sayan640 wrote:
KarishmaB Can you please explain this "half rule" ?
MartyMurrayKinshook wrote:
Given: A student is forming numbers without repetition from the digits 1, 2, 3, 4 and 5 such that the digit in the unit's place is greater than the digit in the tenths' place.
Asked:How many numbers can the student form?
Total numbers that can ne formed using 1,2,3,4 and 5 without repition = 5! = 120
In half of the cases, Unit digit will be greater than the tenth digit.
IMO D
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We can think about this situation logically.
The student is creating all possible five-digit numbers with the digits 1, 2, 3, 4, and 5.
Of course, in some cases, the units digit will be greater than the tens digit. So, the question become, in what proportion of the cases?
Notice that the same digits can appear in the units digit and tens digit positions. For example, we could have 23451 and 23415. In other words, there's no difference between what can be a units digit and what can be a tens digit. Thus, in the cases of all possible such numbers, any given digit will appear equally as often in the tens digit position as in the units digit position.
Accordingly, the number of numbers such that the units digit is greater than the tens digit must be equal to the number of numbers such that the tens digit is greater than the units digit.
Thus, of all possible values, half would have a greater units digit.
What's more important than understanding all that is understanding that you could have figured that out yourself. There's no "half rule." All that's going on is that logic dictates that half the cases will satisfy the given criterion, and a great way to prepare for the GMAT is to reason through things like that so that when you have an opportunity to use logic to quickly find an answer when you take the test, you have practice in doing so.