GMAT Question of the Day - Daily to your Mailbox; hard ones only

It is currently 07 Dec 2019, 02:02

Close

GMAT Club Daily Prep

Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track
Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.

Close

Request Expert Reply

Confirm Cancel

A milk vendor has 2 cans of milk. The first contains 25% water and the

  new topic post reply Question banks Downloads My Bookmarks Reviews Important topics  
Author Message
TAGS:

Hide Tags

Find Similar Topics 
Manager
Manager
User avatar
G
Joined: 03 Nov 2018
Posts: 62
Location: India
Schools: LBS '21
GMAT 1: 580 Q44 V28
GMAT 2: 580 Q44 V28
GPA: 3.44
CAT Tests
A milk vendor has 2 cans of milk. The first contains 25% water and the  [#permalink]

Show Tags

New post 05 Feb 2019, 07:52
3
1
12
00:00
A
B
C
D
E

Difficulty:

  55% (hard)

Question Stats:

68% (02:35) correct 32% (02:50) wrong based on 184 sessions

HideShow timer Statistics

A milk vendor has 2 cans of milk. The first contains 25% water and the rest milk. The second contains 50% water. How much milk should he mix from each of the containers so as to get 12 litres of milk such that the ratio of water to milk is 3 : 5?

A. 4 litres, 8 litres
B. 6 litres, 6 litres
C. 5 litres, 7 litres
D. 7 litres, 5 litres
E 8 litres, 7litres
Target Test Prep Representative
User avatar
D
Status: Chief Curriculum and Content Architect
Affiliations: Target Test Prep
Joined: 24 Nov 2014
Posts: 627
GMAT 1: 800 Q51 V51
Re: A milk vendor has 2 cans of milk. The first contains 25% water and the  [#permalink]

Show Tags

New post 05 Feb 2019, 08:15
3
1
To answer this question, let's match up the percentages of water in the two milk mixtures with the ratio that we want to achieve.

The ratio that we want to achieve is 3:5, water to milk.

So, we want 3/8 water and 5/8 milk.

To answer the question, let's focus on the water, since, if 3/8 of the mixture is water, the other 5/8 will have be milk.

The mixes that we have are 25% water and 50% water. Let's express them in 8ths as well.

The first mix is 2/8 water. The second mix is 4/8 water.

We want 3/8 water, and since 3/8 is halfway between 2/8 and 4/8, this question is turning out to be pretty easy.

By using allegation, we can determine that we have to use equal quantities of the two mixtures.

The correct answer is (B).
_________________

Marty Murray

Chief Curriculum and Content Architect

Marty@targettestprep.com
TTP - Target Test Prep Logo
122 Reviews

5-star rated online GMAT quant
self study course

See why Target Test Prep is the top rated GMAT quant course on GMAT Club. Read Our Reviews

If you find one of my posts helpful, please take a moment to click on the "Kudos" button.

Intern
Intern
avatar
B
Joined: 04 Mar 2017
Posts: 7
Reviews Badge
Re: A milk vendor has 2 cans of milk. The first contains 25% water and the  [#permalink]

Show Tags

New post 05 Feb 2019, 08:34
thx for the solution, so useful
Manager
Manager
avatar
G
Joined: 14 May 2018
Posts: 96
Location: India
Concentration: Finance, Entrepreneurship
GMAT 1: 710 Q49 V38
GPA: 4
Re: A milk vendor has 2 cans of milk. The first contains 25% water and the  [#permalink]

Show Tags

New post 05 Feb 2019, 21:41
1
dharam44 wrote:
A milk vendor has 2 cans of milk. The first contains 25% water and the rest milk. The second contains 50% water. How much milk should he mix from each of the containers so as to get 12 litres of milk such that the ratio of water to milk is 3 : 5?

A. 4 litres, 8 litres
B. 6 litres, 6 litres
C. 5 litres, 7 litres
D. 7 litres, 5 litres
E 8 litres, 7litres


Another quick way to solve could be-

3:5 ratio of 12l water:milk ==>4.5l water and 7.5l milk
Now see option A-it has 1l+2l=3l water this is not the solution
Option B-1.5l+3l water=4.5l water this is the answer
(you can also check other options to confirm that they don't give the same answer,but they won't since the question has a unique solution)
Director
Director
User avatar
V
Joined: 27 May 2012
Posts: 945
Re: A milk vendor has 2 cans of milk. The first contains 25% water and the  [#permalink]

Show Tags

New post 19 Mar 2019, 12:47
MartyTargetTestPrep wrote:
To answer this question, let's match up the percentages of water in the two milk mixtures with the ratio that we want to achieve.

The ratio that we want to achieve is 3:5, water to milk.

So, we want 3/8 water and 5/8 milk.

To answer the question, let's focus on the water, since, if 3/8 of the mixture is water, the other 5/8 will have be milk.

The mixes that we have are 25% water and 50% water. Let's express them in 8ths as well.

The first mix is 2/8 water. The second mix is 4/8 water.

We want 3/8 water, and since 3/8 is halfway between 2/8 and 4/8, this question is turning out to be pretty easy.

By using allegation, we can determine that we have to use equal quantities of the two mixtures.

The correct answer is (B).


Hi MartyTargetTestPrep,
Although the answer is B , are we getting 6 and 6 because I am getting a different equal proportion of the two mixtures .
Can you please confirm if the two milk cans are indeed mixed in 6:6 proportion.
Appreciate your help, Thank you.
_________________
- Stne
VP
VP
avatar
P
Joined: 07 Dec 2014
Posts: 1218
A milk vendor has 2 cans of milk. The first contains 25% water and the  [#permalink]

Show Tags

New post Updated on: 27 Jun 2019, 21:46
dharam44 wrote:
A milk vendor has 2 cans of milk. The first contains 25% water and the rest milk. The second contains 50% water. How much milk should he mix from each of the containers so as to get 12 litres of milk such that the ratio of water to milk is 3 : 5?

A. 4 litres, 8 litres
B. 6 litres, 6 litres
C. 5 litres, 7 litres
D. 7 litres, 5 litres
E 8 litres, 7litres


let x=total liters in first can
.75x+.5(12-x)=5/8*12→
x=6
12-6=6 liters in second can
6 liters, 6 liters
B

Originally posted by gracie on 19 Mar 2019, 14:18.
Last edited by gracie on 27 Jun 2019, 21:46, edited 1 time in total.
Target Test Prep Representative
User avatar
D
Status: Chief Curriculum and Content Architect
Affiliations: Target Test Prep
Joined: 24 Nov 2014
Posts: 627
GMAT 1: 800 Q51 V51
Re: A milk vendor has 2 cans of milk. The first contains 25% water and the  [#permalink]

Show Tags

New post 20 Mar 2019, 12:10
stne wrote:
Hi MartyTargetTestPrep,
Although the answer is B , are we getting 6 and 6 because I am getting a different equal proportion of the two mixtures .
Can you please confirm if the two milk cans are indeed mixed in 6:6 proportion.
Appreciate your help, Thank you.

Yes. Since the total resulting quantity is to be 12 liters, the equal parts have to be 6 liters and 6 liters.
_________________

Marty Murray

Chief Curriculum and Content Architect

Marty@targettestprep.com
TTP - Target Test Prep Logo
122 Reviews

5-star rated online GMAT quant
self study course

See why Target Test Prep is the top rated GMAT quant course on GMAT Club. Read Our Reviews

If you find one of my posts helpful, please take a moment to click on the "Kudos" button.

Intern
Intern
avatar
B
Joined: 12 Aug 2018
Posts: 3
Location: United States
GPA: 3.56
WE: Manufacturing and Production (Manufacturing)
Re: A milk vendor has 2 cans of milk. The first contains 25% water and the  [#permalink]

Show Tags

New post 21 Mar 2019, 07:13
1
MartyTargetTestPrep wrote:
To answer this question, let's match up the percentages of water in the two milk mixtures with the ratio that we want to achieve.

The ratio that we want to achieve is 3:5, water to milk.

So, we want 3/8 water and 5/8 milk.

To answer the question, let's focus on the water, since, if 3/8 of the mixture is water, the other 5/8 will have be milk.

The mixes that we have are 25% water and 50% water. Let's express them in 8ths as well.

The first mix is 2/8 water. The second mix is 4/8 water.

We want 3/8 water, and since 3/8 is halfway between 2/8 and 4/8, this question is turning out to be pretty easy.

By using allegation, we can determine that we have to use equal quantities of the two mixtures.

The correct answer is (B).



This explanation is excellent - I started doing this problem with algebra but this method is much quicker. However, the way I read the question there are no correct answers; the question states that the target mixture has 12L of milk in it. Is the problem written incorrectly? The author must be intending to have a final solution of 12L total - otherwise it would be impossible to obtain a solution with 12L of milk using only 12L from each container...
Director
Director
User avatar
V
Joined: 27 May 2012
Posts: 945
Re: A milk vendor has 2 cans of milk. The first contains 25% water and the  [#permalink]

Show Tags

New post 22 May 2019, 08:09
5e3 wrote:
MartyTargetTestPrep wrote:
To answer this question, let's match up the percentages of water in the two milk mixtures with the ratio that we want to achieve.

The ratio that we want to achieve is 3:5, water to milk.

So, we want 3/8 water and 5/8 milk.

To answer the question, let's focus on the water, since, if 3/8 of the mixture is water, the other 5/8 will have be milk.

The mixes that we have are 25% water and 50% water. Let's express them in 8ths as well.

The first mix is 2/8 water. The second mix is 4/8 water.

We want 3/8 water, and since 3/8 is halfway between 2/8 and 4/8, this question is turning out to be pretty easy.

By using allegation, we can determine that we have to use equal quantities of the two mixtures.

The correct answer is (B).



This explanation is excellent - I started doing this problem with algebra but this method is much quicker. However, the way I read the question there are no correct answers; the question states that the target mixture has 12L of milk in it. Is the problem written incorrectly? The author must be intending to have a final solution of 12L total - otherwise it would be impossible to obtain a solution with 12L of milk using only 12L from each container...


Hi 5e3,
You are Correct, it's 12L of milk and not 12L of total solution. From the question all we can tell is that equal proportions of both the cans have been used.
_________________
- Stne
Senior Manager
Senior Manager
User avatar
G
Joined: 12 Sep 2017
Posts: 308
Re: A milk vendor has 2 cans of milk. The first contains 25% water and the  [#permalink]

Show Tags

New post 27 Jun 2019, 17:14
Is it possible to answer it with weighted averages?
ISB School Moderator
User avatar
G
Joined: 08 Dec 2013
Posts: 615
Location: India
Concentration: Nonprofit, Sustainability
Schools: ISB '21
GMAT 1: 630 Q47 V30
WE: Operations (Non-Profit and Government)
Reviews Badge CAT Tests
Re: A milk vendor has 2 cans of milk. The first contains 25% water and the  [#permalink]

Show Tags

New post 27 Jun 2019, 17:30
1
1
dharam44 wrote:
A milk vendor has 2 cans of milk. The first contains 25% water and the rest milk. The second contains 50% water. How much milk should he mix from each of the containers so as to get 12 litres of milk such that the ratio of water to milk is 3 : 5?

A. 4 litres, 8 litres
B. 6 litres, 6 litres
C. 5 litres, 7 litres
D. 7 litres, 5 litres
E 8 litres, 7litres


Let us take x and 12-x lt. of milk, so

(5/8) = {.75x + .5(12-x)}/12
x=6
Intern
Intern
avatar
B
Joined: 23 Oct 2013
Posts: 43
Re: A milk vendor has 2 cans of milk. The first contains 25% water and the  [#permalink]

Show Tags

New post 28 Jun 2019, 07:49
12lite is the quantity of milk not water and milk mixture
Intern
Intern
avatar
B
Joined: 27 Feb 2019
Posts: 8
Concentration: General Management, Marketing
CAT Tests
Re: A milk vendor has 2 cans of milk. The first contains 25% water and the  [#permalink]

Show Tags

New post 28 Jun 2019, 09:42
Want to confirm if my solution (below) is right :

[ 75/100 x (milk in 1st can) + 50/100 x (milk in 2nd can) ] / [ x (total milk) + y (total water) ] = 12 / 19.2

after solving we get 2.4 x = 2.4 y -> x = y

Hence, 6 = 6. Option B
Senior Manager
Senior Manager
User avatar
B
Joined: 03 Sep 2018
Posts: 252
Location: Netherlands
GMAT 1: 710 Q48 V40
GMAT 2: 780 Q50 V49
GMAT 3: 760 Q49 V44
GPA: 4
Reviews Badge CAT Tests
Re: A milk vendor has 2 cans of milk. The first contains 25% water and the  [#permalink]

Show Tags

New post 26 Jul 2019, 01:20
allegation style:

((1/2)-(3/8))/((3/8)-(1/4))= 1/1 –> ratio 1:1
_________________
Good luck to you.
Intern
Intern
avatar
B
Joined: 12 Feb 2018
Posts: 13
Re: A milk vendor has 2 cans of milk. The first contains 25% water and the  [#permalink]

Show Tags

New post 02 Aug 2019, 23:43
Given, 12 litres final solution in the ratio of water to milk is 3:5.
So amount of water in 12L solution=4.5 L which is equal to 37.5%
now using the weighted average formula:

25---37.5--50

so, both are equally distant which is 1:1 ratio. Therefore, answer is 6 litres, 6 litres (B)
Intern
Intern
avatar
B
Joined: 12 Feb 2018
Posts: 13
Re: A milk vendor has 2 cans of milk. The first contains 25% water and the  [#permalink]

Show Tags

New post 02 Aug 2019, 23:50
sameeruce08 wrote:
12lite is the quantity of milk not water and milk mixture


Given that , final quantity of milk is 12 litres such that the ratio of water to milk is 3 :5--> we can take the final mixture as 12 litres.
GMAT Club Bot
Re: A milk vendor has 2 cans of milk. The first contains 25% water and the   [#permalink] 02 Aug 2019, 23:50
Display posts from previous: Sort by

A milk vendor has 2 cans of milk. The first contains 25% water and the

  new topic post reply Question banks Downloads My Bookmarks Reviews Important topics  





Powered by phpBB © phpBB Group | Emoji artwork provided by EmojiOne