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Working together but independently, Scott and Eric can addre [#permalink]
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Could someone please explain how Statement 1 is sufficient? I went through the responses already here but could not understand as they are rather unclear. Thank you.

Edit 1: I managed to solve it this way, could anyone confirm that this is in fact correct?

S = Rate of Scott
E = Rate of Eric

\(S + E =\frac{x}{18}\) X being the amount of work done, and 18 being the time taken, thus X/18 given the rate for the two together

1. In M minutes, Scott addresses three times as many envelopes as Eric addresses in M minutes.

\(Eric = EM\)
\(Scott = 3EM\)

\(3EM + EM = \frac{x}{18}\)
\(4EM = \frac{x}{18}\)
\(x = 72EM\)

x = 72EM which means it would take Eric 72 hours to complete X amount of work, and since Scott can address three times as many envelopes as Eric, he can complete X amount of work in 24 hours.
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Re: Working together but independently, Scott and Eric can addre [#permalink]
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The formula for the statement in question is (S+E)*18=X. The questions is S*?=X
1.The first statement gives us ratio of Scott's rate of work to Eric's. The ratios is S/E=3r/1r
(3r+1r)*18=X; 72r=X; r=X/72; S=3X/72=X/24. It takes Scott 24 hours to address X envelopes. This statement is sufficient.
2. The second statement gives us Eric's rate: E=X/72; (S+E)*18=72E; 18S=54E; 1S=3E; It takes Eric three times as much time to address X enveloped as it takes Scott. Since Eric can do the work in 72 hours, Scott can do it in 72/3=24 hours. This statement is also sufficient.

Both statements alone are sufficient to answer this question.
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Re: Working together but independently, Scott and Eric can addre [#permalink]
I have solved this way:

E
S
E+S 1.000 18

(1)

E 1.000 M
S 3.000 M
E+S 1.000 18
3.000 / M + 1.000 / M = 1.000 / 18 >>> M = 72 SOLVE

(2)

1.000 / 72 + 1.000 / x = 1.000 / 18 >>>>> x = 24 SOLVE

Answer: D
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Re: Working together but independently, Scott and Eric can addre [#permalink]
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It is clear for me statement 2, but I didn't understand how can I solve the question using statement 1.

Can someone can help me?

Thaaaanks
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Working together but independently, Scott and Eric can addre [#permalink]
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pepo wrote:
It is clear for me statement 2, but I didn't understand how can I solve the question using statement 1.

Can someone can help me?

Thaaaanks


Let E and S be the number of envelopes/hour produced by Eric and Scott resp.

Per statement 1, You are given that 3E=S ---> in M minutes, Eric can produce 3 times as many envelopes as produced by Scott. IN 1 hour, they will produce each

--->Eric = EM/60 Scott = 3EM/60 . In 18 hours, they produce,

3EM*18/60+EM*18/60 = X ---> X= 72EM/60

Thus, from above, number of envelopes produced by Eric in 1 hour = EM/60 ---> time for him to produce X (=72EM/60) envelopes =X/(EM/60) = (72EM/60)/(EM/60) = 72 hours.

Hence statement 1 is sufficient.

Hope this helps.

Originally posted by ENGRTOMBA2018 on 20 Jan 2016, 10:56.
Last edited by ENGRTOMBA2018 on 20 Jan 2016, 13:29, edited 1 time in total.
Edited the typos
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Re: Working together but independently, Scott and Eric can addre [#permalink]
pepo wrote:
Engr2012 wrote:
pepo wrote:
It is clear for me statement 2, but I didn't understand how can I solve the question using statement 1.

Can someone can help me?

Thaaaanks


Let E and S be the number of envelopes/hour produced by Eric and Scott resp.

Per statement 1, You are given that E=3S ---> in M minutes, Eric can produce 3 times as many envelopes as produced by Scott. IN 1 hour, they will produce each

---> Scott = SM/60 and E = 3SM/60. In 18 hours, they produce,

3SM*18/60+SM/60 = X ---> X= 4SM/60

Thus, from above, number of envelopes produced by Eric in 1 hour = 3SM/60 ---> time for him to produce X (=4SM/60) envelopes =X/(3SM/60) = (4SM/60)/(3SM/60) = 4/3 hours.

Hence statement 1 is sufficient.

Hope this helps.


Hi Engr2012,

thanks for your reply!!!

I have just 2 issues:
1) statement says: "In M minutes, Scott address three times as many envelopes as Eric address in M minutes". It should be S=3E, right?
2) I don't understand how you can get X= 4SM/60 from 3SM*18/60+SM/60 = X.
I performed the calculations and I got X=55sm/60.

Best,
Pepo


My bad. Thanks for pointing it out. I have corrected the typos in my solution above although nothing would change as this is a DS question and any unique value will make statement 1 sufficient.
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Re: Working together but independently, Scott and Eric can addre [#permalink]
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