Summer is Coming! Join the Game of Timers Competition to Win Epic Prizes. Registration is Open. Game starts Mon July 1st.

 It is currently 17 Jul 2019, 07:58

### GMAT Club Daily Prep

#### Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

# Two vessels A and B contain milk and water mixed in the ratio 8:5 and

Author Message
TAGS:

### Hide Tags

Manager
Joined: 23 Nov 2014
Posts: 60
Two vessels A and B contain milk and water mixed in the ratio 8:5 and  [#permalink]

### Show Tags

Updated on: 15 Mar 2019, 03:43
3
16
00:00

Difficulty:

55% (hard)

Question Stats:

68% (02:30) correct 32% (02:57) wrong based on 219 sessions

### HideShow timer Statistics

Two vessels A and B contain milk and water mixed in the ratio 8:5 and 5:2 respectively. The ratio in which these two mixtures be mixed to get a new mixture containing milk and water in the ratio 9:4

A) 2:7
B) 5:2
C) 3:5
D) 5:7
E) 6:7

Originally posted by ruchi857 on 14 May 2016, 09:11.
Last edited by Bunuel on 15 Mar 2019, 03:43, edited 2 times in total.
Edited the question.
Math Expert
Joined: 02 Aug 2009
Posts: 7764
Re: Two vessels A and B contain milk and water mixed in the ratio 8:5 and  [#permalink]

### Show Tags

14 May 2016, 09:32
4
8
ruchi857 wrote:
Two vessels A and B contain milk and water mixed in the ratio 8:5 and 5:2 respectively. The ratio in which these two mixtures be mixed to get a new mixture containing milk and water in the ratio 9:4

A) 2:7
B) 5:2
C) 3:5
D) 5:7

Hi,
say A qty of vessel A and B qty of vessel B is added together..
Lets concentrate on quantity of milk

$$\frac{8A}{13}+ \frac{5B}{7}= \frac{9}{13}(A+B)$$ ...

$$\frac{8A}{13}+ \frac{5B}{7}= \frac{9A}{13}+\frac{9B}{13})$$ ..

$$\frac{5B}{7}-\frac{9B}{13}=\frac{9A}{13}-8A/13$$.....

$$\frac{65B-63B}{7*13}=\frac{A}{13}$$...

$$\frac{2B}{7*13}=\frac{A}{13}$$....

$$\frac{A}{B}=\frac{2}{7}$$

A
_________________
Retired Moderator
Joined: 13 Apr 2015
Posts: 1677
Location: India
Concentration: Strategy, General Management
GMAT 1: 200 Q1 V1
GPA: 4
WE: Analyst (Retail)
Re: Two vessels A and B contain milk and water mixed in the ratio 8:5 and  [#permalink]

### Show Tags

14 May 2016, 09:52
3
2
Another method:

Required Ratio = $$\frac{\frac{5}{7} - \frac{9}{13}}{\frac{9}{13} - \frac{8}{13}}$$ = $$\frac{2}{7}$$

##### General Discussion
Manager
Joined: 16 Jan 2013
Posts: 79
GMAT 1: 490 Q41 V18
GMAT 2: 610 Q45 V28
GPA: 2.75
Re: Two vessels A and B contain milk and water mixed in the ratio 8:5 and  [#permalink]

### Show Tags

06 Jun 2016, 04:42
1
Not sure what’s wrong with the following approach:

In vessel A: milk = 8x, water = 5x
In vessel B: milk = 5y, water = 2y
According to the question stem 8x + 5y : 5x + 2y should equal to 9:4

Hence, 8x + 5y / 5x + 2y = 9/4
=> 2y = 13x
=> x/y = 2/13

Regards.
_________________
Math Expert
Joined: 02 Aug 2009
Posts: 7764
Re: Two vessels A and B contain milk and water mixed in the ratio 8:5 and  [#permalink]

### Show Tags

06 Jun 2016, 09:07
4
3
Not sure what’s wrong with the following approach:

In vessel A: milk = 8x, water = 5x
In vessel B: milk = 5y, water = 2y
According to the question stem 8x + 5y : 5x + 2y should equal to 9:4

Hence, 8x + 5y / 5x + 2y = 9/4
=> 2y = 13x
=> x/y = 2/13

Regards.

Hi,

you have started well but left it in between....

it is fine till
$$\frac{x}{y} = \frac{2}{13}$$.....
But we are not looking for x/y..
what is the total of FIRST mixture = 8x+5x = 13x....
and SECOND mix = 5y+2y = 7y...

so we are looking for $$\frac{13x}{7y}$$......
$$\frac{x}{y}= \frac{2}{13}$$, so$$\frac{x}{y}*\frac{13}{7} = \frac{2}{13}*\frac{13}{7}.......... \frac{13x}{7y} = \frac{2}{7}$$....
ans$$\frac{2}{7}$$
_________________
VP
Joined: 07 Dec 2014
Posts: 1206
Re: Two vessels A and B contain milk and water mixed in the ratio 8:5 and  [#permalink]

### Show Tags

17 Jul 2016, 11:08
1
8A/13+5B/7=9/13(A+B)
A/B=2/7
A:B=2:7
Manager
Joined: 22 Nov 2016
Posts: 205
Location: United States
GPA: 3.4
Re: Two vessels A and B contain milk and water mixed in the ratio 8:5 and  [#permalink]

### Show Tags

16 Oct 2017, 09:16
1
There are two equations here, either one of which, when solved, will get you the final answer.

1) $$(\frac{8}{13})*X + (\frac{5}{7})*Y = (\frac{9}{13})*(X+Y)$$

2) $$(\frac{5}{13})*X + (\frac{2}{7})*Y = (\frac{4}{13})*(X+Y)$$

Both equations lead to$$\frac{X}{Y} = \frac{2}{7}$$
_________________
Kudosity killed the cat but your kudos can save it.
Manager
Joined: 04 May 2014
Posts: 158
Location: India
WE: Sales (Mutual Funds and Brokerage)
Re: Two vessels A and B contain milk and water mixed in the ratio 8:5 and  [#permalink]

### Show Tags

14 Nov 2017, 07:08
1
In questions like this concentrate only on one of the ingredients of the mixture.

Let us take milk.

what is the percentage of milk in A=8/13. (When we have a ratio like given in this question 8:5 add them to get the total)

% of milk in B=5/7

% of milk after mixing=9/13=average after mixing 2 solutions or mixtures.

use weighted average formula

w1/w2=(A2-avg)/(avg-A1). Here A1=A and A2=B

A1=8/13, A2=5/7 and Avg=9/13. (You can take A1 and A2 as any of the given value and you will get the same answer)

w1/w2=(5/7-9/13)÷(9/13-8/13)=[(65-63)/91]÷[(9-8)/13]=2/91÷1/13=2/7 or 2:7 answer is =A
Intern
Joined: 23 Mar 2018
Posts: 1
Re: Two vessels A and B contain milk and water mixed in the ratio 8:5 and  [#permalink]

### Show Tags

23 Mar 2018, 04:07
8/13 5/7
\
\
9/13
\
\
2/91 1/13

=2/91:1/13= 2/91*13/1

Posted from my mobile device
Target Test Prep Representative
Affiliations: Target Test Prep
Joined: 04 Mar 2011
Posts: 2823
Re: Two vessels A and B contain milk and water mixed in the ratio 8:5 and  [#permalink]

### Show Tags

26 Mar 2018, 17:36
ruchi857 wrote:
Two vessels A and B contain milk and water mixed in the ratio 8:5 and 5:2 respectively. The ratio in which these two mixtures be mixed to get a new mixture containing milk and water in the ratio 9:4

A) 2:7
B) 5:2
C) 3:5
D) 5:7

We can create the ratios:

Vessel A:

milk : water = 8x : 5x and so 8x + 5x = 13x (Eq. 1)

Vessel B:

milk : water = 5y : 2y and so 5y + 2y = 7y (Eq. 2)

We can create the equation:

(8x + 5y)/(5x + 2y) = 9/4

4(8x + 5y) = 9(5x + 2y)

32x + 20y = 45x + 18y

2y = 13x (Eq. 3)

Notice that Eq. 1 stated that 8x + 5x = 13x; thus, in terms of y, we use Eq. 3 to state that vessel A has an amount of 2y, and vessel B has an amount of 5y + 2y = 7y (from Eq. 2). Thus, the ratio of the amount in vessel A to the amount in vessel B is 2y/7y = 2/7.

_________________

# Jeffrey Miller

Jeff@TargetTestPrep.com
122 Reviews

5-star rated online GMAT quant
self study course

See why Target Test Prep is the top rated GMAT quant course on GMAT Club. Read Our Reviews

If you find one of my posts helpful, please take a moment to click on the "Kudos" button.

Non-Human User
Joined: 09 Sep 2013
Posts: 11668
Re: Two vessels A and B contain milk and water mixed in the ratio 8:5 and  [#permalink]

### Show Tags

10 Apr 2019, 05:04
Hello from the GMAT Club BumpBot!

Thanks to another GMAT Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).

Want to see all other topics I dig out? Follow me (click follow button on profile). You will receive a summary of all topics I bump in your profile area as well as via email.
_________________
Re: Two vessels A and B contain milk and water mixed in the ratio 8:5 and   [#permalink] 10 Apr 2019, 05:04
Display posts from previous: Sort by