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If 4<(7x)/3, which of the following must be true?
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12 Mar 2014, 00:07
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If \(4<\frac{7x}{3}\), which of the following must be true? I. \(5<x\) II. \(x+3>2\) III. \((x+5)\) is positive (A) II only (B) III only (C) I and II only (D) II and III only (E) I, II and III
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Re: If 4<(7x)/3, which of the following must be true?
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12 Mar 2014, 00:10
SOLUTIONIf 4<(7x)/3, which of the following must be true?
I. 5<x II. x+3>2 III. (x+5) is positive(A) II only (B) III only (C) I and II only (D) II and III only (E) I, II and III Note that we are asked to determine which MUST be true, not could be true. \(4<\frac{7x}{3}\) > \(12<7x\) > \(x<5\). So we know that \(x<5\), it's given as a fact. Now, taking this info we should find out which of the following inequalities will be true OR which of the following inequalities will be true for the range \(x<5\). Basically the question asks: if \(x<5\) which of the following is true? I. \(5<x\) > not true as \(x<5\). II. \(x+3>2\), this inequality holds true for 2 cases, (for 2 ranges): 1. when \(x+3>2\), so when \(x>1\) or 2. when \(x3>2\), so when \(x<5\). We are given that second range is true (\(x<5\)), so this inequality holds true. Or another way: ANY \(x\) from the range \(x<5\) (5.1, 6, 7, ...) will make \(x+3>2\) true, so as \(x<5\), then \(x+3>2\) is always true. III. \((x+5)>0\) > \(x<5\) > true. Answer: D.
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Re: If 4<(7x)/3, which of the following must be true?
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12 Mar 2014, 00:56
If 4<(7x)/3, which of the following must be true?
I. 5<x II. x+3>2 III. (x+5) is positive
(A) II only (B) III only (C) I and II only (D) II and III only (E) I, II and III
Sol:The given expression can be 4<(7x)/3 (multiply by 3) we get 12<7x or x<5 St 1 can be ruled out St 3 must be true So Option A,C and E can be ruled out Consider st 2 x+3>2 When x+3 >/ 0 then x+3= x+3 and also x>/3 or x+3> 2 or x>1 but our condition is x>/3 so x> 1 (because if x>1 then x surely is greater than 3) When x+3 <0 then x+3= (x+3) and the st2 equation becomes x+3<2 or x<5 and thus x<5 (because of x<5 then x <3 as well) So we have x >1 or x<5 > In this range the St 2 will hold good. But we are given that x<5 thus St 2 is true Ans is D....
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Re: If 4<(7x)/3, which of the following must be true?
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12 Mar 2014, 07:12
Solved the equation to get x < 5 As the question says must be true, it means that for any below 5 the statements have to hold true. So just assumed it to be 6 in every statement
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Re: If 4<(7x)/3, which of the following must be true?
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12 Mar 2014, 08:42
Answer is D As statement 1 can be ruled out as from question statementx<5 statement 2 holds ok as modulus of lx+3l>2 : as from question statementx<5 staement 3 is also correct as from question statementx<5 therefore multiplication of 2 negative term is positive



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Re: If 4<(7x)/3, which of the following must be true?
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04 Jan 2015, 05:49
Bunuel wrote: SOLUTION
If 4<(7x)/3, which of the following must be true?
I. 5<x II. x+3>2 III. (x+5) is positive
(A) II only (B) III only (C) I and II only (D) II and III only (E) I, II and III
Note that we are asked to determine which MUST be true, not could be true.
\(4<\frac{7x}{3}\) > \(12<7x\) > \(x<5\). So we know that \(x<5\), it's given as a fact. Now, taking this info we should find out which of the following inequalities will be true OR which of the following inequalities will be true for the range \(x<5\).
Basically the question asks: if \(x<5\) which of the following is true?
I. \(5<x\) > not true as \(x<5\).
II. \(x+3>2\), this inequality holds true for 2 cases, (for 2 ranges): 1. when \(x+3>2\), so when \(x>1\) or 2. when \(x3>2\), so when \(x<5\). We are given that second range is true (\(x<5\)), so this inequality holds true.
Or another way: ANY \(x\) from the range \(x<5\) (5.1, 6, 7, ...) will make \(x+3>2\) true, so as \(x<5\), then \(x+3>2\) is always true.
III. \((x+5)>0\) > \(x<5\) > true.
Answer: D. For (2): X could be a positive number or a negative number, if x is a negative number than solving inequality would result into X < 5 which is true because it is the exact same inequality which has been given in the question. But if x would be positive that solving inequality would result into x >1 which would make the option (2) not true. So in other words when x is negative than statement (2) is true but when x is positive than statement (2) is not true. So statement (2) is not ALWAYS true. Can you please tell me why im unable to get the right answer? what is flaw in my reasoning?



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Re: If 4<(7x)/3, which of the following must be true?
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05 Jan 2015, 03:28
mulhinmjavid wrote: Bunuel wrote: SOLUTION
If 4<(7x)/3, which of the following must be true?
I. 5<x II. x+3>2 III. (x+5) is positive
(A) II only (B) III only (C) I and II only (D) II and III only (E) I, II and III
Note that we are asked to determine which MUST be true, not could be true.
\(4<\frac{7x}{3}\) > \(12<7x\) > \(x<5\). So we know that \(x<5\), it's given as a fact. Now, taking this info we should find out which of the following inequalities will be true OR which of the following inequalities will be true for the range \(x<5\).
Basically the question asks: if \(x<5\) which of the following is true?
I. \(5<x\) > not true as \(x<5\).
II. \(x+3>2\), this inequality holds true for 2 cases, (for 2 ranges): 1. when \(x+3>2\), so when \(x>1\) or 2. when \(x3>2\), so when \(x<5\). We are given that second range is true (\(x<5\)), so this inequality holds true.
Or another way: ANY \(x\) from the range \(x<5\) (5.1, 6, 7, ...) will make \(x+3>2\) true, so as \(x<5\), then \(x+3>2\) is always true.
III. \((x+5)>0\) > \(x<5\) > true.
Answer: D. For (2): X could be a positive number or a negative number, if x is a negative number than solving inequality would result into X < 5 which is true because it is the exact same inequality which has been given in the question. But if x would be positive that solving inequality would result into x >1 which would make the option (2) not true. So in other words when x is negative than statement (2) is true but when x is positive than statement (2) is not true. So statement (2) is not ALWAYS true. Can you please tell me why im unable to get the right answer? what is flaw in my reasoning? It should be other way around. To elaborate more. Question uses the same logic as in the examples below:If \(x=5\), then which of the following must be true about \(x\):A. x=3 B. x^2=10 C. x<4 D. x=1 E. x>10 Answer is E (x>10), because as x=5 then it's more than 10. Or: If \(1<x<10\), then which of the following must be true about \(x\):A. x=3 B. x^2=10 C. x<4 D. x=1 E. x<120 Again answer is E, because ANY \(x\) from \(1<x<10\) will be less than 120 so it's always true about the number from this range to say that it's less than 120. Or: If \(1<x<0\) or \(x>1\), then which of the following must be true about \(x\):A. x>1 B. x>1 C. x<1 D. x=1 E. x^2>1 As \(1<x<0\) or \(x>1\) then ANY \(x\) from these ranges would satisfy \(x>1\). So B is always true. \(x\) could be for example 1/2, 3/4, or 10 but no matter what \(x\) actually is it's IN ANY CASE more than 1. So we can say about \(x\) that it's more than 1. On the other hand for example A is not always true as it says that \(x>1\), which is not always true as \(x\) could be 1/2 and 1/2 is not more than 1. Hope it's clear.
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Re: If 4<(7x)/3, which of the following must be true?
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14 May 2015, 01:03
Bunuel wrote: mulhinmjavid wrote: Bunuel wrote: SOLUTION
If 4<(7x)/3, which of the following must be true?
I. 5<x II. x+3>2 III. (x+5) is positive
(A) II only (B) III only (C) I and II only (D) II and III only (E) I, II and III
Note that we are asked to determine which MUST be true, not could be true.
\(4<\frac{7x}{3}\) > \(12<7x\) > \(x<5\). So we know that \(x<5\), it's given as a fact. Now, taking this info we should find out which of the following inequalities will be true OR which of the following inequalities will be true for the range \(x<5\).
Basically the question asks: if \(x<5\) which of the following is true?
I. \(5<x\) > not true as \(x<5\).
II. \(x+3>2\), this inequality holds true for 2 cases, (for 2 ranges): 1. when \(x+3>2\), so when \(x>1\) or 2. when \(x3>2\), so when \(x<5\). We are given that second range is true (\(x<5\)), so this inequality holds true.
Or another way: ANY \(x\) from the range \(x<5\) (5.1, 6, 7, ...) will make \(x+3>2\) true, so as \(x<5\), then \(x+3>2\) is always true.
III. \((x+5)>0\) > \(x<5\) > true.
Answer: D. For (2): X could be a positive number or a negative number, if x is a negative number than solving inequality would result into X < 5 which is true because it is the exact same inequality which has been given in the question. But if x would be positive that solving inequality would result into x >1 which would make the option (2) not true. So in other words when x is negative than statement (2) is true but when x is positive than statement (2) is not true. So statement (2) is not ALWAYS true. Can you please tell me why im unable to get the right answer? what is flaw in my reasoning? It should be other way around. To elaborate more. Question uses the same logic as in the examples below:If \(x=5\), then which of the following must be true about \(x\):A. x=3 B. x^2=10 C. x<4 D. x=1 E. x>10 Answer is E (x>10), because as x=5 then it's more than 10. Or: If \(1<x<10\), then which of the following must be true about \(x\):A. x=3 B. x^2=10 C. x<4 D. x=1 E. x<120 Again answer is E, because ANY \(x\) from \(1<x<10\) will be less than 120 so it's always true about the number from this range to say that it's less than 120. Or: If \(1<x<0\) or \(x>1\), then which of the following must be true about \(x\):A. x>1 B. x>1 C. x<1 D. x=1 E. x^2>1 As \(1<x<0\) or \(x>1\) then ANY \(x\) from these ranges would satisfy \(x>1\). So B is always true. \(x\) could be for example 1/2, 3/4, or 10 but no matter what \(x\) actually is it's IN ANY CASE more than 1. So we can say about \(x\) that it's more than 1. On the other hand for example A is not always true as it says that \(x>1\), which is not always true as \(x\) could be 1/2 and 1/2 is not more than 1. Hope it's clear. I still don't understand the application of this, to the question. Sure, I understand that if x = 5 its > 10. But, here, we get two different cases. Solving the question stem we get x < 5. In "II" we have that x is either x < 5 or x > 1. If I plug in a value where x > 1. Say x = 3. The equation doesn't hold? We get 4 < (73)/3 > 12 < 4. Not true? How can this be a valid answer choice then Edit: Don't know if this is how you should go about doing it, correct me if I'm wrong:
If we have \(x < 5.\)
Plugging in a value < 5, say 6 into II: \(6+3 > 2\). This holds true, aka sufficient



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Re: If 4<(7x)/3, which of the following must be true?
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14 May 2015, 02:17
Quote: I still don't understand the application of this, to the question. Sure, I understand that if x = 5 its > 10.
But, here, we get two different cases. Solving the question stem we get x < 5.
In "II" we have that x is either x < 5 or x > 1. If I plug in a value where x > 1. Say x = 3. The equation doesn't hold?
We get 4 < (73)/3 > 12 < 4. Not true?
How can this be a valid answer choice then
Edit: Don't know if this is how you should go about doing it, correct me if I'm wrong:
If we have \(x < 5.\)
Plugging in a value < 5, say 6 into II: \(6+3 > 2\). This holds true, aka sufficient Hi erikvm, Let me explain the solution to you using the representation on number line. We need to evaluate if for every value in the range of the question statement i.e. x < 5, do the statements hold true. Refer the below diagram for the range given to us in the question & the other statements: Question Statement: The question statement gives us the range as x < 5. We need to see for every value of x < 5, are the inequality in the statements true. StatementI: StI gives us the range as x > 5. We see that this range does not hold true for any value of x. Hence, it can't be true. StatementII: StII gives us the range as x > 1 or x < 5. We see that for every value of x < 5 (i.e. the inequality in the question statement), we can write x +3 > 2 holds. Hence this is a must be true statement. StatementIII: StIII gives us the range as x < 5 which is nothing but the range in question statement. Hence this is a must be true statement. Therefore, stII & III are true for every value of x < 5 and hence must be true statements. Hope its clear Regards Harsh
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Re: If 4<(7x)/3, which of the following must be true?
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19 May 2015, 06:12
Thanks, I'm just abit confused about the whole "must be true". I know how absolute values work, but \(x+3 > 2\) provides me with 2 different values for x, so I just assumed that this statement was not true because we have two different possibilities for X



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Re: If 4<(7x)/3, which of the following must be true?
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19 May 2015, 22:47
erikvm wrote: Thanks, I'm just abit confused about the whole "must be true". I know how absolute values work, but \(x+3 > 2\) provides me with 2 different values for x, so I just assumed that this statement was not true because we have two different possibilities for X Actually, \(x+3 > 2\) provides you infinite values of x. It gives you two ranges: x < 5 OR x > 1. The inequality implies that distance of x from 3 is more than 2. So x can lie to the right of 1 or to the left of 5. (Draw it on a number line to see). Hence you get two ranges: x < 5 OR x > 1 The question gives you that x < 5. So x will take any value less than 5. When it does, for all such values \(x+3 > 2\) will always be true because it holds for all values such that x < 5. It holds for some more values too (x > 1) but we don't care about those. All values that x can take in our question, for those \(x+3 > 2\) will always work. So \(x+3 > 2\) must be true.
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Re: If 4<(7x)/3, which of the following must be true?
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04 May 2016, 06:26
Why can statement 1 not be true? if we consider x to be negative, the question stem gives us x>5 as a possible result of x.
Thank you.



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Re: If 4<(7x)/3, which of the following must be true?
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04 May 2016, 06:31
BobbyAssassinCross wrote: Why can statement 1 not be true? if we consider x to be negative, the question stem gives us x>5 as a possible result of x.
Thank you. Hi BobbyAssassinCross, look at the highlighted portion.. initially you start with x as ive and then get a +ive value for x as x>5.. so contradictory solution.. hence NOT possible
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Re: If 4<(7x)/3, which of the following must be true?
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03 Jan 2018, 23:46
Hi Bunuel can we think of 2nd statement as a Big set of ( 0,1,2,3,4,5 and also 6,7,8...) and what we need for must be true is a subset (6, 7, 8...) ? Is this correct?
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Re: If 4<(7x)/3, which of the following must be true?
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04 Jan 2018, 01:09
Prashant10692 wrote: Hi Bunuel can we think of 2nd statement as a Big set of ( 0,1,2,3,4,5 and also 6,7,8...) and what we need for must be true is a subset (6, 7, 8...) ? Is this correct? We are not given that x is necessarily an integer. For x + 3 > 2 to hold true, x < 5 or x > 1 must be true. We know that x < 5, so x + 3 > 2, will be true. Check other similar questions from Trickiest Inequality Questions Type: Confusing Ranges (part of our Special Questions Directory).
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Re: If 4<(7x)/3, which of the following must be true?
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06 Feb 2018, 15:48
Bunuel wrote: The Official Guide For GMAT® Quantitative Review, 2ND EditionIf 4<(7x)/3, which of the following must be true? I. 5<x II. x+3>2 III. (x+5) is positive (A) II only (B) III only (C) I and II only (D) II and III only (E) I, II and III First, let's deal with the given inequality. 4 < (7x)/3 Multiply both sides by 3 to get: 12 < 7  x Add x to both sides: x + 12 < 7 Subtract 12 from both sides to get: x < 5So, if x < 5, which of the following statements MUST be true? Aside: When dealing with "MUST be true" questions, we can eliminate a statement if we can find an instance where it is not true.I. 5 < x (MUST this be true?) No! If x < 5, then it could be the case that x = 7, and 7 is NOT greater than 5 So, statement I need NOT be true. II. x+3 > 2 (MUST this be true?) The answer is Yes. Here's why: IMPORTANT CONCEPT: x  k represents the DISTANCE between x and k on the number line. So, for example, we can think of 4  7 as the distance between 4 and 7 on the number line. Notice that 4  7 = 3 = 3, and 3 is indeed the distance between 4 and 7 on the number line. Now let's examine x+3 We can rewrite this as x  (3) This represents the DISTANCE between x and 3 on the number line. So, the inequality x(3) > 2 is stating that the DISTANCE between x and 3 on the number line is GREATER THAN 2 Well, since we're told that x < 5, we can be certain that the DISTANCE between x and 3 on the number line is definitely GREATER THAN 2 [If you're not convinced, sketch a number line, and place a big dot at 3. Then choose ANY value for x such that x < 5. You'll see that the distance between x and 3 is greater than 2] So, statement II MUST be true. III. (x+5) is positive This is the same as saying (x+5) > 0 (MUST this be true?) The answer is Yes. Here's why: We're told that x < 5If we add 5 to both sides we get x+5 < 0 Now, if we multiply both sides by 1, we get (x+5) > 0[aside: notice that, since I multiplied both sides by a negative value, I reversed the direction of the inequality] As we can see, statement III MUST be true. Answer: D Cheers, Brent
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Re: If 4<(7x)/3, which of the following must be true?
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12 Feb 2018, 12:02
Bunuel wrote: The Official Guide For GMAT® Quantitative Review, 2ND EditionIf 4<(7x)/3, which of the following must be true? I. 5<x II. x+3>2 III. (x+5) is positive (A) II only (B) III only (C) I and II only (D) II and III only (E) I, II and III Simplifying the given inequality we have: 4 < (7  x)/3 12 < 7  x 5 < x 5 > x Since x is less than 5, we see that x+3 > 2. Also, since x < 5, we see that x + 5 will always be negative and thus (x+5) will always be positive. Answer: D
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Re: If 4<(7x)/3, which of the following must be true?
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13 Dec 2019, 00:39
Bunuel wrote: Prashant10692 wrote: Hi Bunuel can we think of 2nd statement as a Big set of ( 0,1,2,3,4,5 and also 6,7,8...) and what we need for must be true is a subset (6, 7, 8...) ? Is this correct? We are not given that x is necessarily an integer. For x + 3 > 2 to hold true, x < 5 or x > 1 must be true. We know that x < 5, so x + 3 > 2, will be true. Check other similar questions from Trickiest Inequality Questions Type: Confusing Ranges (part of our Special Questions Directory). Hi Bunuel : i had a question about the above reasoning. From statement II we get two ranges i.e. x< 5 (which conforms to the inequality given in the question stem) and x>1 which is a new one based on the option. My observations here is that despite two ranges of X coming off option II, we can only take the one that conforms to the constraint (x<5) and see if the entire expression ( x + 3 > 2 ) holds true, which it does when we consider any value of X <5 . Is this correct ? Thanks & Regards, Deeuce



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Re: If 4<(7x)/3, which of the following must be true?
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13 Dec 2019, 00:48
deeeuce wrote: Bunuel wrote: Prashant10692 wrote: Hi Bunuel can we think of 2nd statement as a Big set of ( 0,1,2,3,4,5 and also 6,7,8...) and what we need for must be true is a subset (6, 7, 8...) ? Is this correct? We are not given that x is necessarily an integer. For x + 3 > 2 to hold true, x < 5 or x > 1 must be true. We know that x < 5, so x + 3 > 2, will be true. Check other similar questions from Trickiest Inequality Questions Type: Confusing Ranges (part of our Special Questions Directory). Hi Bunuel : i had a question about the above reasoning. From statement II we get two ranges i.e. x< 5 (which conforms to the inequality given in the question stem) and x>1 which is a new one based on the option. My observations here is that despite two ranges of X coming off option II, we can only take the one that conforms to the constraint (x<5) and see if the entire expression ( x + 3 > 2 ) holds true, which it does when we consider any value of X <5 . Is this correct ? Thanks & Regards, Deeuce Yes. We are given that x < 5 and the question asks: is x + 3 > 2 true? For any x which is more than 5, x + 3 > 2 IS true. So, x + 3 > 2 must be true given that x < 5.
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Re: If 4<(7x)/3, which of the following must be true?
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15 Dec 2019, 09:17
Bunuel wrote: If 4<(7x)/3, which of the following must be true?
I. 5<x II. x+3>2 III. (x+5) is positive
(A) II only (B) III only (C) I and II only (D) II and III only (E) I, II and III First, solve the quetion stem instead of going through the options first. From question stem, 4 < [7x][/3] 12<7x x< 5 Try to match this value with the options given in the question now. I. 5<x : This could never be true because we already have a range which is x< 5II. x+3>2 : Do not be fearful of the absolute value bars. A very simple way to test this inequality is to test with some values first, in case you want to avoid the tacky algebra. Because x < 5, try x = 6, 6+3 = 3. try x = 12, 12+3 = 9 In either case, the answer is >2. Therefore, this ineuqality appears to be holding true universally. III. (x+5) is positive: Because x < 5, try x = 6, (6+5) = 1. try x = 12, (12+3) = 9 In either case, the answer is positive. negative * negative is always positive. Therefore, this condition holds good to. Final answer D) II and III only




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