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All of the stocks on the over the counter market are designated by eit
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27 Jan 2012, 13:35
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All of the stocks on the over the counter market are designated by either a 4 letter or a 5 letter code that is created by using the 26 letters of the alphabet. Which of the following gives the maximum number of different stocks that can be designated with these codes? A. \(2(26)^5\) B. \(26(26)^4\) C. \(27(26)^4\) D. \(26(26)^5\) E. \(27(26)^5\)
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Re: All of the stocks on the over the counter market are designated by eit
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27 Jan 2012, 13:38
All of the stocks on the over the counter market are designated by either a 4 letter or a 5 letter code that is created by using the 26 letters of the alphabet. Which of the following gives the maximum number of different stocks that can be desgnated with these codes?A. 2 (26)^5 B. 26(26)^4 C. 27(26)^4 D. 26(26)^5 E. 27(26)^5 In 4digit code {XXXX} each digit can take 26 values (as there are 26 letters), so total # of 4digits code possible is 26^4; The same for 5digit code {XXXXX} again each digit can take 26 values (26 letters), so total # of 5digits code possible is 26^5; Total: \(26^4+26^5=26^4(1+26)=27*26^4\). Answer: C.
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Re: All of the stocks on the over the counter market are designated by eit
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23 Jun 2012, 03:30
Important point to note here is that letters are not distinct , i.e we can have a code as aaaa or aaaaa for 4 or 5 letter words respectively. This question is similar to the question ifacodewordisdefinedtobeasequenceofdifferent126652.htmlIn which we have selected 4 letters from 10 and 5 letters from 10 but in this case the letters have to be distinct. so using \(P^{10}_{4}\) and \(P^{10}_{5}\) we get \(\frac{10!}{6!}\) and \(\frac{10!}{5!}\) But cannot we use the same logic here to select 4 letters from 26 or 5 letters from 26, why?... because the letters are not distinct ( letters can be repeated ) and we cannot use the general permutation formula when there is repetition . so we cannot use \(P^{26}_{4}\) \(+\) \(P^{26}_{5}\) if this question were each four letter code and 5 letter code are made of distinct elements then the answer, I think could be \(P^{26}_{4}\) \(+\) \(P^{26}_{5}\). 4 distinct letters can be selected from 26 or 5 distinct letters can be selected from 26 to make the 4 digit codes or 5 digit codes . so if \("distinct "\) is not mentioned then we automatically should assume that there can be repetitions . So in this question since no distinct word is mentioned , we can assume letters can we repeated to form the codes.Unlike the sum in the link above. Hope this will prevent many people from wondering why we are solving two very similar questions in two very different ways. like I myself was wondering for a while before this eureka moment if Anyone can add or verify or correct the reasoning that I have used It would certainly help.




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Re: All of the stocks on the over the counter market are designated by eit
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23 Jun 2012, 11:24
26^4+26^5 when we have "OR" word in sentence then when we add two posibilities and wen we have and word ..we multiple those posibilties 26^4(1+26)=27*26^4 so ans C..
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Re: All of the stocks on the over the counter market are designated by eit
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05 May 2013, 07:14
a4lettercodewordconsistsoflettersabandcifthe59065.htmlin the link posted above also contains a similar question of 4 letter code where A,B,C,A  two A's are repeating so we are using a formula 4 !/2 ! here also we are repeating the same letters tats why we are 26 ^4 for a letter code .But i should be 26 ^4 /4 ! na? please help me i am getting confused..When should i use the principle n!/ no# repeating letters and when i should not?



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Re: All of the stocks on the over the counter market are designated by eit
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05 May 2013, 09:00
skamal7 wrote: http://gmatclub.com/forum/a4lettercodewordconsistsoflettersabandcifthe59065.html
in the link posted above also contains a similar question of 4 letter code where A,B,C,A  two A's are repeating so we are using a formula 4 !/2 ! here also we are repeating the same letters tats why we are 26 ^4 for a letter code .But i should be 26 ^4 /4 ! na?
please help me i am getting confused..When should i use the principle n!/ no# repeating letters and when i should not? Here each letter can come any number of times. i.e a 4 letter code can be aaaa. But in the link provided by you, due to the restrictions imposed by the question, such liberty is not allowed there. There each letter should appear atleast once... leaving only 1 letter to repeat. Hence the difference. Hope you understood it



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Re: All of the stocks on the over the counter market are designated by eit
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25 Oct 2014, 11:44
Bunuel wrote: All of the stocks on the over the counter market are designated by either a 4 letter or a 5 letter code that is created by using the 26 letters of the alphabet. Which of the following gives the maximum number of different stocks that can be desgnated with these codes? A. 2 (26)^5 B. 26(26)^4 C. 27(26)^4 D. 26(26)^5 E. 27(26)^5
In 4digit code {XXXX} each digit can take 26 values (as there are 26 letters), so total # of 4digits code possible is 26^4;
The same for 5digit code {XXXXX} again each digit can take 26 values (26 letters), so total # of 5digits code possible is 26^5;
Total: \(26^4+26^5=26^4(1+26)=27*26^4\).
Answer: C. In this case, wouldn't there be a possibility of 2 tickets having the same code? If no, can you please explain! Thanks
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Re: All of the stocks on the over the counter market are designated by eit
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26 Oct 2014, 07:07
swanidhi wrote: Bunuel wrote: All of the stocks on the over the counter market are designated by either a 4 letter or a 5 letter code that is created by using the 26 letters of the alphabet. Which of the following gives the maximum number of different stocks that can be desgnated with these codes? A. 2 (26)^5 B. 26(26)^4 C. 27(26)^4 D. 26(26)^5 E. 27(26)^5
In 4digit code {XXXX} each digit can take 26 values (as there are 26 letters), so total # of 4digits code possible is 26^4;
The same for 5digit code {XXXXX} again each digit can take 26 values (26 letters), so total # of 5digits code possible is 26^5;
Total: \(26^4+26^5=26^4(1+26)=27*26^4\).
Answer: C. In this case, wouldn't there be a possibility of 2 tickets having the same code? If no, can you please explain! Thanks Which two codes could possibly be the same? It would be better to try with an easier example: try to count the number of 3 digit codes using 2 letters. You should get 2^3. For more practice, check Constructing Numbers, Codes and Passwords in our Speciall Questions Directory.
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Re: All of the stocks on the over the counter market are designated by eit
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09 Nov 2015, 00:41
Murmeltier wrote: All of the stocks on the over the counter market are designated by either a 4 letter or a 5 letter code that is created by using the 26 letters of the alphabet. Which of the following gives the maximum number of different stocks that can be desgnated with these codes?
A. 2 (26)^5 B. 26(26)^4 C. 27(26)^4 D. 26(26)^5 E. 27(26)^5 The first thing to note in these questions is whether we are allowed to repeat the variables or not. Since here, nothing about repetition is mentioned, we can safely assume that we can repeat the variables. 4 Letter Code: _ _ _ _ The first place can have 26 alphabets. The second place can also have 26 alphabets, since we can repeat. Similarly for 3rd and 4th. Hence total codes = 26*26*26*26 = \(26^4\) 5 Letter Code: _ _ _ _ _ By the above logic, Total codes = \(26^5\) Since we are asked the 4 letter codes OR the 5 letter codes, Total codes = \(26^4 + 26^5\) = \(26^4(26 + 1)\) = \(26^4*27\) Option C



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Re: All of the stocks on the over the counter market are designated by eit
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27 May 2017, 07:10
kilukilam wrote: All of the stock on the over counter market are designed by either 4 letter or 5 letter code that is created by using the 26 letter of the alphabet, which of the following given is the maximum number of different stock that can be designed with these code
a. 2 (26)^5 b. 26(26)^4 c. 27(26)^4 d. 26(26)^5 e. 27(26)^5 1. The maximum is when alphabets are repeating and ordering is important, which is n^r 2. For 4 letter codes it is 26^4 3. for 5 letter codes it is 26^5 4. Total is (26^4 + 26^5)= 26^4(1+26) = 27(26)^4
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Re: All of the stocks on the over the counter market are designated by eit
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31 May 2017, 11:23
amit2k9 wrote: 26^4 + 26^5
26^4(26+1)
C Can someone explain the step where we get (26 + 1). I follow up until that point. Unsure how we get that part.



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Re: All of the stocks on the over the counter market are designated by eit
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31 May 2017, 12:27
leeum wrote: amit2k9 wrote: 26^4 + 26^5
26^4(26+1)
C Can someone explain the step where we get (26 + 1). I follow up until that point. Unsure how we get that part. That's done by factoring out 26^4 from both terms: \(26^4+26^5=26^4+26^4*26=26^4(1+26)=27*26^4\). Hope it's clear.
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Re: All of the stocks on the over the counter market are designated by eit
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05 Jun 2017, 16:11
kilukilam wrote: All of the stock on the over counter market are designed by either 4 letter or 5 letter code that is created by using the 26 letter of the alphabet, which of the following given is the maximum number of different stock that can be designed with these code
a. 2 (26)^5 b. 26(26)^4 c. 27(26)^4 d. 26(26)^5 e. 27(26)^5 We need to determine the maximum number of different stocks that can be designated by a 4letter or 5letter code that is created by using the 26 letters of the alphabet. Number of 5letter codes: 26 x 26 x 26 x 26 x 26 = 26^5 Number of 4letter codes: 26 x 26 x 26 x 26 = 26^4 Since the stocks can be designated by a 4letter OR 5letter code, we must add our results together to determine the maximum number of codes that can be created. 26^5 + 26^4 = 26^4(26 + 1) = 26^4(27) Answer: C
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Re: All of the stocks on the over the counter market are designated by eit
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29 Jul 2018, 10:58
SravnaTestPrep wrote: kilukilam wrote: All of the stock on the over counter market are designed by either 4 letter or 5 letter code that is created by using the 26 letter of the alphabet, which of the following given is the maximum number of different stock that can be designed with these code
a. 2 (26)^5 b. 26(26)^4 c. 27(26)^4 d. 26(26)^5 e. 27(26)^5 1. The maximum is when alphabets are repeating and ordering is important, which is n^r 2. For 4 letter codes it is 26^4 3. for 5 letter codes it is 26^5 4. Total is (26^4 + 26^5)= 26^4(1+26) = 27(26)^4 t I don't understand the logic. If alphabets are repeating then there will be many similar codes.
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Re: All of the stocks on the over the counter market are designated by eit
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31 Jul 2018, 21:51
Bunuel wrote: All of the stocks on the over the counter market are designated by either a 4 letter or a 5 letter code that is created by using the 26 letters of the alphabet. Which of the following gives the maximum number of different stocks that can be desgnated with these codes? A. 2 (26)^5 B. 26(26)^4 C. 27(26)^4 D. 26(26)^5 E. 27(26)^5
In 4digit code {XXXX} each digit can take 26 values (as there are 26 letters), so total # of 4digits code possible is 26^4;
The same for 5digit code {XXXXX} again each digit can take 26 values (26 letters), so total # of 5digits code possible is 26^5;
Total: \(26^4+26^5=26^4(1+26)=27*26^4\).
Answer: C. I used the 26c4 multipled 26c5 and got the answer wrong. Whats the reason for this and when should we use this formula?
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Re: All of the stocks on the over the counter market are designated by eit
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01 Aug 2018, 00:47
Shbm wrote: Bunuel wrote: All of the stocks on the over the counter market are designated by either a 4 letter or a 5 letter code that is created by using the 26 letters of the alphabet. Which of the following gives the maximum number of different stocks that can be desgnated with these codes? A. 2 (26)^5 B. 26(26)^4 C. 27(26)^4 D. 26(26)^5 E. 27(26)^5
In 4digit code {XXXX} each digit can take 26 values (as there are 26 letters), so total # of 4digits code possible is 26^4;
The same for 5digit code {XXXXX} again each digit can take 26 values (26 letters), so total # of 5digits code possible is 26^5;
Total: \(26^4+26^5=26^4(1+26)=27*26^4\).
Answer: C. I used the 26c4 multipled 26c5 and got the answer wrong. Whats the reason for this and when should we use this formula? 26C4 gives the number of unordered groups of 4 different letters out of 26. For one, the order matters, {a, b, c, d} code is different from {b, a, c, d} code. Also, the letters could be repeated in the code, and 26C4 gives groups of 4 different letters. Finally, multiplying is wrong because 4letter codes and 5letter codes are different cases, so the number of possible codes should be added not multiplied. Hope it's clear.
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Re: All of the stocks on the over the counter market are designated by eit
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01 Aug 2018, 22:28
Bunuel wrote: Shbm wrote: Bunuel wrote: All of the stocks on the over the counter market are designated by either a 4 letter or a 5 letter code that is created by using the 26 letters of the alphabet. Which of the following gives the maximum number of different stocks that can be desgnated with these codes? A. 2 (26)^5 B. 26(26)^4 C. 27(26)^4 D. 26(26)^5 E. 27(26)^5
In 4digit code {XXXX} each digit can take 26 values (as there are 26 letters), so total # of 4digits code possible is 26^4;
The same for 5digit code {XXXXX} again each digit can take 26 values (26 letters), so total # of 5digits code possible is 26^5;
Total: \(26^4+26^5=26^4(1+26)=27*26^4\).
Answer: C. I used the 26c4 multipled 26c5 and got the answer wrong. Whats the reason for this and when should we use this formula? 26C4 gives the number of unordered groups of 4 different letters out of 26. For one, the order matters, {a, b, c, d} code is different from {b, a, c, d} code. Also, the letters could be repeated in the code, and 26C4 gives groups of 4 different letters. Finally, multiplying is wrong because 4letter codes and 5letter codes are different cases, so the number of possible codes should be added not multiplied. Hope it's clear. thanks bossman. are these type of questions generally placed in the 700 level category or can be a product of the 600700 level?
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Re: All of the stocks on the over the counter market are designated by eit
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01 Aug 2018, 22:44
Shbm wrote: Bunuel wrote: Shbm wrote: I used the 26c4 multipled 26c5 and got the answer wrong. Whats the reason for this and when should we use this formula? 26C4 gives the number of unordered groups of 4 different letters out of 26. For one, the order matters, {a, b, c, d} code is different from {b, a, c, d} code. Also, the letters could be repeated in the code, and 26C4 gives groups of 4 different letters. Finally, multiplying is wrong because 4letter codes and 5letter codes are different cases, so the number of possible codes should be added not multiplied. Hope it's clear. thanks bossman. are these type of questions generally placed in the 700 level category or can be a product of the 600700 level? It depends. This one for example, is 600700 level question. You can check different level combination's questions in our questions ban: https://gmatclub.com/forum/search.php?view=search_tagsHope it helps.
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