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Re: A straight line in the xy-plane has a slope of 2 and a y-intercept of [#permalink]
Equation of the line is Y = 2X + 2
=> X = (Y-2)/2
for Y = 500, we get X as 249.
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Re: A straight line in the xy-plane has a slope of 2 and a y-intercept of [#permalink]
Slope=\(\frac{(y1-y2)}{(x1-x2)}\)
2=\(\frac{(500-2)}{(x-0)}\)
2x=498
x=249

Answer: A
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Re: A straight line in the xy-plane has a slope of 2 and a y-intercept of [#permalink]
slope of 2 and a y-intercept of 2
y-coordinate is 500

y = 2x + 2
498 = 2x
x = 249


Answer:
A. 249
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Re: A straight line in the xy-plane has a slope of 2 and a y-intercept of [#permalink]
there can be 2 ways
first: either use the line equation y = mx+c ( y = 500 ; m = 2 ; c = 2)
second: use the way slope is calculated
that is m = (y2-y1)/(x2-x1) ( m = 2 , y2 = 500 ; y1 = 2 ; x2 = x ; x1 = 0)

OPTION A is the OA
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Re: A straight line in the xy-plane has a slope of 2 and a y-intercept of [#permalink]
Bunuel wrote:
A straight line in the xy-plane has a slope of 2 and a y-intercept of 2. On this line, what is the x-coordinate of the point whose y-coordinate is 500 ?

A. 249
B. 498
C. 676
D. 823
E. 1,002

Kudos for a correct solution.


Slope = y2-y1/x2-x1
at x= 0 y is 2 ; x=? when y=500
plug in the values
2=500-2/x-0
2=498/x
x=498/2=249

A is the answer
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A straight line in the xy-plane has a slope of 2 and a y-intercept of [#permalink]
A straight line in the xy-plane has a slope of 2 and a y-intercept of 2. On this line, what is the x-coordinate of the point whose y-coordinate is 500?

A. 249
B. 498
C. 676
D. 823
E. 1,002

Y= MX+C
500= 2X+2
X= 298

Answer: A
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A straight line in the xy-plane has a slope of 2 and a y-intercept of [#permalink]
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