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# a solid cubial block has dimension as shown in the figure and the bloc

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Intern
Joined: 03 Jul 2015
Posts: 31
a solid cubial block has dimension as shown in the figure and the bloc [#permalink]

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02 Sep 2015, 06:45
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Question Stats:

68% (01:27) correct 32% (01:05) wrong based on 144 sessions

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a solid cubial block has dimension as shown in the figure and the block is to be cut in half as indicated be the shared region.
what is the total surface area of one of the resulting halves of the block ?

a. 27+9 root 2
b. 27
c. 27+ root 9
d. 28
e. 29+9 root 2

[Reveal] Spoiler: OA

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Current Student
Joined: 20 Mar 2014
Posts: 2652
Concentration: Finance, Strategy
Schools: Kellogg '18 (M)
GMAT 1: 750 Q49 V44
GPA: 3.7
WE: Engineering (Aerospace and Defense)
a solid cubial block has dimension as shown in the figure and the bloc [#permalink]

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02 Sep 2015, 07:54
anik19890 wrote:
a solid cubical block has dimension as shown in the figure and the block is to be cut in half as indicated be the shared region.
what is the total surface area of one of the resulting halves of the block ?

a. 27+9 root 2
b. 27
c. 27+ root 9
d. 28
e. 29+9 root 2

What question # is this from the official guide. Which official guide is this from? Official guide or the quant review? Please mention the complete thing.

You need to find the total area of the 2 halves created by the black plane added to the figure. Doing this, you will get 6 distinct regions that will be the

1. rectangle shaded in black with dimensions 3 $$\sqrt(2)$$ * 3
2. 2 slanted rectangles with dimensions 3*3
3. 2 Triangles, 1 at the top and 1 at the bottom with area : 0.5*3*3

Thus the total surface area of the 1 of the 2 halves created: 3 $$\sqrt(2)$$ * 3 + 2*0.5*3*3 + 2*3*3 = 9+18+9 $$\sqrt(2)$$ = 27+ 9 $$\sqrt(2)$$ . A is the correct answer.
Intern
Joined: 03 Jul 2015
Posts: 31
Re: a solid cubial block has dimension as shown in the figure and the bloc [#permalink]

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02 Sep 2015, 21:02
Engr2012 wrote:
anik19890 wrote:
a solid cubical block has dimension as shown in the figure and the block is to be cut in half as indicated be the shared region.
what is the total surface area of one of the resulting halves of the block ?

a. 27+9 root 2
b. 27
c. 27+ root 9
d. 28
e. 29+9 root 2

What question # is this from the official guide. Which official guide is this from? Official guide or the quant review? Please mention the complete thing.

You need to find the total area of the 2 halves created by the black plane added to the figure. Doing this, you will get 6 distinct regions that will be the

1. rectangle shaded in black with dimensions 3 $$\sqrt(2)$$ * 3
2. 2 slanted rectangles with dimensions 3*3
3. 2 Triangles, 1 at the top and 1 at the bottom with area : 0.5*3*3

Thus the total surface area of the 1 of the 2 halves created: 3 $$\sqrt(2)$$ * 3 + 2*0.5*3*3 + 2*3*3 = 9+18+9 $$\sqrt(2)$$ = 27+ 9 $$\sqrt(2)$$ . A is the correct answer.

thank you very much. but i can not understand one of the resulting halves. what does it mean to the structure?
Current Student
Joined: 20 Mar 2014
Posts: 2652
Concentration: Finance, Strategy
Schools: Kellogg '18 (M)
GMAT 1: 750 Q49 V44
GPA: 3.7
WE: Engineering (Aerospace and Defense)
Re: a solid cubial block has dimension as shown in the figure and the bloc [#permalink]

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02 Sep 2015, 21:13
anik19890 wrote:
Engr2012 wrote:
anik19890 wrote:
a solid cubical block has dimension as shown in the figure and the block is to be cut in half as indicated be the shared region.
what is the total surface area of one of the resulting halves of the block ?

a. 27+9 root 2
b. 27
c. 27+ root 9
d. 28
e. 29+9 root 2

What question # is this from the official guide. Which official guide is this from? Official guide or the quant review? Please mention the complete thing.

You need to find the total area of the 2 halves created by the black plane added to the figure. Doing this, you will get 6 distinct regions that will be the

1. rectangle shaded in black with dimensions 3 $$\sqrt(2)$$ * 3
2. 2 slanted rectangles with dimensions 3*3
3. 2 Triangles, 1 at the top and 1 at the bottom with area : 0.5*3*3

Thus the total surface area of the 1 of the 2 halves created: 3 $$\sqrt(2)$$ * 3 + 2*0.5*3*3 + 2*3*3 = 9+18+9 $$\sqrt(2)$$ = 27+ 9 $$\sqrt(2)$$ . A is the correct answer.

thank you very much. but i can not understand one of the resulting halves. what does it mean to the structure?

You still have not provided the question number of this question from the official guide.

Dividing into halves means that the shaded plane divides the cube into 2 equal shapes/halves having identical properties.
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Re: a solid cubial block has dimension as shown in the figure and the bloc [#permalink]

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04 Apr 2016, 00:55
Engr2012 wrote:
anik19890 wrote:
a solid cubical block has dimension as shown in the figure and the block is to be cut in half as indicated be the shared region.
what is the total surface area of one of the resulting halves of the block ?

a. 27+9 root 2
b. 27
c. 27+ root 9
d. 28
e. 29+9 root 2

You need to find the total area of the 2 halves created by the black plane added to the figure. Doing this, you will get 6 distinct regions that will be the

1. rectangle shaded in black with dimensions 3 $$\sqrt(2)$$ * 3
2. 2 slanted rectangles with dimensions 3*3
3. 2 Triangles, 1 at the top and 1 at the bottom with area : 0.5*3*3

Thus the total surface area of the 1 of the 2 halves created: 3 $$\sqrt(2)$$ * 3 + 2*0.5*3*3 + 2*3*3 = 9+18+9 $$\sqrt(2)$$ = 27+ 9 $$\sqrt(2)$$ . A is the correct answer.

May be Typo mistake.The distinct regions will be 5.
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Re: a solid cubial block has dimension as shown in the figure and the bloc [#permalink]

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04 Apr 2016, 14:27
Here is my approach => total surface area => Area of all the surfaces
=> 3^2+3^2+3^2 +3√18 => 27+9√2 => A is correct.
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Posts: 59
Re: a solid cubial block has dimension as shown in the figure and the bloc [#permalink]

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06 Apr 2018, 07:57
Re: a solid cubial block has dimension as shown in the figure and the bloc   [#permalink] 06 Apr 2018, 07:57
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