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If grapes are 92% water and raisins are 20% water, then how

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If grapes are 92% water and raisins are 20% water, then how  [#permalink]

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New post 02 Sep 2013, 09:59
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If grapes are 92% water and raisins are 20% water, then how much did a quantity of raisins, which currently weighs 10 pounds, weigh when all the raisins were grapes? (Assume that the only difference between their raisin-weight and their grape-weight is water that evaporated during their transformation.)

A. 25 pounds
B. 46 pounds
C. 92 pounds
D. 100 pounds
E. 146 pounds


Spoiler Alert :VeritasPrep Mock Test Question.

Though I could get this question right, I took more than 3 minutes. Is there any simpler way to solve this one?
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Re: If grapes are 92% water and raisins are 20% water, then how  [#permalink]

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New post 03 Sep 2013, 04:18
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pavan2185 wrote:
If grapes are 92% water and raisins are 20% water, then how much did a quantity of raisins, which currently weighs 10 pounds, weigh when all the raisins were grapes? (Assume that the only difference between their raisin-weight and their grape-weight is water that evaporated during their transformation.)

A. 25 pounds
B. 46 pounds
C. 92 pounds
D. 100 pounds
E. 146 pounds


Spoiler Alert :VeritasPrep Mock Test Question.

Though I could get this question right, I took more than 3 minutes. Is there any simpler way to solve this one?


Since only water evaporates, then the weight of pulp (non-water) in grapes and raisins is the same. Thus 0.08*{weight of grapes}=0.8*{weight of raisins} --> 0.08x = 0.8*10 --> x = 100.

Answer: D.

Similar questions to practice:
each-of-the-cucumbers-in-100-pounds-of-cucumbers-is-composed-102354.html
five-kilograms-of-oranges-contained-98-of-water-141401.html
fresh-dates-contain-90-water-while-dry-dates-contain-143245.html

Hope this helps.
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Re: If grapes are 92% water and raisins are 20% water, then how  [#permalink]

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New post 26 Nov 2013, 00:46
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pavan2185 wrote:
If grapes are 92% water and raisins are 20% water, then how much did a quantity of raisins, which currently weighs 10 pounds, weigh when all the raisins were grapes? (Assume that the only difference between their raisin-weight and their grape-weight is water that evaporated during their transformation.)

A. 25 pounds
B. 46 pounds
C. 92 pounds
D. 100 pounds
E. 146 pounds


Spoiler Alert :VeritasPrep Mock Test Question.

Though I could get this question right, I took more than 3 minutes. Is there any simpler way to solve this one?


Responding to a pm:
Actually, the best method for this question is the one given by Bunuel. I used the same method to give the explanation in the mock too. But you can use weighted average if you wish.

Raisins have 20% water. Water is 100% water. You mix these two to make grapes which has 92% water. (This is another way of saying you remove water from grapes to make raisins)
In what ratio will you mix them?

Wr/Ww = (Cw - Cavg)/(Cavg - Cr) = (100 - 92)/(92 - 20) = 8/72 = 1/9

So every 1 unit of raisin will be mixed with 9 units of water to give 10 units of grapes.
So 10 pounds of raisins will mix with 90 pounds of water to give 100 pounds of grapes.

Answer (D)
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Re: If grapes are 92% water and raisins are 20% water, then how  [#permalink]

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New post 03 Apr 2014, 23:10
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Bunuel wrote:
pavan2185 wrote:
If grapes are 92% water and raisins are 20% water, then how much did a quantity of raisins, which currently weighs 10 pounds, weigh when all the raisins were grapes? (Assume that the only difference between their raisin-weight and their grape-weight is water that evaporated during their transformation.)

A. 25 pounds
B. 46 pounds
C. 92 pounds
D. 100 pounds
E. 146 pounds


Spoiler Alert :VeritasPrep Mock Test Question.

Though I could get this question right, I took more than 3 minutes. Is there any simpler way to solve this one?


Since only water evaporates, then the weight of pulp (non-water) in grapes and raisins is the same. Thus 0.08*{weight of grapes}=0.8*{weight of raisins} --> 0.08x = 0.8*10 --> x = 100.

Answer: D.

Similar questions to practice:
each-of-the-cucumbers-in-100-pounds-of-cucumbers-is-composed-102354.html
five-kilograms-of-oranges-contained-98-of-water-141401.html
fresh-dates-contain-90-water-while-dry-dates-contain-143245.html

Hope this helps.



(Assume that the only difference between their raisin-weight and their grape-weight is water that evaporated during their transformation.)

Had the above highlighted condition not mentioned, would 46 pounds be the answer.. ?
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Re: If grapes are 92% water and raisins are 20% water, then how  [#permalink]

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New post 11 May 2015, 07:42
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If 92 percent of grapes is water then 8 percent is the fruit. If 20 percent of raisins is water then 80 percent is fruit.

.08 (x pounds) = .8 (10 pounds)
x = 100 pounds
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Re: If grapes are 92% water and raisins are 20% water, then how  [#permalink]

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New post 06 Jun 2015, 19:46
Hi I understand the solution given but why is the answer not 46 pounds? why can't one get the answer by proportionality? what is the flaw in my logic?Would appreciate an answer if possible.
Thanks so much.
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Re: If grapes are 92% water and raisins are 20% water, then how  [#permalink]

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New post 08 Jun 2015, 21:03
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Hi sykhong,

Until you show your 'steps', we won't know exactly where you made your mistake. We CAN prove why 46 pounds is NOT the correct answer though....

IF....the grapes weighted 46 pounds total and those grapes were 92% water, then we'd have....

Total = 46 pounds
Water = .92(46) = 42.32 pounds
Not-Water = 3.68 pounds

The part that is NOT-WATER is key here, since that number does NOT change.

The raisins would ALSO contain those 3.68 pounds of not-water, which would represent 80% of the weight (since 20% of the raisins are water).

3.68 = .8(Total Weight)
3.68/.8 = Total Weight
4.6 pounds = Total weight of the raisins

However, the prompt tells us that the raisins are supposed to weigh 10 POUNDS, so the 4.6 pounds is clearly TOO LOW and the grapes must weigh MORE than 46 pounds.

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Re: If grapes are 92% water and raisins are 20% water, then how  [#permalink]

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New post 10 Jun 2015, 22:33
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Presenting a slightly alternate approach:

Since the weight of water is the difference between raisins and grapes, let's calculate the weight of water in \(10\) pounds of raisins and water's weight in raisins when they were grapes

Water in raisins
For \(10\) pounds of raisins there is \(20\)% of water. Hence amount of water = \(20\)% of \(10 = 2\) pounds.

Water in grapes before they evaporated
Let \(x\) pounds be the amount of water that evaporated. So when the raisins were grapes,

Total weight of water = \(2 + x\)

Total weight of grapes = \(10 + x\)

When raisins were grapes, \(\frac{Weight of Water}{Weight of Grapes} = 92\)%

i.e. \(\frac{2 + x}{10 + x} = 0.92\).

Solving for \(x\) would give \(x = 90\) pounds.

Hence total weight of 10 pounds of raisins when they were grapes = \(10 + 90 = 100\) pounds

Hope this helps :)

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Re: If grapes are 92% water and raisins are 20% water, then how  [#permalink]

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New post 14 Nov 2015, 23:11
grape: 92% water & 8% pulp
raisin : 20% water and 80% pulp

80% of (total weight of raisin (x)) = 8 (pulp )
x= 10

total weight = 10* (10 pounds)
= 100
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If grapes are 92% water and raisins are 20% water, then how  [#permalink]

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New post 06 Dec 2015, 09:45
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if we take the grape ratio and apply to it 100 pounds then we will have 92 pounds of water and 8 pounds of pure pulp. the stem says also that out of 10 pounds - 8 pounds is pure pulp.

hence we look up and see that this amount of pure pulp (8 pounds) used to have 92 corresponding pounds of water when this was grape that is 100 in total
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Re: If grapes are 92% water and raisins are 20% water, then how  [#permalink]

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New post 21 May 2016, 12:26
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At first glance this questions seems relatively straightforward but I always find these types of questions some what difficult to work out.

But, I think the best way to do it is clearly write down the info you have and use logic to work it out.

So,

Raisins Contain:

20% Water, and
80% Other

For a total of 10lbs.

Therefore, the raisins contain 2lbs of water and 8lbs of other.

Important to note: The question states the other quantity does not change at all.

Grapes contain:

92% water, and
8% other.

8% other is equals to 8lbs. As this 8% is represented by 8lbs of other the 92% must equal 92lbs of water. 92% + 8% = 100%. Therefore, 92lbs + 8lbs = 100lbs. Answer D.
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Re: If grapes are 92% water and raisins are 20% water, then how  [#permalink]

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New post 08 Sep 2016, 10:34
Dear All

This is how i tried to solve it.

Letting x equal to the number of pounds of grapes

x * 0.92 * 0.2 should be the pounds of water left after 80% of the water in the grapes evaporates

x * 0.92 * 0.2 = 2 should be equal to pounds of water that is in the raisins. so we should be able to solve for x. but this equation does not lead to any solution.

Where i am making the mistake?

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Re: If grapes are 92% water and raisins are 20% water, then how  [#permalink]

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New post 14 May 2017, 21:09
Work with options -

Water weight in raisins = 2 units

From the question; water evaporated = grapes weight - raisin weight

let grapes weight = 100; so water weight in grapes = 92 ; since new water weight = 2 so 90 units of water must have evaporated

LHS=90 (water evaporated )
RHS = grapes weight - raisin weight (100-10)=90

LHS=RHS

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Re: If grapes are 92% water and raisins are 20% water, then how  [#permalink]

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New post 10 Jun 2017, 00:11
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pavan2185 wrote:
If grapes are 92% water and raisins are 20% water, then how much did a quantity of raisins, which currently weighs 10 pounds, weigh when all the raisins were grapes? (Assume that the only difference between their raisin-weight and their grape-weight is water that evaporated during their transformation.)

A. 25 pounds
B. 46 pounds
C. 92 pounds
D. 100 pounds
E. 146 pounds


Spoiler Alert :VeritasPrep Mock Test Question.hough I could get this question right, I took more than 3 minutes. Is there any simpler way to solve this one?

1 The crucial point to understand is that the weight of the non water elements is the same in grapes and raisins. They are just different percentages of different weights but the actual weight is the same.
2. 80% of 10 =8% of x. So x=100.
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If grapes are 92% water and raisins are 20% water, then how  [#permalink]

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New post 19 Aug 2017, 11:18
I keep getting thrown off here because I use the following ratios formula:

G/R = 0.08/0.8

Why doesn't this work? The formula works with other ratios (such as when working with similar triangles). Why do we have to make it 0.08G=0.8R instead? Does it have to do with the fact that we're using percentages?
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Re: If grapes are 92% water and raisins are 20% water, then how  [#permalink]

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New post 20 Aug 2017, 00:34
gmat_george wrote:
I keep getting thrown off here because I use the following ratios formula:

G/R = 0.08/0.8

Why doesn't this work? The formula works with other ratios (such as when working with similar triangles). Why do we have to make it 0.08G=0.8R instead? Does it have to do with the fact that we're using percentages?


We are told that 8% of the weight of grapes equal to 80% of the weight of raisins:
0.08*{weight of grapes}=0.8*{weight of raisins}
{weight of grapes}/{weight of raisins}=0.8/0.08
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Re: If grapes are 92% water and raisins are 20% water, then how  [#permalink]

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New post 21 Dec 2017, 10:50
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Grapes --- > Raisins
8% solid------8% solid of Grapes
92% water-----20% water

10 pound raisins
means-> water will be 20% of 10 =2
solid will be 10-2 = 8
now 8 is 8% of grapes
Y x 0.08 = 8
Y = 100 OPTION D
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Re: If grapes are 92% water and raisins are 20% water, then how  [#permalink]

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New post 01 Apr 2018, 20:39
sykhong wrote:
Hi I understand the solution given but why is the answer not 46 pounds? why can't one get the answer by proportionality? what is the flaw in my logic?Would appreciate an answer if possible.
Thanks so much.



Hi, I was getting the same answer... 46. Now I know why I was wrong. Let me help u understand why 100 pounds is correct.

Total raisins right now weigh 10 pounds.
20% of this is contributed by its water content.
That means, out of 10 pounds:-
Water.................................................................. = 2 pounds
AND
Other/ solid matter (which has a constant weight)..... = 8 pounds
Got it?

So, now this 8 pounds cannot change. Right?
So now, we know that when 10 pounds of raisins were grapes, it contained 8 pounds of 'solid unchangeable weight'.

In grapes, 92% is water weight and 8% is solid weight.
We want to know the TOTAL WEIGHT of the grapes, NOT just the weight of water in these grapes.
So if, 92% corresponds to water weight 8% of the grape weight is of solid content.

So,
8% means out of every 100 parts of grape, 8 parts are of solid.
Therefore,
Since the total solid weight is 8 pound, total grape weight = 100 pounds.

Hope this helps.
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If grapes are 92% water and raisins are 20% water, then how  [#permalink]

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New post 09 May 2018, 06:12
OFFICIAL SOLUTION

D. Begin this question by accounting for what you know - as grapes, these items were 92% water and so 8% "other". And the "other" portion doesn't change. So if you call the volume 92 units of water and 8 units of "other", then when water in a raisin makes up 20% of the total, the other 80% is made up by the 8 units of "other". Since 8 units = 80%,then each unit is 10%, meaning that the 20% water equates to 2 units.

That means that the weight of a raisin is 2 units water, 8 units "other", for a total of 10 units. And the weight of a grape is 92 units water, 8 units "other" for a total of 100 units. To get from raisin weight to grape weight, then, you'd multiply by 10, meaning that 10 pounds of raisins would have weighed 100 pounds as grapes.
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Re: If grapes are 92% water and raisins are 20% water, then how  [#permalink]

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New post 16 Mar 2019, 07:21
My take:
(A1*W1 + A2*W2) / (W1 + W2) = Aavg
=> (20*10 + 100*n) / (10 + n) = 92; Here water concentration = 100% and weight of water = n
=> 200 + 100n = 920 + 92n
=> 8n = 720
=> n = 90
Therefore, weight of grapes = weight of water + weight of raisins = 90 + 10 = 100 pounds
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Re: If grapes are 92% water and raisins are 20% water, then how   [#permalink] 16 Mar 2019, 07:21

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