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Math Expert
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Re: 10^x + 10^y + 10^z = n, where x, y, and z are positive integers. Which [#permalink]
Consider x as 1, y as 3, z as 2. Then n = 1110. the total number of zeros to the left of the decimal point is 1.

Statement 2 is possible as y-z = 3-2 = 1.

Since x,y and z are positive integers. min value of x+y is 2. But if x is 1 and y is 1 and z is 2. then n = 120. only 1 zero. cannot be possible.
Statement 1 is not possible.

If x is 3, y is 2 and z is 1. then n will contain 1 zero. Hence statement 3 is possible.

Only 2 and 3 are possible.

D is the answer.
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Re: 10^x + 10^y + 10^z = n, where x, y, and z are positive integers. Which [#permalink]
Hi GMAT fellows,

I am having hard time, understanding solution for this problem.
Could someone please explain any approach to do these kind of questions?
GMAT Club Bot
Re: 10^x + 10^y + 10^z = n, where x, y, and z are positive integers. Which [#permalink]
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