When running a mile during a recent track meet, Nuria was initially

The long approach is to meticulously convert 11/25 of a minute to seconds, and then ADD that unaccounted time to Nuria's recorded time (of 5 minutes, 44 seconds)
However, when we check the answer choices before performing any calculations (ALWAYS check the answer choices before performing any calculations), we see that most answers are LESS THAN 5 minutes, 44 seconds

Now notice that 11/25 is kind of close to 1/2
So, 11/25 minutes is approximately 1/2 a minute (aka 30 seconds)
When we add 30 seconds to 5 minutes, 44 seconds, we get MORE than 6 minutes.

Answer: E

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11/25=.4400 minute
44 seconds=.7333 minute
.4399+5+.7333=6.1732 minutes=6 minutes, 10.4 seconds

One approach:
The watch starts to work after Nuria began his running. It means the time should be greater than credited 5 minutes, 44 seconds. The only number is 6 minutes, 10.4 seconds.

Another approach:
11/25 close to 30 second when added to the 5 minutes, 44 seconds, it means it passes 6 minute.


Answer: E

11/25 minutes is 11/25 x 60 = 11/5 x 12 = 26.4 seconds

Thus, her actual time was 5 minutes 44 seconds + 26.4 seconds = 5 minutes 70.4 seconds = 6 minutes 10.4 seconds

Answer: E
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Time 1 = 5 min 44 secs

Delay = 11/25 * 60 secs

Delay = 132/5 secs

= 26.4 secs

Actual time = 5 : 44 + 0 : 26.4

= 6 : 10.4 secs

Hence(E)
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\(? = 5\min 44{\text{s}} + \frac{{11}}{{25}}\min\)

\(\frac{{11}}{{25}}\min \,\,\left( {\frac{{60{\text{s}}}}{{1\min }}} \right)\,\,\, = \,\,\,\frac{{11 \cdot 12}}{5}{\text{s}}\,\,\,\mathop = \limits^{\left( * \right)} \,\,\,26\frac{2}{5}{\text{s}}\)

\(\left( * \right)\,\,\,\frac{{\left( {10 + 1} \right) \cdot 12}}{5} = \underleftrightarrow {2 \cdot 12 + \frac{{12}}{5} = 24 + \frac{{10 + 2}}{5}} = 26\frac{2}{5}{\text{s}}\)

\(? = 5\min 44s + 16s + 10s + \frac{2}{5}s = 6\min 10.4\,{\text{s}}\)

POST-MORTEM: the alternative choices help you avoid the precise calculations above, BUT I think they are very instructive...

The above follows the notations and rationale taught in the GMATH method.
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Hi All,

We're told that when running a mile during a recent track meet, Nuria was initially credited with a final time of 5 minutes, 44 seconds. Shortly after her run, officials realized that the timing mechanism malfunctioned. The stopwatch did not begin timing her until 11/25 of a MINUTE after she began to run. If the time was otherwise correct, how long did it actually take Nuria to run the mile? Based on the 'spread' of the answer choices, you can actually answer this question with almost no math at all; paying attention to the information that you're given - along with a little logic - can get you the correct answer rather quickly.

We know that Nuria was timed at 5 minutes 44 seconds, but the stop watch was NOT started until almost HALF OF A MINUTE had gone by. Thus, Nuria's actual time is greater than 5 minutes 44 second - almost HALF A MINUTE greater. There's only one answer that makes sense...

Final Answer:

GMAT assassins aren't born, they're made,
Rich

Hello,

You can get the answer in less than 20 seconds.

If the time didn't start right away, the total time should be 5Minutes 44 Second Plus Some time.. The answer should be > 5minutes 44 seconds..

When you look at the answer choices, there is only one answer that is more than 5M and 44S, which is E....

The initial time recorded = 5 minutes 44 seconds

Since the stopwatch began after 11/25 of a minute after she began, the lapsed time will be added to the recorded time.

Thus, the actual time taken by Nuria = 5 minutes 44 seconds + (11/25)*60 seconds.

Actual time = 6 minutes 10.4 seconds.

Thus, the correct option is E.