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From the starting point in a boat race, one competitor started to sail

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Bunuel
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From the starting point in a boat race, one competitor started to sail [#permalink] New post   08 Jun 2016, 10:02
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From the starting point in a boat race, one competitor started to sail north at a speed of 1.6 Km/h, the other competitor started to sail west at a speed of 1.2 Km/h. What is the distance in Km between the two competitors after 5 hours?

A. 10.
B. 12.
C. 12.5.
D. 14.
E. 15.4.
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From the starting point in a boat race, one competitor started to sail [#permalink] New post   08 Jun 2016, 10:20
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If one person is travelling to the West and another is travelling to the North, it means that they are moving away from each other creating two right triangle legs (there is a 90 degree angle between the distances they travel). The distance between them will be equal two the hypothenuse of that right triangle.

So now we jsut have to find how long are the legs of this triangle after 5 hours of travelling:
L1 = 1.6 km/h * 5h = 8 km
L2 = 1.2 km/h * 5h = 6 km

Hypothenuse = \(\sqrt{{8^2 + 6^2}\) or 10 km.


Answer: A
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Re: From the starting point in a boat race, one competitor started to sail [#permalink] New post   08 Jun 2016, 11:06
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Bunuel wrote:
From the starting point in a boat race, one competitor started to sail north at a speed of 1.6 Km/h, the other competitor started to sail west at a speed of 1.2 Km/h. What is the distance in Km between the two competitors after 5 hours?

A. 10.
B. 12.
C. 12.5.
D. 14.
E. 15.4.



After five hours,
At a 1.6km/h speed first competitor went=1.6*5=8km

and

At a 1.2/h speed second competitor went=1.2*5=6km

Since north and West are in \(90^{\circ}\) ,their Distance =\(\sqrt{8^2+6^2}\)=\(\sqrt{100}\)=10

Correct answer A
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Re: From the starting point in a boat race, one competitor started to sail [#permalink] New post   08 Jun 2016, 10:27
Bunuel wrote:
From the starting point in a boat race, one competitor started to sail north at a speed of 1.6 Km/h, the other competitor started to sail west at a speed of 1.2 Km/h. What is the distance in Km between the two competitors after 5 hours?

A. 10.
B. 12.
C. 12.5.
D. 14.
E. 15.4.


Both competitors are sailing making angle of 90 degrees.

After 5 hrs one competitor will cover a distance of = 1.6 *5= 8 KM
And, other competitor will cover a distance of = 1.2*5= 6KM

distance between them after 5 hrs = (8^2+ 6^2)^1/2= 10 KM

A is the answer
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Re: From the starting point in a boat race, one competitor started to sail [#permalink] New post   08 Jun 2016, 10:34
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Bunuel wrote:
From the starting point in a boat race, one competitor started to sail north at a speed of 1.6 Km/h, the other competitor started to sail west at a speed of 1.2 Km/h. What is the distance in Km between the two competitors after 5 hours?

A. 10.
B. 12.
C. 12.5.
D. 14.
E. 15.4.


Hi
the triangle formed is right angle triangle with two sides 1.2 *5 = 3*0.4 *5 and 4*0.4* 5 and these are in the ratio 3:4..
so we have a triangle in the ratio 3:4:5....and we have to find the HYP0 or ratio 5...
so it is \(5* 1.2 *\frac{5}{3} = 5*0.4*5 = 10\)
A
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Re: From the starting point in a boat race, one competitor started to sail [#permalink] New post   09 Jun 2016, 03:52
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Bunuel wrote:
From the starting point in a boat race, one competitor started to sail north at a speed of 1.6 Km/h, the other competitor started to sail west at a speed of 1.2 Km/h. What is the distance in Km between the two competitors after 5 hours?

A. 10.
B. 12.
C. 12.5.
D. 14.
E. 15.4.


The two competitors are sailing in perpendicular lines.
Hence the distance between the two would be the hypotenuse of the triangle formed.

Distance by competitor 1 = 1.6*5 = 8km
Distance by competitor 2 = 1.2*5 = 6km

Distance between the both = (64 + 36)^(1/2) = 10km

Correct Option: A
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From the starting point in a boat race, one competitor started to sail [#permalink] New post   23 Aug 2016, 13:11
Classic pythagoras problem using a bit of time-speed-distance
the person travelling north at rate of 1.6 km/hr for a period of 5 hrs travels 8 kms
the person travelling west at rate of 1.2 km/hr for a period of 5 hrs travels 6 kms

Distance between them can be given by \(8^2\) \(+\) \(6 ^2\) \(=\) \(10 ^2\)
taking positive square roots
so distance = 10 kms
Correct answer -\(A\)
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Re: From the starting point in a boat race, one competitor started to sail [#permalink] New post   06 Dec 2020, 02:34
Hello from the GMAT Club BumpBot!

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Re: From the starting point in a boat race, one competitor started to sail [#permalink]
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