It is currently 17 Oct 2017, 17:51

### GMAT Club Daily Prep

#### Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

# Events & Promotions

###### Events & Promotions in June
Open Detailed Calendar

# Two vessels A and B contain milk and water mixed in the ratio 8:5 and

Author Message
TAGS:

### Hide Tags

Manager
Joined: 23 Nov 2014
Posts: 59

Kudos [?]: 56 [0], given: 301

Two vessels A and B contain milk and water mixed in the ratio 8:5 and [#permalink]

### Show Tags

14 May 2016, 09:11
7
This post was
BOOKMARKED
00:00

Difficulty:

55% (hard)

Question Stats:

75% (01:46) correct 25% (02:06) wrong based on 118 sessions

### HideShow timer Statistics

Two vessels A and B contain milk and water mixed in the ratio 8:5 and 5:2 respectively. The ratio in which these two mixtures be mixed to get a new mixture containing milk and water in the ratio 9:4

A) 2:7
B) 5:2
C) 3:5
D) 5:7
[Reveal] Spoiler: OA

Last edited by ruchi857 on 14 May 2016, 09:41, edited 1 time in total.

Kudos [?]: 56 [0], given: 301

Math Forum Moderator
Joined: 02 Aug 2009
Posts: 4967

Kudos [?]: 5453 [2], given: 112

Re: Two vessels A and B contain milk and water mixed in the ratio 8:5 and [#permalink]

### Show Tags

14 May 2016, 09:32
2
KUDOS
Expert's post
2
This post was
BOOKMARKED
ruchi857 wrote:
Two vessels A and B contain milk and water mixed in the ratio 8:5 and 5:2 respectively. The ratio in which these two mixtures be mixed to get a new mixture containing milk and water in the ratio 9:4

A) 2:7
B) 5:2
C) 3:5
D) 5:7

Hi,
say A qty of vessel A and B qty of vessel B is added together..
Lets concentrate on quantity of milk

$$\frac{8A}{13}+ \frac{5B}{7}= \frac{9}{13}(A+B)$$ ...

$$\frac{8A}{13}+ \frac{5B}{7}= \frac{9A}{13}+\frac{9B}{13})$$ ..

$$\frac{5B}{7}-\frac{9B}{13}=\frac{9A}{13}-8A/13$$.....

$$\frac{65B-63B}{7*13}=\frac{A}{13}$$...

$$\frac{2B}{7*13}=\frac{A}{13}$$....

$$\frac{A}{B}=\frac{2}{7}$$

A
_________________

Absolute modulus :http://gmatclub.com/forum/absolute-modulus-a-better-understanding-210849.html#p1622372
Combination of similar and dissimilar things : http://gmatclub.com/forum/topic215915.html

Kudos [?]: 5453 [2], given: 112

Math Forum Moderator
Joined: 13 Apr 2015
Posts: 1501

Kudos [?]: 1102 [0], given: 884

Location: India
Concentration: Strategy, General Management
WE: Information Technology (Consulting)
Re: Two vessels A and B contain milk and water mixed in the ratio 8:5 and [#permalink]

### Show Tags

14 May 2016, 09:52
1
This post was
BOOKMARKED
Another method:

Required Ratio = $$\frac{\frac{5}{7} - \frac{9}{13}}{\frac{9}{13} - \frac{8}{13}}$$ = $$\frac{2}{7}$$

Kudos [?]: 1102 [0], given: 884

Manager
Joined: 16 Jan 2013
Posts: 93

Kudos [?]: 3 [0], given: 1192

GMAT 1: 490 Q41 V18
GPA: 2.75
Re: Two vessels A and B contain milk and water mixed in the ratio 8:5 and [#permalink]

### Show Tags

06 Jun 2016, 04:42
Not sure what’s wrong with the following approach:

In vessel A: milk = 8x, water = 5x
In vessel B: milk = 5y, water = 2y
According to the question stem 8x + 5y : 5x + 2y should equal to 9:4

Hence, 8x + 5y / 5x + 2y = 9/4
=> 2y = 13x
=> x/y = 2/13

Regards.
_________________

Kudos [?]: 3 [0], given: 1192

Math Forum Moderator
Joined: 02 Aug 2009
Posts: 4967

Kudos [?]: 5453 [3], given: 112

Re: Two vessels A and B contain milk and water mixed in the ratio 8:5 and [#permalink]

### Show Tags

06 Jun 2016, 09:07
3
KUDOS
Expert's post
Not sure what’s wrong with the following approach:

In vessel A: milk = 8x, water = 5x
In vessel B: milk = 5y, water = 2y
According to the question stem 8x + 5y : 5x + 2y should equal to 9:4

Hence, 8x + 5y / 5x + 2y = 9/4
=> 2y = 13x
=> x/y = 2/13

Regards.

Hi,

you have started well but left it in between....

it is fine till
$$\frac{x}{y} = \frac{2}{13}$$.....
But we are not looking for x/y..
what is the total of FIRST mixture = 8x+5x = 13x....
and SECOND mix = 5y+2y = 7y...

so we are looking for $$\frac{13x}{7y}$$......
$$\frac{x}{y}= \frac{2}{13}$$, so$$\frac{x}{y}*\frac{13}{7} = \frac{2}{13}*\frac{13}{7}.......... \frac{13x}{7y} = \frac{2}{7}$$....
ans$$\frac{2}{7}$$
_________________

Absolute modulus :http://gmatclub.com/forum/absolute-modulus-a-better-understanding-210849.html#p1622372
Combination of similar and dissimilar things : http://gmatclub.com/forum/topic215915.html

Kudos [?]: 5453 [3], given: 112

Director
Joined: 07 Dec 2014
Posts: 811

Kudos [?]: 247 [0], given: 12

Two vessels A and B contain milk and water mixed in the ratio 8:5 and [#permalink]

### Show Tags

17 Jul 2016, 11:08
8A/13+5B/7=9/13(A+B)
A/B=2/7
A:B=2:7

Kudos [?]: 247 [0], given: 12

Manager
Joined: 22 Nov 2016
Posts: 199

Kudos [?]: 36 [0], given: 38

Location: United States
GPA: 3.4
Two vessels A and B contain milk and water mixed in the ratio 8:5 and [#permalink]

### Show Tags

16 Oct 2017, 09:16
There are two equations here, either one of which, when solved, will get you the final answer.

1) $$(\frac{8}{13})*X + (\frac{5}{7})*Y = (\frac{9}{13})*(X+Y)$$

2) $$(\frac{5}{13})*X + (\frac{2}{7})*Y = (\frac{4}{13})*(X+Y)$$

Both equations lead to$$\frac{X}{Y} = \frac{2}{7}$$
_________________

Kudosity killed the cat but your kudos can save it.

Kudos [?]: 36 [0], given: 38

Two vessels A and B contain milk and water mixed in the ratio 8:5 and   [#permalink] 16 Oct 2017, 09:16
Display posts from previous: Sort by