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If 25 squares, each painted one of the solid colours of red, green, ye [#permalink]
E

Let the first square be Blue, second be red, third be blue, fourth as yellow, fifth as blue and sixth as green. We have 3 blue square.
Then let the 7th square be blue. And every alternate square (odd numbers) be blue. Hence the number of blue square is 3+(25-7)/2+1 =13.
This is the arrangement that gives the maximum blue squares as per the given criteria.


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If 25 squares, each painted one of the solid colours of red, green, ye [#permalink]
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