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From statement 1:

Sum of odd and even is given, but The number of integers, which are odd or even is not given. Hence Insufficient.

From statement 2:

The sum of the lowest 10 = 400.
The sum of the highest 10 = 1600.
Average = 2000/20 = 100

B is the answer.
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Bunuel
What is the arithmetic mean of a data set with twenty data values, each of which is a positive integer?


(1) The sum of the odd values is 1,144 and the sum of the even values is 856.

(2) The sum of the lowest ten values is 400 and the sum of the greatest ten values is 1,600.

#1
sufficient
as not given whether the 20 data values are consecutive values or not
#2
400 + 1600/20 = 100
IMO D
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Is really 1 insufficient?
Because if I have sum of odd values and sum of even values I can calculate the sum of all values and divide by 20 to get the mean. This statement alone is sufficient as well.
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OA:D

1) The sum of the odd values is 1144 and the even values is 856

Total Sum = Sum of odd values + Sum of even values \(= 1144+856 =2000\)
Total number of term \(= 20\)

Average\(= \frac{2000}{20} =100\)

Statement 1 is sufficient to find out the value of average.

2) The sum of the lowest ten values is 400 and the greatest ten values is 1600.

Total Sum = Sum of lowest ten values + Sum of greatest ten values \(= 400+1600 =2000\)
Total number of term \(= 20\)

Average\(= \frac{2000}{20} =100\)

Statement 2 is sufficient to find out the value of average.
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