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If grapes are 92% water and raisins are 20% water, then how [#permalink]
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02 Sep 2013, 10:59
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If grapes are 92% water and raisins are 20% water, then how much did a quantity of raisins, which currently weighs 10 pounds, weigh when all the raisins were grapes? (Assume that the only difference between their raisinweight and their grapeweight is water that evaporated during their transformation.) A. 25 pounds B. 46 pounds C. 92 pounds D. 100 pounds E. 146 pounds Spoiler Alert : VeritasPrep Mock Test Question. Though I could get this question right, I took more than 3 minutes. Is there any simpler way to solve this one?
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Re: If grapes are 92% water and raisins are 20% water, then how [#permalink]
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03 Sep 2013, 05:18



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Re: If grapes are 92% water and raisins are 20% water, then how [#permalink]
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26 Nov 2013, 01:46
pavan2185 wrote: If grapes are 92% water and raisins are 20% water, then how much did a quantity of raisins, which currently weighs 10 pounds, weigh when all the raisins were grapes? (Assume that the only difference between their raisinweight and their grapeweight is water that evaporated during their transformation.) A. 25 pounds B. 46 pounds C. 92 pounds D. 100 pounds E. 146 pounds Spoiler Alert : VeritasPrep Mock Test Question. Though I could get this question right, I took more than 3 minutes. Is there any simpler way to solve this one? Responding to a pm: Actually, the best method for this question is the one given by Bunuel. I used the same method to give the explanation in the mock too. But you can use weighted average if you wish. Raisins have 20% water. Water is 100% water. You mix these two to make grapes which has 92% water. (This is another way of saying you remove water from grapes to make raisins) In what ratio will you mix them? Wr/Ww = (Cw  Cavg)/(Cavg  Cr) = (100  92)/(92  20) = 8/72 = 1/9 So every 1 unit of raisin will be mixed with 9 units of water to give 10 units of grapes. So 10 pounds of raisins will mix with 90 pounds of water to give 100 pounds of grapes. Answer (D)
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Re: If grapes are 92% water and raisins are 20% water, then how [#permalink]
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04 Apr 2014, 00:10
Bunuel wrote: pavan2185 wrote: If grapes are 92% water and raisins are 20% water, then how much did a quantity of raisins, which currently weighs 10 pounds, weigh when all the raisins were grapes? (Assume that the only difference between their raisinweight and their grapeweight is water that evaporated during their transformation.) A. 25 pounds B. 46 pounds C. 92 pounds D. 100 pounds E. 146 pounds Spoiler Alert : VeritasPrep Mock Test Question. Though I could get this question right, I took more than 3 minutes. Is there any simpler way to solve this one? Since only water evaporates, then the weight of pulp (nonwater) in grapes and raisins is the same. Thus 0.08*{weight of grapes}=0.8*{weight of raisins} > 0.08x = 0.8*10 > x = 100. Answer: D. Similar questions to practice: eachofthecucumbersin100poundsofcucumbersiscomposed102354.htmlfivekilogramsoforangescontained98ofwater141401.htmlfreshdatescontain90waterwhiledrydatescontain143245.htmlHope this helps. (Assume that the only difference between their raisinweight and their grapeweight is water that evaporated during their transformation.)Had the above highlighted condition not mentioned, would 46 pounds be the answer.. ?
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Re: If grapes are 92% water and raisins are 20% water, then how [#permalink]
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11 May 2015, 08:42
If 92 percent of grapes is water then 8 percent is the fruit. If 20 percent of raisins is water then 80 percent is fruit.
.08 (x pounds) = .8 (10 pounds) x = 100 pounds



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Re: If grapes are 92% water and raisins are 20% water, then how [#permalink]
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06 Jun 2015, 20:46
Hi I understand the solution given but why is the answer not 46 pounds? why can't one get the answer by proportionality? what is the flaw in my logic?Would appreciate an answer if possible. Thanks so much.



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Re: If grapes are 92% water and raisins are 20% water, then how [#permalink]
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08 Jun 2015, 22:03
Hi sykhong, Until you show your 'steps', we won't know exactly where you made your mistake. We CAN prove why 46 pounds is NOT the correct answer though.... IF....the grapes weighted 46 pounds total and those grapes were 92% water, then we'd have.... Total = 46 pounds Water = .92(46) = 42.32 pounds NotWater = 3.68 pounds The part that is NOTWATER is key here, since that number does NOT change. The raisins would ALSO contain those 3.68 pounds of notwater, which would represent 80% of the weight (since 20% of the raisins are water). 3.68 = .8(Total Weight) 3.68/.8 = Total Weight 4.6 pounds = Total weight of the raisins However, the prompt tells us that the raisins are supposed to weigh 10 POUNDS, so the 4.6 pounds is clearly TOO LOW and the grapes must weigh MORE than 46 pounds. GMAT assassins aren't born, they're made, Rich
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Re: If grapes are 92% water and raisins are 20% water, then how [#permalink]
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10 Jun 2015, 23:33
Presenting a slightly alternate approach: Since the weight of water is the difference between raisins and grapes, let's calculate the weight of water in \(10\) pounds of raisins and water's weight in raisins when they were grapes Water in raisinsFor \(10\) pounds of raisins there is \(20\)% of water. Hence amount of water = \(20\)% of \(10 = 2\) pounds. Water in grapes before they evaporatedLet \(x\) pounds be the amount of water that evaporated. So when the raisins were grapes, Total weight of water = \(2 + x\) Total weight of grapes = \(10 + x\) When raisins were grapes, \(\frac{Weight of Water}{Weight of Grapes} = 92\)% i.e. \(\frac{2 + x}{10 + x} = 0.92\). Solving for \(x\) would give \(x = 90\) pounds. Hence total weight of 10 pounds of raisins when they were grapes = \(10 + 90 = 100\) pounds Hope this helps Regards Harsh
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Re: If grapes are 92% water and raisins are 20% water, then how [#permalink]
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15 Nov 2015, 00:11
grape: 92% water & 8% pulp raisin : 20% water and 80% pulp
80% of (total weight of raisin (x)) = 8 (pulp ) x= 10
total weight = 10* (10 pounds) = 100



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If grapes are 92% water and raisins are 20% water, then how [#permalink]
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06 Dec 2015, 10:45
if we take the grape ratio and apply to it 100 pounds then we will have 92 pounds of water and 8 pounds of pure pulp. the stem says also that out of 10 pounds  8 pounds is pure pulp. hence we look up and see that this amount of pure pulp (8 pounds) used to have 92 corresponding pounds of water when this was grape that is 100 in total
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Re: If grapes are 92% water and raisins are 20% water, then how [#permalink]
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21 May 2016, 13:26
At first glance this questions seems relatively straightforward but I always find these types of questions some what difficult to work out.
But, I think the best way to do it is clearly write down the info you have and use logic to work it out.
So,
Raisins Contain:
20% Water, and 80% Other
For a total of 10lbs.
Therefore, the raisins contain 2lbs of water and 8lbs of other.
Important to note: The question states the other quantity does not change at all.
Grapes contain:
92% water, and 8% other.
8% other is equals to 8lbs. As this 8% is represented by 8lbs of other the 92% must equal 92lbs of water. 92% + 8% = 100%. Therefore, 92lbs + 8lbs = 100lbs. Answer D.



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Re: If grapes are 92% water and raisins are 20% water, then how [#permalink]
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08 Sep 2016, 11:34
Dear All
This is how i tried to solve it.
Letting x equal to the number of pounds of grapes
x * 0.92 * 0.2 should be the pounds of water left after 80% of the water in the grapes evaporates
x * 0.92 * 0.2 = 2 should be equal to pounds of water that is in the raisins. so we should be able to solve for x. but this equation does not lead to any solution.
Where i am making the mistake?
Regards
B



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Re: If grapes are 92% water and raisins are 20% water, then how [#permalink]
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14 May 2017, 22:09
Work with options 
Water weight in raisins = 2 units
From the question; water evaporated = grapes weight  raisin weight
let grapes weight = 100; so water weight in grapes = 92 ; since new water weight = 2 so 90 units of water must have evaporated
LHS=90 (water evaporated ) RHS = grapes weight  raisin weight (10010)=90
LHS=RHS
D



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Re: If grapes are 92% water and raisins are 20% water, then how [#permalink]
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10 Jun 2017, 01:11
pavan2185 wrote: If grapes are 92% water and raisins are 20% water, then how much did a quantity of raisins, which currently weighs 10 pounds, weigh when all the raisins were grapes? (Assume that the only difference between their raisinweight and their grapeweight is water that evaporated during their transformation.) A. 25 pounds B. 46 pounds C. 92 pounds D. 100 pounds E. 146 pounds Spoiler Alert : VeritasPrep Mock Test Question.hough I could get this question right, I took more than 3 minutes. Is there any simpler way to solve this one? 1 The crucial point to understand is that the weight of the non water elements is the same in grapes and raisins. They are just different percentages of different weights but the actual weight is the same. 2. 80% of 10 =8% of x. So x=100.
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If grapes are 92% water and raisins are 20% water, then how [#permalink]
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19 Aug 2017, 12:18
I keep getting thrown off here because I use the following ratios formula:
G/R = 0.08/0.8
Why doesn't this work? The formula works with other ratios (such as when working with similar triangles). Why do we have to make it 0.08G=0.8R instead? Does it have to do with the fact that we're using percentages?



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Re: If grapes are 92% water and raisins are 20% water, then how [#permalink]
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20 Aug 2017, 01:34



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Re: If grapes are 92% water and raisins are 20% water, then how [#permalink]
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21 Dec 2017, 11:50
Grapes  > Raisins 8% solid8% solid of Grapes 92% water20% water 10 pound raisins means> water will be 20% of 10 =2 solid will be 102 = 8 now 8 is 8% of grapes Y x 0.08 = 8 Y = 100 OPTION D
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Re: If grapes are 92% water and raisins are 20% water, then how [#permalink]
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01 Apr 2018, 21:39
sykhong wrote: Hi I understand the solution given but why is the answer not 46 pounds? why can't one get the answer by proportionality? what is the flaw in my logic?Would appreciate an answer if possible. Thanks so much. Hi, I was getting the same answer... 46. Now I know why I was wrong. Let me help u understand why 100 pounds is correct. Total raisins right now weigh 10 pounds. 20% of this is contributed by its water content. That means, out of 10 pounds: Water.................................................................. = 2 pounds AND Other/ solid matter (which has a constant weight)..... = 8 pounds Got it? So, now this 8 pounds cannot change. Right? So now, we know that when 10 pounds of raisins were grapes, it contained 8 pounds of 'solid unchangeable weight'. In grapes, 92% is water weight and 8% is solid weight. We want to know the TOTAL WEIGHT of the grapes, NOT just the weight of water in these grapes. So if, 92% corresponds to water weight 8% of the grape weight is of solid content. So, 8% means out of every 100 parts of grape, 8 parts are of solid. Therefore, Since the total solid weight is 8 pound, total grape weight = 100 pounds. Hope this helps.



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If grapes are 92% water and raisins are 20% water, then how [#permalink]
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09 May 2018, 07:12
OFFICIAL SOLUTION D. Begin this question by accounting for what you know  as grapes, these items were 92% water and so 8% "other". And the "other" portion doesn't change. So if you call the volume 92 units of water and 8 units of "other", then when water in a raisin makes up 20% of the total, the other 80% is made up by the 8 units of "other". Since 8 units = 80%,then each unit is 10%, meaning that the 20% water equates to 2 units. That means that the weight of a raisin is 2 units water, 8 units "other", for a total of 10 units. And the weight of a grape is 92 units water, 8 units "other" for a total of 100 units. To get from raisin weight to grape weight, then, you'd multiply by 10, meaning that 10 pounds of raisins would have weighed 100 pounds as grapes.
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If grapes are 92% water and raisins are 20% water, then how
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