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Each Machine of type A has 3 steel parts and 2 chrome parts.

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Each Machine of type A has 3 steel parts and 2 chrome parts.  [#permalink]

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New post 14 Mar 2011, 14:31
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A
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Question Stats:

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Each Machine of type A has 3 steel parts and 2 chrome parts. Each machine of type B has 4 steel parts and 7 chrome parts. If a certain group of type A and type B machines has a total of 20 steel parts and 22 chrome parts, how many machines are in the group

A. 2
B. 3
C. 4
D. 6
E. 9
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Re: No. of machines  [#permalink]

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New post 14 Mar 2011, 14:57
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tonebeeze wrote:
Each Machine of type A has 3 steel parts and 2 chrome parts. Each machine of type B has 4 steel parts and 7 chrome parts. If a certain group of type A and type B machines has a total of 20 steel parts and 22 chrome parts, how many machines are in the group

a. 2
b. 3
c. 4
d. 6
e. 9


Given:
(i) \(3a+4b=20\) and (ii) \(2a+7b=22\), where \(a\) and \(b\) are # of type A and type B machines respectively.

Multiply (i) by 2 and (ii) by 3 and subtract: \((6a+21b)-(6a+8b)=66-40\) --> \(b=2\) --> \(a=4\) --> \(a+b=6\).

Answer: D.

Or you can notice that from (i) \(3a=20-4b\): 20 minus multiple of 4 to be a positive multiple of 3 \(b\) must be either 2 or 5 (which doesn't fit into the second equation) --> \(b=2\) --> \(a=4\) --> \(a+b=6\).

Answer: D.
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Re: No. of machines  [#permalink]

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New post 14 Mar 2011, 21:20
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Look at the below representation of the problem:
Steel Chrome total
A 3 2 20 >>no. of type A machines=20/5=4

B 4 7 22 >>no. of type B machines=22/11=2


So the answer is 6 i.e D.

Hope its clear .
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Re: No. of machines  [#permalink]

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New post 14 Mar 2011, 21:40
Let there be x # of machine A and y # of machine B

So we have :

3x + 4y = 20

4x + 7y = 22

=> y = 2 and x = (20 - 8)/3 = 4

So total = 6, answer is D.
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Re: No. of machines  [#permalink]

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New post 15 Mar 2011, 23:06
tonebeeze wrote:
Each Machine of type A has 3 steel parts and 2 chrome parts. Each machine of type B has 4 steel parts and 7 chrome parts. If a certain group of type A and type B machines has a total of 20 steel parts and 22 chrome parts, how many machines are in the group

a. 2
b. 3
c. 4
d. 6
e. 9



3a + 4b = 20 ......1

4a + 7b = 22.......2

solving (!) n (2)
b=2 a=4

thus total=6
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Re: No. of machines  [#permalink]

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New post 02 Jun 2012, 14:54
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Re: Each Machine of type A has 3 steel parts and 2 chrome parts.  [#permalink]

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New post 15 Dec 2018, 19:34
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Hi All,

We're told that each Machine of type A has 3 steel parts and 2 chrome parts, each machine of type B has 4 steel parts and 7 chrome parts and a certain group of type A and type B machines has a total of 20 steel parts and 22 chrome parts. We're asked for the total number of machines. This question can be approached in a number of different ways; the easiest approach would likely be to focus on the 'multiples' involved and play around a little bit with the basic Arithmetic.

While it might seem a bit weird, we can actually ignore whether the parts are 'steel' or 'chrome.' Each Machine A has a total of 5 parts and each Machine B has a total of 11 parts. The 'group' has a total of 42 parts, so we need to add a multiple of 5 to a multiple of 11 and end up with 42. The number 42 is relatively small, so there's likely just one way to get to that total... You might recognize that 11(2) = 22... meaning that there would be 42 - 22 = 20 parts remaining. Since 20 is a multiple of 5, we know that there would be 4 type B machines to go along with the 2 Type A machines. That's the only way to get to 42 total parts, so 4+2 = 6 must be the answer.

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Re: Each Machine of type A has 3 steel parts and 2 chrome parts.  [#permalink]

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New post 07 Jan 2019, 16:03
tonebeeze wrote:
Each Machine of type A has 3 steel parts and 2 chrome parts. Each machine of type B has 4 steel parts and 7 chrome parts. If a certain group of type A and type B machines has a total of 20 steel parts and 22 chrome parts, how many machines are in the group

A. 2
B. 3
C. 4
D. 6
E. 9


Let there be a type A machines and b type B machines:
Need: a+b

3a + 4b = 20
2a + 7b = 22

Solving those 2 equations: a=4, b=2
Therefore: 6
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Re: Each Machine of type A has 3 steel parts and 2 chrome parts.  [#permalink]

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New post 05 Aug 2019, 21:41
Alternate method:

We can form equations based on each component.

Steel:
Let x and y equal the number of machines of A and B respectively.

3x + 4y = 20

Test y=1 machine
3x+4(1)=20
3x = 16

this won't work since x is at least equal to 1 and is an integer (we are dealing with machines here)
Keep testing
3x + 4(2) = 20 --> 3x=12
3x + 4(3) = 20 --> 3x= 8
3x + 4(4) = 20 --> 3x= 4

The only mix that satisfies this equation is when y = 2 and x=4

We can test in the second equation but its unnecessary.
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Re: Each Machine of type A has 3 steel parts and 2 chrome parts.  [#permalink]

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New post 09 Aug 2019, 23:30
This seemed to me like an allegation/mixture problem but couldn't solve that way. Saw the solutions n realised that its a number property one. How do i differentiate between the two? Please help.

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Re: Each Machine of type A has 3 steel parts and 2 chrome parts.   [#permalink] 09 Aug 2019, 23:30
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