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What is the greatest prime factor of 6^8−3^8 ?

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zxcvbnmas
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What is the greatest prime factor of 6^8−3^8 ? [#permalink] What is the greatest prime factor of 6^8−3^8 ?   15 Feb 2016, 13:48
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What is the greatest prime factor of \(6^8−3^8\) ?

A) 3

B) 11

C) 17

D) 19

E) 31
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C
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What is the greatest prime factor of 6^8−3^8 ? [#permalink] What is the greatest prime factor of 6^8−3^8 ?   Updated on: 15 Feb 2016, 14:03
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\(6^8 - 3^8\)

\(2^8*3^8 - 3^8\)

\(3^8(2^8 - 1)\)

\((2^4 + 1)(2^4 - 1)\)

\((16+1)(16-1)\)

\((17)(15)\)

So 17 is Answer

Originally posted by zxcvbnmas on 15 Feb 2016, 13:56.
Last edited by zxcvbnmas on 15 Feb 2016, 14:03, edited 1 time in total.
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BrentGMATPrepNow
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What is the greatest prime factor of 6^8−3^8 ? [#permalink] What is the greatest prime factor of 6^8−3^8 ?   Updated on: 18 Jun 2021, 06:13
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Quote:

What is the greatest prime factor of 6⁸ − 3⁸?

a) 3
b) 11
c) 17
d) 19
e) 31

Thanks in advance :-)


6⁸ − 3⁸ is a DIFFERENCE OF SQUARES. So we can factor it.
6⁸ − 3⁸ = (6⁴ + 3⁴)(6⁴ - 3⁴)
= (6⁴ + 3⁴)(6² + 3²)(6² - 3²)
= (6⁴ + 3⁴)(6² + 3²)(6 + 3)(6 - 3)
= (6⁴ + 3⁴)(45)(9)(3)
= (6⁴ + 3⁴)(3)(3)(5)(3)(3)(3)

Hmmmm, we can see that the correct answer is "hiding" in the first number (6⁴ + 3⁴)
Let's factor out the 3⁴, to get:
6⁴ + 3⁴ = 3⁴(2⁴ + 1)
= 3⁴(16 + 1)
= 3⁴(17)
= (3)(3)(3)(3)(17)

So, 6⁸ − 3⁸ = (3)(3)(3)(3)(17)(3)(3)(5)(3)(3)(3)

So the correct answer is C

Cheers,
Brent

Originally posted by BrentGMATPrepNow on 15 Feb 2016, 13:55.
Last edited by BrentGMATPrepNow on 18 Jun 2021, 06:13, edited 1 time in total.
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Re: What is the greatest prime factor of 6^8−3^8 ? [#permalink] What is the greatest prime factor of 6^8−3^8 ?   15 Feb 2016, 14:01
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zxcvbnmas wrote:
What is the greatest prime factor of \(6^8−3^8\) ?

A) 3

B) 11

C) 17

D) 19

E) 31


Solution:

\(6^8-3^8=3^8*(2^8-1)=3^8(256-1)=3^8(255)=3^8*51*5=3^8*17*3*5\).

ANS .17
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Re: What is the greatest prime factor of 6^8−3^8 ? [#permalink] What is the greatest prime factor of 6^8−3^8 ?   09 Jul 2016, 13:05
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how do u solve this? how do u know what methodology to apply when u get a question like this?
im soo confused!!
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What is the greatest prime factor of 6^8−3^8 ? [#permalink] What is the greatest prime factor of 6^8−3^8 ?   09 Jul 2016, 23:27
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jonmarrow wrote:
how do u solve this? how do u know what methodology to apply when u get a question like this?
im soo confused!!


To find the greatest prime of 6^8−3^8 you should make prime factorization of this number. The techniques above does exactly this.

Check similar questions to practice:
what-is-the-greatest-prime-factor-of-158991.html
what-is-the-greatest-prime-factor-of-104757.html
what-is-the-greatest-prime-factor-of-70126.html
what-is-the-greatest-prime-factor-of-190425.html

Hope it helps.
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What is the greatest prime factor of 6^8−3^8 ? [#permalink] What is the greatest prime factor of 6^8−3^8 ?   Updated on: 06 Apr 2018, 00:20
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First figure out the common factors in both
\(6^8\) can be written s \(2^8 * 3^8\)

\(take 3^8 common\)

\(3^8*2^8-3^8\)
\(3^8(2^8-1)\) (here you should know that \(2^8 = 256\), The easiest way to remember this is \(2^{10}=1024\) and now you can derive most \(2^x\))
SO your expression becomes \(3^8(256-1)\) ===> \(3^8 (255)\)==>\(3^8 (17*15)\)
so your prime factorisation will be \(3^8*15*17\)===>\(3^8*(3^1*5^1)*17\)=====>\(3^9*5^1*17\)

so as we can see there are there prime numbers here 3, 5 and 17 out of which 3 is the smallest prime number and 17 is the biggest.

Hence 17 is the biggest Prime Factor

Answer is C


zxcvbnmas wrote:
What is the greatest prime factor of \(6^8−3^8\) ?

A) 3

B) 11

C) 17

D) 19

E) 31

Originally posted by LogicGuru1 on 10 Jul 2016, 01:40.
Last edited by LogicGuru1 on 06 Apr 2018, 00:20, edited 1 time in total.
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Re: What is the greatest prime factor of 6^8−3^8 ? [#permalink] What is the greatest prime factor of 6^8−3^8 ?   11 Jul 2016, 05:06
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3^8(2^8-1)=3^8(255) =3^8(17*15)=3^8*17*5*3=3^9*5*17
therefore 17 C
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Re: What is the greatest prime factor of 6^8−3^8 ? [#permalink] What is the greatest prime factor of 6^8−3^8 ?   14 Jul 2016, 20:57
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AdlaT wrote:
zxcvbnmas wrote:
What is the greatest prime factor of \(6^8−3^8\) ?

A) 3

B) 11

C) 17

D) 19

E) 31


Solution:

\(6^8-3^8=3^8*(2^8-1)=3^8(256-1)=3^8(255)=3^8*51*5=3^8*17*3*5\).

ANS .17



what about 3^8, it could have a prime factor greater than 17.
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Re: What is the greatest prime factor of 6^8−3^8 ? [#permalink] What is the greatest prime factor of 6^8−3^8 ?   14 Jul 2016, 21:08
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ramanan42 wrote:
AdlaT wrote:
zxcvbnmas wrote:
What is the greatest prime factor of \(6^8−3^8\) ?

A) 3

B) 11

C) 17

D) 19

E) 31


Solution:

\(6^8-3^8=3^8*(2^8-1)=3^8(256-1)=3^8(255)=3^8*51*5=3^8*17*3*5\).

ANS .17



what about 3^8, it could have a prime factor greater than 17.


understood the reasoning behind this . ! good now!
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Re: What is the greatest prime factor of 6^8−3^8 ? [#permalink] What is the greatest prime factor of 6^8−3^8 ?   10 Apr 2017, 18:49
GMATPrepNow wrote:
Quote:

What is the greatest prime factor of 6⁸ − 3⁸?

a) 3
b) 11
c) 17
d) 19
e) 31

Thanks in advance :-)


6⁸ − 3⁸ is a DIFFERENCE OF SQUARES. So we can factor it.
6⁸ − 3⁸ = (6⁴ + 3⁴)(6⁴ - 3⁴)
= (6⁴ + 3⁴)(6² + 3²)(6² - 3²)
= (6⁴ + 3⁴)(6² + 3²)(6 + 3)(6 - 3)
= (6⁴ + 3⁴)(45)(9)(3)
= (6⁴ + 3⁴)(3)(3)(5)(3)(3)(3)

Hmmmm, we can see that the correct answer is "hiding" in the first number (6⁴ + 3⁴)
Let's factor out the 3⁴, to get:
6⁴ + 3⁴ = 3⁴(2⁴ + 1)
= 3⁴(16 + 1)
= 3⁴(17)
= (3)(3)(3)(3)(17)

So, 6⁸ − 3⁸ = (3)(3)(3)(3)(17)(3)(3)(5)(3)(3)(3)

So the correct answer is C

ASIDE: For more on factoring differences of squares, see our free video - https://www.gmatprepnow.com/module/gmat- ... /video/955

Cheers,
Brent


It's interesting to see all the different methodologies here- many paths that lead to the same answers; anyways, my method following this technique was slightly different. When you mention the answer lies in (6^4 + 3^4)

3^4(3^4 +1)
81 (82)
82/2 =
41/3 = 17 (plug in values)
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Re: What is the greatest prime factor of 6^8−3^8 ? [#permalink] What is the greatest prime factor of 6^8−3^8 ?   08 Jul 2017, 14:59
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zxcvbnmas wrote:
What is the greatest prime factor of \(6^8−3^8\) ?

A) 3

B) 11

C) 17

D) 19

E) 31


In order to find the greatest prime factor, lets break down the below number into its prime factors

\(6^8−3^8\)

= \((3^8 * 2^8) − 3^8\)

= \((3^8 * 2^8) − 3^8\)

= \(3^8 (2^8 - 1)\)

= \(3^8 * 255\)

= \(3^8 * 15 * 17\)

= \(3^9 * 5 * 17\)

As we can see that the greatest prime factor is \(17\)

Answer is C
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Re: What is the greatest prime factor of 6^8−3^8 ? [#permalink] What is the greatest prime factor of 6^8−3^8 ?   08 Feb 2018, 12:38
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Hi All,

If you're comfortable with Exponent Rules and Factoring, you can also approach this prompt without using a Quadratic:

6^8 - 3^8 =

First, we can 'rewrite' 6^8....
(2^8)(3^8) - 3^8

Now, factor out 3^8...
(3^8)(2^8 - 1)

2^8 = 256
(3^8)(256-1)
(3^8)(255)
(3^8)(5)(51)
(3^8)(5)(3)(17)

The greatest prime factor is 17.

Final Answer:
Show Spoiler
C


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Re: What is the greatest prime factor of 6^8−3^8 ? [#permalink] What is the greatest prime factor of 6^8−3^8 ?   05 Aug 2018, 09:21
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6^8-3^8=
3^8*2^8-3^8=
3^8(2^8-1)=
3^8(256-1)=
3^8(255)=
3^8(3*5*17)
Answ is 17 (C)
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Re: What is the greatest prime factor of 6^8−3^8 ? [#permalink] What is the greatest prime factor of 6^8−3^8 ?   05 Aug 2018, 10:54
zxcvbnmas wrote:
What is the greatest prime factor of \(6^8−3^8\) ?

A) 3

B) 11

C) 17

D) 19

E) 31


\(6^8−3^8\)

= \(2^8*3^8−3^8\)

= \(3^8(2^8 −1)\)

Now, \(2^8 − 1\) \(= 255 = 15*17\), So The greatest Prime number is 17 Answer must be (C)
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Re: What is the greatest prime factor of 6^8−3^8 ? [#permalink] What is the greatest prime factor of 6^8−3^8 ?   20 May 2019, 15:11
It should be 17, since we can use a^2 - b^2 here. C
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Re: What is the greatest prime factor of 6^8−3^8 ? [#permalink] What is the greatest prime factor of 6^8−3^8 ?   20 May 2019, 16:46
zxcvbnmas wrote:
What is the greatest prime factor of \(6^8−3^8\) ?

A) 3

B) 11

C) 17

D) 19

E) 31


Prime factor is a number that is divisible by only one and itself; e.g. 3, 5, 19 etc.

We have to break down this number as far as possible.

3^8 * (2^8 - 1)
3^8 * (255)
3^8 * (51*5)
3^8 * (5)(17*3)

So, this number can be factorized into following primes: 3, 5, 17. 17 being the greatest.
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Re: What is the greatest prime factor of 6^8−3^8 ? [#permalink] What is the greatest prime factor of 6^8−3^8 ?   10 Jul 2020, 05:31
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zxcvbnmas wrote:
What is the greatest prime factor of \(6^8−3^8\) ?

A) 3

B) 11

C) 17

D) 19

E) 31


Solution:

Let’s prime factorize the given expression:

6^8 - 3^8

3^8(2^8 - 1)

3^8(2^4 - 1)(2^4 + 1)

3^8(16 - 1)(16 + 1)

3^8(15)(17)

3^8 x 3 x 5 x 17

So the largest prime factor is 17.

Answer: C
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What is the greatest prime factor of 6^8−3^8 ? [#permalink] What is the greatest prime factor of 6^8−3^8 ?   21 Nov 2020, 11:27
zxcvbnmas wrote:
What is the greatest prime factor of \(6^8−3^8\) ?

A) 3

B) 11

C) 17

D) 19

E) 31


\(6^8 - 3^8\)

= \((3^8 * 2^8) - 3^8\)

\(3^8 ( 2^8 - 1)\)

\(3^8 (2^4 +1)(2^4-1)\)

\(3^8 * 17 * 15\)

Greatest prime factor is 17. Answer is C.
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