Author 
Message 
TAGS:

Hide Tags

Intern
Joined: 10 Jun 2012
Posts: 8

Five kilograms of oranges contained 98% of water.
[#permalink]
Show Tags
27 Oct 2012, 05:30
Question Stats:
61% (01:43) correct 39% (02:09) wrong based on 709 sessions
HideShow timer Statistics
Five kilograms of oranges contained 98% of water. If the next day the concentration of water decreased by 2%, what was the new weight of the oranges, in kilograms? (A) 4.9 (B) 4.8 (C) 2.5 (D) 2 (E) 0.2 I've got the answer (A) but the correct one is (C). How can it be possible? Please, share your ideas!
Official Answer and Stats are available only to registered users. Register/ Login.




Math Expert
Joined: 02 Sep 2009
Posts: 64239

Re: Five kilograms of oranges contained 98% of water.
[#permalink]
Show Tags
27 Oct 2012, 06:24
Five kilograms of oranges contained 98% of water. If the next day the concentration of water decreased by 2%, what was the new weight of the oranges, in kilograms?(A) 4.9 (B) 4.8 (C) 2.5 (D) 2 (E) 0.2 If C is the answer, then the question means that the concentration of water the newt day became 96%. Out of 5 kilograms 98%, or 4.9 kilograms was water and 0.1 kilograms was nonwater. The next day, after some water evaporated, oranges became 96% water and 4% of nonwater, so the next day 0.1 kilograms of nonwater composed 4% of oranges, which means that the new weight of the oranges was x*0.04=0.1 > x=2.5 kilograms. Answer: C. Similar questions to practice: eachofthecucumbersin100poundsofcucumbersiscomposed102354.htmlfreshdatescontain90waterwhiledrydatescontain143245.htmlHope it helps.
_________________




Intern
Joined: 10 Jun 2012
Posts: 8

Re: Five kilograms of oranges contained 98% of water.
[#permalink]
Show Tags
27 Oct 2012, 06:47
Nice explanation! Thank you! Achievement Unlocked. =)



Manager
Joined: 28 Feb 2012
Posts: 103
Concentration: Strategy, International Business
GPA: 3.9
WE: Marketing (Other)

Re: Five kilograms of oranges contained 98% of water.
[#permalink]
Show Tags
29 Oct 2012, 05:33
Bunuel wrote: Five kilograms of oranges contained 98% of water. If the next day the concentration of water decreased by 2%, what was the new weight of the oranges, in kilograms?(A) 4.9 (B) 4.8 (C) 2.5 (D) 2 (E) 0.2 If C is the answer, then the question means that the concentration of water the newt day became 96%. Out of 5 kilograms 98%, or 4.9 kilograms was water and 0.1 kilograms was nonwater. The next day, after some water evaporated, oranges became 96% water and 4% of nonwater, so the next day 0.1 kilograms of nonwater composed 4% of oranges, which means that the new weight of the oranges was x*0.04=0.1 > x=2.5 kilograms. Answer: C. Similar question to practice: eachofthecucumbersin100poundsofcucumbersiscomposed102354.htmlHope it helps. I also thought that it is A, Bunuel do you think that it is real GMAT like question, because i think that it is a little unclear.



Math Expert
Joined: 02 Sep 2009
Posts: 64239

Re: Five kilograms of oranges contained 98% of water.
[#permalink]
Show Tags
29 Oct 2012, 05:36
ziko wrote: Bunuel wrote: Five kilograms of oranges contained 98% of water. If the next day the concentration of water decreased by 2%, what was the new weight of the oranges, in kilograms?(A) 4.9 (B) 4.8 (C) 2.5 (D) 2 (E) 0.2 If C is the answer, then the question means that the concentration of water the newt day became 96%. Out of 5 kilograms 98%, or 4.9 kilograms was water and 0.1 kilograms was nonwater. The next day, after some water evaporated, oranges became 96% water and 4% of nonwater, so the next day 0.1 kilograms of nonwater composed 4% of oranges, which means that the new weight of the oranges was x*0.04=0.1 > x=2.5 kilograms. Answer: C. Similar question to practice: eachofthecucumbersin100poundsofcucumbersiscomposed102354.htmlHope it helps. I also thought that it is A, Bunuel do you think that it is real GMAT like question, because i think that it is a little unclear. I agree, the wording is ambiguous. So, not a GMAT like question. Check the link in my previous post for similar question with better wording.
_________________



Manager
Joined: 14 Nov 2011
Posts: 113
Location: United States
Concentration: General Management, Entrepreneurship
GPA: 3.61
WE: Consulting (Manufacturing)

Re: Five kilograms of oranges contained 98% of water.
[#permalink]
Show Tags
19 Jun 2013, 18:02
rainbooow wrote: Five kilograms of oranges contained 98% of water. If the next day the concentration of water decreased by 2%, what was the new weight of the oranges, in kilograms? (A) 4.9 (B) 4.8 (C) 2.5 (D) 2 (E) 0.2 I've got the answer (A) but the correct one is (C). How can it be possible? Please, share your ideas! 0.02*5 = 0.04*x => x=2.5



Intern
Joined: 29 May 2013
Posts: 5

Re: Five kilograms of oranges contained 98% of water.
[#permalink]
Show Tags
30 Jun 2013, 06:07
98% water =4.9 Kg 2% Non Water = .1kg (I)
After evaporation, let new weight of oranges be X kgs.
Water is 2 % less. 96 % of X. Therefore, non water is 4% of X. (II)
Weight of Non water is same, before and after evaporation,so equate I and II.
4/100 of X kg =.1Kg, Solve for X.
X= .1*100/2.5
Thanks.



Retired Moderator
Joined: 17 Sep 2013
Posts: 315
Concentration: Strategy, General Management
WE: Analyst (Consulting)

Re: Five kilograms of oranges contained 98% of water.
[#permalink]
Show Tags
18 Jul 2014, 10:18
Hey Bunuel how did you assume that 98% of water implies 98% of the weight share...is it not ambiguous?..Or am I over thinking?



Math Expert
Joined: 02 Sep 2009
Posts: 64239

Re: Five kilograms of oranges contained 98% of water.
[#permalink]
Show Tags
18 Jul 2014, 11:12
JusTLucK04 wrote: Hey Bunuel how did you assume that 98% of water implies 98% of the weight share...is it not ambiguous?..Or am I over thinking? As I mentioned here: fivekilogramsoforangescontained98ofwater141401.html#p1137031 the wording is indeed ambiguous. You can practice better quality questions testing the same concept which are given in my post above.
_________________



Manager
Joined: 24 Oct 2013
Posts: 131
Location: Canada
WE: Design (Transportation)

Re: Five kilograms of oranges contained 98% of water.
[#permalink]
Show Tags
01 Oct 2014, 18:40
Weight of water in the beginning = 5*0.98
Weight of water after loss of x kg weight = 5*0.98  x
Weight of Oranges after loss of weight = 5  x
New concentration = ( 5*0.98  x ) / ( 5  x ) x 100 = 96 (since it's 2% less now)
solve for x



Current Student
Joined: 03 Apr 2013
Posts: 258
Location: India
Concentration: Marketing, Finance
GMAT 1: 740 Q50 V41
GPA: 3

Five kilograms of oranges contained 98% of water.
[#permalink]
Show Tags
27 Jun 2016, 22:27
Bunuel wrote: Five kilograms of oranges contained 98% of water. If the next day the concentration of water decreased by 2%, what was the new weight of the oranges, in kilograms?(A) 4.9 (B) 4.8 (C) 2.5 (D) 2 (E) 0.2 If C is the answer, then the question means that the concentration of water the newt day became 96%. Out of 5 kilograms 98%, or 4.9 kilograms was water and 0.1 kilograms was nonwater. The next day, after some water evaporated, oranges became 96% water and 4% of nonwater, so the next day 0.1 kilograms of nonwater composed 4% of oranges, which means that the new weight of the oranges was x*0.04=0.1 > x=2.5 kilograms. Answer: C. Similar questions to practice: eachofthecucumbersin100poundsofcucumbersiscomposed102354.htmlfreshdatescontain90waterwhiledrydatescontain143245.htmlHope it helps. I hope the GMAT differentiates clearly between "percentage" and "percentage points"...If it doesn't..then please tell how would it be stated differently..so there are no surprises in the test.



Target Test Prep Representative
Status: Founder & CEO
Affiliations: Target Test Prep
Joined: 14 Oct 2015
Posts: 10651
Location: United States (CA)

Re: Five kilograms of oranges contained 98% of water.
[#permalink]
Show Tags
01 Feb 2019, 17:43
rainbooow wrote: Five kilograms of oranges contained 98% of water. If the next day the concentration of water decreased by 2%, what was the new weight of the oranges, in kilograms?
(A) 4.9 (B) 4.8 (C) 2.5 (D) 2 (E) 0.2 The initial weight of the water is 5 x 0.98 = 4.9. Since only water evaporates, we can let x = the weight of the water that evaporates and create the equation: (4.9  x)/(5  x) = 0.96 4.9  x = 0.96(5  x) 4.9  x = 4.8  0.96x 0.1 = 0.04x 4x = 10 x = 2.5 Since 2.5 lbs of water is lost, the new weight of the oranges is 5  2.5 = 2.5 lbs. Answer: C
_________________
5star rated online GMAT quant self study course See why Target Test Prep is the top rated GMAT quant course on GMAT Club. Read Our Reviews If you find one of my posts helpful, please take a moment to click on the "Kudos" button.



Intern
Joined: 28 Aug 2016
Posts: 30
Location: India
Concentration: General Management, Technology
WE: Engineering (Computer Software)

Re: Five kilograms of oranges contained 98% of water.
[#permalink]
Show Tags
16 Mar 2019, 07:44
My Take:
Generally: (A1*W1 + A2*W2) / (W1 + W2) = Aavg
In this case:(Water evaporates) (A1*W1  A2*W2) / (W1  W2) = Aavg
=> (98*5  100*n) / (5  n) = 96; Here water concentration = 100% and weight of water = n; 96% because water concentration decreased by 2% => 98*5  100n = 96*5  96n => 5(9896) = 100n  96n => 10 = 4n => n = 2.5 Therefore, new weight of oranges = 5  2.5 = 2.5 kgs



GMAT Club Legend
Joined: 18 Aug 2017
Posts: 6306
Location: India
Concentration: Sustainability, Marketing
GPA: 4
WE: Marketing (Energy and Utilities)

Re: Five kilograms of oranges contained 98% of water.
[#permalink]
Show Tags
05 Aug 2019, 10:05
rainbooow wrote: Five kilograms of oranges contained 98% of water. If the next day the concentration of water decreased by 2%, what was the new weight of the oranges, in kilograms? (A) 4.9 (B) 4.8 (C) 2.5 (D) 2 (E) 0.2 I've got the answer (A) but the correct one is (C). How can it be possible? Please, share your ideas! for 5kgs water = 4.9 kgs ans .1 kgs is weight later 4% or say 0.04*x=.1 x=2.5 IMO C



Intern
Joined: 02 Aug 2019
Posts: 1

Re: Five kilograms of oranges contained 98% of water.
[#permalink]
Show Tags
05 Aug 2019, 23:41
The answer can't be C because that's nearly 50% reduction in the weight of the oranges which can't be possible with 2% reduction in water. The question has some data missing.
Posted from my mobile device




Re: Five kilograms of oranges contained 98% of water.
[#permalink]
05 Aug 2019, 23:41




