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Which of the following must be non-negative?

A. (a-0.9)(a-1)

B. (a+1)(a-1)

C. (a+0.9)(a+1)

D. (a-0.9)(a-0.9)

E. a(a+1)


Option E.
Reasoning: The product of two consecutive integers will always be non-negative.
PS: It can be zero and zero is a non-negative number.

Be careful with variables.
It is nowhere written that a is an integer.
So, a(a+1) will be negative when a is between 0 and -1. For example a=-0.5, so -0.5*0.5=-0.25

Answer is (a-0.9)(a-0.9)

\((a-0.9)(a-0.9)=(a-0.9)^2\)
Squares are always non negative

D

Thanks a lot chetan2u, got my mistake. Not sure, why I took it to be an integer.
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Bunuel
Which of the following must be non-negative?

A. (a-0.9)(a-1)

B. (a+1)(a-1)

C. (a+0.9)(a+1)

D. (a-0.9)(a-0.9)

E. a(a+1)

Option D

D) ... can be simplified to \((a-0.9)^2\) . Square of any number is \(>= 0\), in other words its always non negative.

Since we are not sure whether "a" is positive or negative, we can not comment on other options.
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Bunuel
Which of the following must be non-negative?

A. (a-0.9)(a-1)

B. (a+1)(a-1)

C. (a+0.9)(a+1)

D. (a-0.9)(a-0.9)

E. a(a+1)

5-sec approach:

D. (a-0.9)(a-0.9) = (a-0.9)^2. The square of a number is always non-negative.

Answer: D.
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Quick question: Option B says (a+1)(a-1) = a^2 - 1^2. Can we prove that it can produce a negative number?
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D

It can be helpful to think of the rules regarding stuff like a^2 etc.

If you re-arrange (D), it's actually something similar to (a-b)^2 ... which is basically (d)^2 ... which has to be 0 or above.
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↧↧↧ Detailed Video Solution to the Problem Series ↧↧↧



We need to find which of the following must be non-negative?

A. (a-0.9)(a-1) : will be negative for values of a between 0.9 and 1 as first term will be positive and second term will be negative => FALSE

B. (a+1)(a-1) = a^2 - 1 : will be negative for values of a between -1 and 1 => FALSE

C. (a+0.9)(a+1) : will be negative for values of a between -0.9 and -1 as first term will be negative and second term will be positive => FALSE

D. (a-0.9)(a-0.9) = (a - 0.9)^2 : since this is a square of a number so it will ALWAYS be non-negative => TRUE

E. a(a+1) : will be negative for values of a between -1 and 0 as a will be negative but (a+1) will be positive => FALSE

So, Answer will be D
Hope it helps!

Watch the following video to MASTER Inequalities

­
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