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Re: Cyclist A averages 19.9 miles per hour and Cyclist B averages 15.1 mil [#permalink]
1500÷15.1=~99.3
1500÷19.9=~75.3
99.3-75.3=24
Nearest to the option C

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Re: Cyclist A averages 19.9 miles per hour and Cyclist B averages 15.1 mil [#permalink]
We can approximate 15.1 to 15 and 19.9 to 20.

\(\frac{1500}{15}\) - \(\frac{1500}{20}\) = 100 - 75
Number of hours Cyclist B ride more than Cyclist A = 25 hours


So, option C.
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Re: Cyclist A averages 19.9 miles per hour and Cyclist B averages 15.1 mil [#permalink]
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Bunuel wrote:
Cyclist A averages 19.9 miles per hour and Cyclist B averages 15.1 miles per hour. If each cycle is ridden 1,500 miles, approximately how many more hours will Cyclist B ride than Cyclist A?

A. 18
B. 20
C. 25
D. 30
E. 36


Video Explanation



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Cyclist A averages 19.9 miles per hour and Cyclist B averages 15.1 mil [#permalink]
How could we solve this qq with relative speeds? We cannot because we do not know if they are cycling in the same direction or opposite direction?
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Cyclist A averages 19.9 miles per hour and Cyclist B averages 15.1 mil [#permalink]
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