}*(x^4)^2*x^3}{x*x^{(-7)}*(x^{(-5)})^4}$$
$$\frac{1}{x^5}*x^8* x^3 *\frac{1}{x} * x^7 * x^2^0$$
$$x^3 * x^3 * x^6 * x^2^0$$
$$x^3^2$$

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Re: The above equation may be rewritten as which of the following? [#permalink]
Bunuel wrote:
$$\frac{x^{(-5)}*(x^4)^2*x^3}{x*x^{(-7)}*(x^{(-5)})^4}$$

The above equation may be rewritten as which of the following?

A. 1/x^25

B. 1/x^8

C. x^6

D. x^20

E. x^32

Let’s rewrite some of the expressions in the numerator and the denominator:

(x^4)^2 = x^8

(x^-5)^4 = x^-20

So, the numerator becomes:

(x^-5)*(x^8)*(x^3) = x^(-5 + 8 + 3) = x^6

Similarly, the denominator becomes:

x*(x^-7)*(x^-20) = x^(1 - 7 - 20) = x^-26

Then:

x^6/x^-26 = x^(6 - (-26)) = x^(6 + 26) = x^32

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Re: The above equation may be rewritten as which of the following? [#permalink]
$$\frac{x^{(−5)}∗(x^4)^2∗x^3}{x∗x^{(−7)}∗(x^{(−5)})^4}$$
The above equation may be rewritten as which of the following?

$$\frac{x^{(−5)}∗(x^4)^2∗x^3}{x∗x^{(−7)}∗(x^{(−5)})^4}$$ = $$\frac{x^{-5} * x^8 * x^3}{x * x*^{-7} * x^{-20}}$$= $$\frac{x^{11} * x^{20} * x^7}{x * x^5}$$= $$\frac{x^{38}}{x^6}$$= $$x^{32}$$