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The measures of the interior angles in a polygon are consecutive odd i
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01 Jul 2019, 12:52
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The measures of the interior angles in a polygon are consecutive odd integers. The largest angle measures 153 degrees. How many sides does this polygon have? A) 8 B) 9 C) 10 D) 11 E) 12
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The measures of the interior angles in a polygon are consecutive odd i
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01 Jul 2019, 12:55
dabaobao wrote: The measures of the interior angles in a polygon are consecutive odd integers. The largest angle measures 153 degrees. How many sides does this polygon have?
A) 8 B) 9 C) 10 D) 11 E) 12 Solution: Using Sequence Sum of Interior angles = (n2) * 180 Max Angle = 153; Min Angle = 153  2(n1) Since we have an evenly spaced set, sum of interior angles = ((a1 + an)/2)*n ((153  2(n1) + 153)/2)*n = (n2) * 180 (153 n + 1)*n = 180n  360 => 153n n^2 +n = 180n  360 => n^2 + 26n  360 = 0 => (n + 36) (n  10) = 0 => n = 10 ANSWER: C Veritas Prep Official Solution Angles of the polygon: 153, 151, 149, 147, 145, 143, 141, … , (153 – 2(n1)) The average of these angles must be equal to the measure of each interior angle of a regular polygon with n sides since the sum of all angles is the same in both the cases. Measure of each interior angle of n sided regular polygon = Sum of all angles / n = (n−2)∗180n Using the options: Measure of each interior angle of 8 sided regular polygon = 180*6/8 = 135 degrees Measure of each interior angle of 9 sided regular polygon = 180*7/9 = 140 degrees Measure of each interior angle of 10 sided regular polygon = 180*8/10 = 144 degrees Measure of each interior angle of 11 sided regular polygon = 180*9/11 = 147 degrees apprx and so on… Notice that the average of the given angles can be 144 if there are 10 angles. The average cannot be higher than 144 i.e. 147 since that will give us only 7 sides (153, 151, 149, 147, 145, 143, 141 – the average is 147 is this case). But the regular polygon with interior angle measure of 147 has 11 sides. Similarly, the average cannot be less than 144 i.e. 140 either because that will give us many more sides than the required 9. Hence, the polygon must have 10 sides. Answer (C). Similar questions to practice: themeasuresoftheinterioranglesinapolygonare127388.html themeasuresoftheinterioranglesinapolygon151005.html
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Re: The measures of the interior angles in a polygon are consecutive odd i
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03 Jul 2019, 19:39
The sum of the interior angles of a ‘n’ sided polygon = (n2) * 180 degrees. Since the interior angles are consecutive odd integers, they represent a set of equally spaced values. For a set of equally spaced values, Mean = \(\frac{First element + Last element}{2}\). The largest angle = 153 degrees. So, the smallest angle = 153 – 2(n1). Therefore, Mean angle = \(\frac{153 + 153 – 2n + 2}{2}\) = 153 – n + 1. But, Mean angle = \(\frac{Sum of angles}{No. of angles}\). Therefore, 153 – n + 1 = \(\frac{180 n – 360}{n}\). Beyond this stage, we can start plugging in the options, starting with option C. If n = 10, 153 – 10 + 1 = \(\frac{180 * 10 – 360}{10}\) i.e. 144 = 144. The equation is satisfied when we plug in n = 10. Therefore, the correct answer option is C. Hope this helps!
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Re: The measures of the interior angles in a polygon are consecutive odd i
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04 Jul 2019, 08:02
dabaobao wrote: The measures of the interior angles in a polygon are consecutive odd integers. The largest angle measures 153 degrees. How many sides does this polygon have?
A) 8 B) 9 C) 10 D) 11 E) 12 I sort of used brute force (nonalgebraic approach) to solve this. Since Sum of Interior angles = (n2) * 180, no matter how many sides the polygon has, the sum of interior angles will have unit digit of 0. Hence, I tried listing the possible options and paid attention to the sum of unit digit, stopping when the sum ends with a unit digit of 0 > ended up with 10. 153 151 149 147 . . . xx5



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The measures of the interior angles in a polygon are consecutive odd i
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04 Jul 2019, 08:34
dabaobao wrote: The measures of the interior angles in a polygon are consecutive odd integers. The largest angle measures 153 degrees. How many sides does this polygon have?
A) 8 B) 9 C) 10 D) 11 E) 12 The sum of the interior angles must be a MULTIPLE OF 180 and thus must be an integer with a UNITS DIGIT OF 0. We can PLUG IN THE ANSWERS, which represent the number of sides and thus the number of angles. For any evenly spaced set, SUM = COUNT * MEDIAN. B: 9 Implied angles: 153, 151, 149, 147, 145, 143, 141, 139, 137 Sum = count * median = 9 * 145 = 1305 The sum does not have a units digit of 0. Eliminate B. If we include the next smallest angle  135  the sum will have a units digit of 0: 1305 + 135 = 1440 Check whether 1440 is a multiple of 180: 1440/180 = 144/18 = 72/9 = 8 Success! If we include the next smallest angle  for a total of 10 angles and thus 10 sides  the sum of the angles is a multiple of 180.
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The measures of the interior angles in a polygon are consecutive odd i
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Updated on: 20 Oct 2019, 06:25
ArvindCrackVerbal wrote: The sum of the interior angles of a ‘n’ sided polygon = (n2) * 180 degrees.
Since the interior angles are consecutive odd integers, they represent a set of equally spaced values. For a set of equally spaced values,
Mean = \(\frac{First element + Last element}{2}\).
The largest angle = 153 degrees. So, the smallest angle = 153 – 2(n1). Therefore,
Mean angle = \(\frac{153 + 153 – 2n + 2}{2}\) = 153 – n + 1.
But, Mean angle = \(\frac{Sum of angles}{No. of angles}\).
Therefore, 153 – n + 1 = \(\frac{180 n – 360}{n}\).
Beyond this stage, we can start plugging in the options, starting with option C.
If n = 10, 153 – 10 + 1 = \(\frac{180 * 10 – 360}{10}\) i.e. 144 = 144. The equation is satisfied when we plug in n = 10. Therefore, the correct answer option is C.
Hope this helps! ArvindCrackVerbalBunueldaaghVeritasKarishmachetan2uGMATPrepNowScottTargetTestPrepI have a silly doubt here. I am always confused how do we form equations of such kind ie 153 – 2(n1) . I can see that 153 – 2(n1)=1552n and as n starts from 1 this equation is fine here. But in general is there any rule/logic to derive such kind of equations?
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Originally posted by axezcole on 20 Oct 2019, 06:09.
Last edited by axezcole on 20 Oct 2019, 06:25, edited 3 times in total.



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Re: The measures of the interior angles in a polygon are consecutive odd i
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20 Oct 2019, 06:14
Asking me about Quants!!. I am honored, thank you
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Re: The measures of the interior angles in a polygon are consecutive odd i
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20 Oct 2019, 07:24
axezcole wrote: ArvindCrackVerbal wrote: The sum of the interior angles of a ‘n’ sided polygon = (n2) * 180 degrees.
Since the interior angles are consecutive odd integers, they represent a set of equally spaced values. For a set of equally spaced values,
Mean = \(\frac{First element + Last element}{2}\).
The largest angle = 153 degrees. So, the smallest angle = 153 – 2(n1). Therefore,
Mean angle = \(\frac{153 + 153 – 2n + 2}{2}\) = 153 – n + 1.
But, Mean angle = \(\frac{Sum of angles}{No. of angles}\).
Therefore, 153 – n + 1 = \(\frac{180 n – 360}{n}\).
Beyond this stage, we can start plugging in the options, starting with option C.
If n = 10, 153 – 10 + 1 = \(\frac{180 * 10 – 360}{10}\) i.e. 144 = 144. The equation is satisfied when we plug in n = 10. Therefore, the correct answer option is C.
Hope this helps! ArvindCrackVerbalBunueldaaghVeritasKarishmachetan2uGMATPrepNowScottTargetTestPrepI have a silly doubt here. I am always confused how do we form equations of such kind ie 153 – 2(n1) . I can see that 153 – 2(n1)=1552n and as n starts from 1 this equation is fine here. But in general is there any rule/logic to derive such kind of equations? Hi, we have the largest angle as 153, and all other angles are consecutive odd number.. To continue having odd numbers we require to subtract 2 from successive angles.. 1532*0, 1532*1,1532*2..153*2*(n1).. If I were told that some series has consecutive odd integer, then I would take the numbers as 2n1, 2n3,.. So, the derivation of a term in n would depend on the numbers we are dealing with
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Re: The measures of the interior angles in a polygon are consecutive odd i
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20 Oct 2019, 07:26
Given that 153 is the largest angle , 153=a+(n1)2. Now the sum of interior angles in a polygon=(n2)180 , sum of n terms in ap =n/2(2a+(n1)2)..>n(a+n1) now (n2)180=n(154n) only c)10 fits
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Re: The measures of the interior angles in a polygon are consecutive odd i
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20 Oct 2019, 09:24
chetan2u wrote: axezcole wrote: ArvindCrackVerbal wrote: The sum of the interior angles of a ‘n’ sided polygon = (n2) * 180 degrees.
Since the interior angles are consecutive odd integers, they represent a set of equally spaced values. For a set of equally spaced values,
Mean = \(\frac{First element + Last element}{2}\).
The largest angle = 153 degrees. So, the smallest angle = 153 – 2(n1). Therefore,
Mean angle = \(\frac{153 + 153 – 2n + 2}{2}\) = 153 – n + 1.
But, Mean angle = \(\frac{Sum of angles}{No. of angles}\).
Therefore, 153 – n + 1 = \(\frac{180 n – 360}{n}\).
Beyond this stage, we can start plugging in the options, starting with option C.
If n = 10, 153 – 10 + 1 = \(\frac{180 * 10 – 360}{10}\) i.e. 144 = 144. The equation is satisfied when we plug in n = 10. Therefore, the correct answer option is C.
Hope this helps! ArvindCrackVerbalBunueldaaghVeritasKarishmachetan2uGMATPrepNowScottTargetTestPrepI have a silly doubt here. I am always confused how do we form equations of such kind ie 153 – 2(n1) . I can see that 153 – 2(n1)=1552n and as n starts from 1 this equation is fine here. But in general is there any rule/logic to derive such kind of equations? Hi, we have the largest angle as 153, and all other angles are consecutive odd number.. To continue having odd numbers we require to subtract 2 from successive angles.. 1532*0, 1532*1,1532*2..153*2*(n1).. If I were told that some series has consecutive odd integer, then I would take the numbers as 2n1, 2n3,.. So, the derivation of a term in n would depend on the numbers we are dealing with Thanks a lot Chetan
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Re: The measures of the interior angles in a polygon are consecutive odd i
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22 Oct 2019, 19:38
axezcole wrote: I have a silly doubt here.
I am always confused how do we form equations of such kind ie 153 – 2(n1) . I can see that 153 – 2(n1)=1552n and as n starts from 1 this equation is fine here.
But in general is there any rule/logic to derive such kind of equations?
You can derive most of such formulas simply by observing the first few terms for a pattern and extending the pattern for the general case. For instance, the formula of 153  2(n  1) gives you the smallest of n consecutive odd integers when the largest one is 153. Let's observe what happens for the first few values of n: If n = 2, the consecutive odd integers are 153 and 151. The difference is 153  151 = 2. If n = 3, the consecutive odd integers are 153, 151 and 149. The difference is 153  149 = 4. If n = 4, the consecutive odd integers are 153, 151, 149 and 147. The difference is 153  147 = 6. We can recognize a pattern here. The difference is always two less than twice the number of terms or, in other words, the largest odd integer is always 2n  2 = 2(n  1) greater than the smallest odd integer. Thus, we obtain the formula 153  2(n  1). As an additional example, let's consider the number of terms in an equally spaced set of integers. For instance, how can we solve a question like "how many three digit multiples of 7 are there?" without using any formula? The smallest three digit multiple of 7 is 105 and the largest three digit multiple of 7 is 994. Let's write these numbers: 105 112 119 ... 994 7*15 7*16 7*17 ... 7*142 Let's divide each term by 7. Notice that we are only interested in the number of terms and dividing each term by 7 will not change the number of terms: 15 16 17 ... 142 Let's subtract 14 from each term. Again, we are only interested in the number of terms and subtracting 14 from each term will not change the number of terms: 1 2 3 ... 128 It's not hard to see that there are exactly 128 terms above. Notice that we would get the same answer if we used the familiar formula of [(last term  first term)/(common difference)] + 1 = [(994  105)/7] + 1 = (889/7) + 1 = 127 + 1 = 128.
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Re: The measures of the interior angles in a polygon are consecutive odd i
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23 Oct 2019, 01:47
ScottTargetTestPrep wrote: axezcole wrote: I have a silly doubt here.
I am always confused how do we form equations of such kind ie 153 – 2(n1) . I can see that 153 – 2(n1)=1552n and as n starts from 1 this equation is fine here.
But in general is there any rule/logic to derive such kind of equations?
You can derive most of such formulas simply by observing the first few terms for a pattern and extending the pattern for the general case. For instance, the formula of 153  2(n  1) gives you the smallest of n consecutive odd integers when the largest one is 153. Let's observe what happens for the first few values of n: If n = 2, the consecutive odd integers are 153 and 151. The difference is 153  151 = 2. If n = 3, the consecutive odd integers are 153, 151 and 149. The difference is 153  149 = 4. If n = 4, the consecutive odd integers are 153, 151, 149 and 147. The difference is 153  147 = 6. We can recognize a pattern here. The difference is always two less than twice the number of terms or, in other words, the largest odd integer is always 2n  2 = 2(n  1) greater than the smallest odd integer. Thus, we obtain the formula 153  2(n  1). As an additional example, let's consider the number of terms in an equally spaced set of integers. For instance, how can we solve a question like "how many three digit multiples of 7 are there?" without using any formula? The smallest three digit multiple of 7 is 105 and the largest three digit multiple of 7 is 994. Let's write these numbers: 105 112 119 ... 994 7*15 7*16 7*17 ... 7*142 Let's divide each term by 7. Notice that we are only interested in the number of terms and dividing each term by 7 will not change the number of terms: 15 16 17 ... 142 Let's subtract 14 from each term. Again, we are only interested in the number of terms and subtracting 14 from each term will not change the number of terms: 1 2 3 ... 128 It's not hard to see that there are exactly 128 terms above. Notice that we would get the same answer if we used the familiar formula of [(last term  first term)/(common difference)] + 1 = [(994  105)/7] + 1 = (889/7) + 1 = 127 + 1 = 128. Thanks a lot Scott!
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Re: The measures of the interior angles in a polygon are consecutive odd i
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23 Oct 2019, 02:25
axezcole wrote: ArvindCrackVerbal wrote: The sum of the interior angles of a ‘n’ sided polygon = (n2) * 180 degrees.
Since the interior angles are consecutive odd integers, they represent a set of equally spaced values. For a set of equally spaced values,
Mean = \(\frac{First element + Last element}{2}\).
The largest angle = 153 degrees. So, the smallest angle = 153 – 2(n1). Therefore,
Mean angle = \(\frac{153 + 153 – 2n + 2}{2}\) = 153 – n + 1.
But, Mean angle = \(\frac{Sum of angles}{No. of angles}\).
Therefore, 153 – n + 1 = \(\frac{180 n – 360}{n}\).
Beyond this stage, we can start plugging in the options, starting with option C.
If n = 10, 153 – 10 + 1 = \(\frac{180 * 10 – 360}{10}\) i.e. 144 = 144. The equation is satisfied when we plug in n = 10. Therefore, the correct answer option is C.
Hope this helps! ArvindCrackVerbalBunueldaaghVeritasKarishmachetan2uGMATPrepNowScottTargetTestPrepI have a silly doubt here. I am always confused how do we form equations of such kind ie 153 – 2(n1) . I can see that 153 – 2(n1)=1552n and as n starts from 1 this equation is fine here. But in general is there any rule/logic to derive such kind of equations? Hello axezcole, In deriving expressions like these, I always consider smaller values and find out a pattern before applying the same logic to bigger values. You also need to keep in mind the type of numbers you are dealing with. In this case, since the angles are odd integers, I know that any two of them will differ by 2. I also know that the largest angle is 153. This is one of the 'n' angles, which means that there are (n1) more angles left. Therefore, the smallest angle can be obtained by subtracting the number 2 from 153 (n1) times. Note: I first considered a polygon with 4 angles and saw what would be the smallest angle if the largest angle was 153 and the angles were consecutive odd integers. This is what I meant when I said I established a pattern using smaller values. That gave me, Smallest angle = 153  2  2 2 .... (n1) times, which is Smallest angle = 153  2(n1) Hope that helps!
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Re: The measures of the interior angles in a polygon are consecutive odd i
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24 Oct 2019, 19:14
axezcole wrote: Thanks a lot Scott!
Sure thing!!
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