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If a and b are integers, is a + b = 12?
(1) \(a-b=7\)
(2) \(\frac{a}{b}=8\)
(1) \(a-b=7\)
(2) \(\frac{a}{b}=8\)
Chetan's questions
chetan2u
If a and b are integers, is a + b = 12?
(1) \(a-b=7\)
(2) \(\frac{a}{b}=8\)
New question!!...
(1) \(a-b=7\)
(2) \(\frac{a}{b}=8\)
New question!!...
Asked: If a and b are integers, is a + b = 12?
(1) \(a-b=7\)
a - b = 7; (a,b) = {(even, odd),(odd,even)}
a + b = even + odd = odd
12 = even
a + b \(\neq\) 12
SUFFICIENT
(2) \(\frac{a}{b}=8\)
a = 8b
a+b = 9b;
9b \(\neq\) 12; since b is an integer
SUFFICIENT
IMO D
20 Oct 2019, 09:15
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chetan2u
If a and b are integers, is a + b = 12?
(1) \(a-b=7\)
(2) \(\frac{a}{b}=8\)
New question!!...
(1) \(a-b=7\)
(2) \(\frac{a}{b}=8\)
New question!!...
(1) \(a-b=7\)
Let \(a + b = 12\) and \(a-b = 7\) on solving we see that \(a\) and \(b\) are not integers, So it is not possible that \(a-b =7\) and \(a+b= 12\) both be true and \(a\)and \(b\) be integers. SUFF
(2) \(\frac{a}{b}=8\)
So question becomes is \(8b +b = 12\) or is \(9b= 12\) ? we know that \(b\) is an integer hence \(9b\) can never be equal to \(12\), SUFF
Ans - D
chetan2u, please can you show how statement 2 is NOT SUFF. IMO ans should be D.
