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01 Sep 2015, 04:24
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A straight line in the xy-plane has a slope of 2 and a y-intercept of 2. On this line, what is the x-coordinate of the point whose y-coordinate is 500 ?
A. 249
B. 498
C. 676
D. 823
E. 1,002
A. 249
B. 498
C. 676
D. 823
E. 1,002
goldfinchmonster
Joined: 13 Apr 2015
Last visit: 13 Jan 2020
Posts: 60
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Given Kudos: 325
Concentration: General Management, Strategy
Schools: Jenkins FT'18 (S) Desautels '18 Iowa State '18 DeGroote (II) UConn FT "18 Alberta'18 Haskayne(Calgary)
GMAT 1: 620 Q47 V28
GPA: 3.25
WE:Project Management (Energy)
Schools: Jenkins FT'18 (S) Desautels '18 Iowa State '18 DeGroote (II) UConn FT "18 Alberta'18 Haskayne(Calgary)
GMAT 1: 620 Q47 V28
Posts: 60
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73
01 Sep 2015, 06:04
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Eq of line = Y = MX +C
M = 2,
C= 2
Y=2X + 2,
Substitute Y by 500 as given in question.
500=2X+2 , X = 249.
Or we can also use Slope formula M= Difference Bw Y Coordinates/ Difference Bw X Coordinates.
i.e.. 2= 2-500/0-X, X= 249.
Hence the answer is A...
M = 2,
C= 2
Y=2X + 2,
Substitute Y by 500 as given in question.
500=2X+2 , X = 249.
Or we can also use Slope formula M= Difference Bw Y Coordinates/ Difference Bw X Coordinates.
i.e.. 2= 2-500/0-X, X= 249.
Hence the answer is A...
01 Sep 2015, 07:37
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Equation of the line is Y = 2X + 2
=> X = (Y-2)/2
for Y = 500, we get X as 249.
=> X = (Y-2)/2
for Y = 500, we get X as 249.
