Bunuel
A precious stone was accidentally dropped and broke into 3 stones of equal weight. The value of this type of stone is always proportional to the square of its weight. The 3 broken stones together are worth how much of the value of the original stone?
(A) 1/9
(B) 1/3
(C) 1
(D) 3
(E) 9
Given: A precious stone was accidentally dropped and broke into 3 stones of equal weight. The value of this type of stone is always proportional to the square of its weight.
Asked: The 3 broken stones together are worth how much of the value of the original stone?
A precious stone was accidentally dropped and broke into 3 stones of equal weight.
Let the weight of broken stone be x each
Weight of original stone = 3x
The value of this type of stone is always proportional to the square of its weight.
Value of each broken stone = \(kx^2\)
Value of 3 broken stones = \(3kx^2\)
Weight of original stone = 3x
The value of original stone =\(k (3x)^2 = 9kx^2\)
The 3 broken stones together are worth how much of the value of the original stone =\(\frac{3kx^2}{9kx^2} = \frac{1}{3}\)
IMO B