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vomhorizon
How many zeros are at the end of 380! ?

(A) 90
(B) 91
(C) 94
(D) None
(E) 95

In order to find the number of zeros we have to find out the number of 5's and 2's , because no. of 5's will be less then the number of 2's ..

\(\frac{380}{5} = 76\)
\(\frac{76}{5} = 15\)
\(\frac{15}{5} = 3\)

So, the total number of 0's in the end of 380! is 76+15+ 3 = 94 , answer will be (C)
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vomhorizon
How many zeros are the end of 380! ?

(A) 90
(B) 91
(C) 94
(D) None
(E) 95

380! has \(\frac{380}{5}+\frac{380}{5^2}+\frac{380}{5^3}=76+15+3=94\) trailing zeros ( take only the quotient into account).

Answer: C.

Hope it helps.


Is there any good tip to have the result of the division (380/5^2=15) in an easier way?

Thanks for any response.
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vomhorizon
How many zeros are at the end of 380! ?

(A) 90
(B) 91
(C) 94
(D) None
(E) 95

In order to find the number of zeros we have to find out the number of 5's and 2's , because no. of 5's will be less then the number of 2's ..

The basic formula for that is: \(\frac{380}{5}+\frac{380}{5^2}+\frac{380}{5^3}; 5^4 \)is larger than 380.

\(=76+15+3=94\)

The answer is C.

Another way, considering the basic formula:
380/5=76
76/5=15
15/5=3

76+15+3=94
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\(\frac{380}{5}+\frac{380}{25}+\frac{380}{125}\)
=76+15+3 (not considering the remainders)
=94
Answer: C
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