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We can approximate 15.1 to 15 and 19.9 to 20.

\(\frac{1500}{15}\) - \(\frac{1500}{20}\) = 100 - 75
Number of hours Cyclist B ride more than Cyclist A = 25 hours


So, option C.
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Bunuel
Cyclist A averages 19.9 miles per hour and Cyclist B averages 15.1 miles per hour. If each cycle is ridden 1,500 miles, approximately how many more hours will Cyclist B ride than Cyclist A?

A. 18
B. 20
C. 25
D. 30
E. 36

Given: Cyclist A averages 19.9 miles per hour and Cyclist B averages 15.1 miles per hour.

Asked: If each cycle is ridden 1,500 miles, approximately how many more hours will Cyclist B ride than Cyclist A?

Hours for Cyclist A = 1500/19.9 = 75 hours approx
Hours for Cyclist B = 1500/15.1 = 100 hours approx

Difference = 100 -75 = 25 hours

IMO C
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Bunuel
Cyclist A averages 19.9 miles per hour and Cyclist B averages 15.1 miles per hour. If each cycle is ridden 1,500 miles, approximately how many more hours will Cyclist B ride than Cyclist A?

A. 18
B. 20
C. 25
D. 30
E. 36

Video Explanation



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How could we solve this qq with relative speeds? We cannot because we do not know if they are cycling in the same direction or opposite direction?
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