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How many zeros are the end of ?

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How many zeros are the end of ?  [#permalink]

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New post 15 Nov 2012, 07:23
1
15
00:00
A
B
C
D
E

Difficulty:

  15% (low)

Question Stats:

74% (01:14) correct 26% (01:16) wrong based on 1276 sessions

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How many zeros are at the end of 380! ?

(A) 90
(B) 91
(C) 94
(D) None
(E) 95

In order to find the number of zeros we have to find out the number of 5's and 2's , because no. of 5's will be less then the number of 2's ..

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How many zeros are the end of ?  [#permalink]

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New post 15 Nov 2012, 07:41
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vomhorizon wrote:
How many zeros are the end of 380! ?

(A) 90
(B) 91
(C) 94
(D) None
(E) 95


380! has \(\frac{380}{5}+\frac{380}{5^2}+\frac{380}{5^3}=76+15+3=94\) trailing zeros ( take only the quotient into account).

Answer: C.

For more on trailing zeros check: everything-about-factorials-on-the-gmat-85592.html

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Hope it helps.
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Re: How many zeros are the end of ?  [#permalink]

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New post 10 Sep 2017, 05:25
380/5 = 76

76/5= 15

15/5= 3

Sum of these quotients. Answer C
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Re: How many zeros are the end of ?  [#permalink]

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New post 13 Jan 2018, 15:57
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rnz wrote:


This is explained in highlighted post.
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Re: How many zeros are the end of ?  [#permalink]

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New post 14 Jan 2018, 09:25
vomhorizon wrote:
How many zeros are at the end of 380! ?

(A) 90
(B) 91
(C) 94
(D) None
(E) 95

In order to find the number of zeros we have to find out the number of 5's and 2's , because no. of 5's will be less then the number of 2's ..


\(\frac{380}{5} = 76\)
\(\frac{76}{5} = 15\)
\(\frac{15}{5} = 3\)

So, the total number of 0's in the end of 380! is 76+15+ 3 = 94 , answer will be (C)
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Re: How many zeros are the end of ? &nbs [#permalink] 14 Jan 2018, 09:25
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