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If x and y are numbers such that (x + 11) (y – 11) = 0, what is the sm
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17 Apr 2015, 05:12
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Re: If x and y are numbers such that (x + 11) (y – 11) = 0, what is the sm
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17 Apr 2015, 05:23
Bunuel wrote: If x and y are numbers such that (x + 11) (y – 11) = 0, what is the smallest possible value of x^2 + y^2 ?
A) 0 B) 11 C) 22 D) 121 E) 242
Kudos for a correct solution. (x + 11) (y – 11) = 0 Either x=11 OR y=11 Either \(x^2\)=121 OR \(y^2\)=121 In any of the case we will have one square as 121, since the square of any number is either 0 or positive, to get the smallest possible value of x^2 + y^2, we need a 0 as the other value of the square. Smallest possible value = 121+0=121 Answer: D




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Re: If x and y are numbers such that (x + 11) (y – 11) = 0, what is the sm
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17 Apr 2015, 06:35
Given (x + 11) (y – 11) = 0 Then, the following values will satisfies the above condition
case (i): x =  11 or y = 11 case (ii): x =  11 or y = 0 case (iii): x = 0 or y = 11
Values of x^2 + y^2 could be 242, 121, 121
So the smallest is 121
Answer D



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Re: If x and y are numbers such that (x + 11) (y – 11) = 0, what is the sm
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17 Apr 2015, 06:49
Should be D. Either x or y has to be 11. For the expression to be smallest, we consider the other as 0. Hence, 0^2 + 11^2 = 121.



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Re: If x and y are numbers such that (x + 11) (y – 11) = 0, what is the sm
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18 Apr 2015, 13:45
Given that,
(x+11)(y11) =0
so either x = 11 or y=11 or both
But we have to minimise X^2 + Y^2.
That can be minimised only when one of x or y is zero
so if we take x=11
then X^2 + Y^2 =(11)^2 + 0 =121
So answer should be D



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Re: If x and y are numbers such that (x + 11) (y – 11) = 0, what is the sm
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19 Apr 2015, 03:48
Bunuel wrote: If x and y are numbers such that (x + 11) (y – 11) = 0, what is the smallest possible value of x^2 + y^2 ?
A) 0 B) 11 C) 22 D) 121 E) 242
Kudos for a correct solution. Take x=11,y=0 OR y=11, x=0 Smallest possible value= 11*2+0^2 OR O^2+11^2=121 Answer D



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Re: If x and y are numbers such that (x + 11) (y – 11) = 0, what is the sm
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20 Apr 2015, 04:49
Bunuel wrote: If x and y are numbers such that (x + 11) (y – 11) = 0, what is the smallest possible value of x^2 + y^2 ?
A) 0 B) 11 C) 22 D) 121 E) 242
Kudos for a correct solution. VERITAS PREP OFFICIAL SOLUTIONThe first thing to recognize is that one of these answers is the correct answer. This means that, given the parameters of the problem, one of these choices should spit out an answer that makes sense if used in the above equations. The easiest thing to do to check which answer choice will give a plausible solution is to plug one of the choices in to our given equations. A) 0 x² + y² = 0 (Plausible, both x and y must be 0) (0 + 11)(0 – 11) = 0 (not possible) By plugging in our first answer choice we are given some very important information. We see that in the equation “(x + 11) (y – 11) = 0”, one or both of the quantities within the parentheses must be zero. That is one of those rules of algebra that we all learned a million years ago in our first algebra class called the zero product property : If ab = 0, then a = 0 or b = 0. Given this fact, we need x to equal 11 or y to equal 11 in order for the first equation to be possible. This will help us in testing our next answer choices. B) 11 x² + y² = 11 (Not plausible given we need x to equal 11 or y to equal 11) C) 22 x² + y² = 22 (Not plausible given we need x to equal 11 or y to equal 11) D) 121 x² + y² = 121 (Plausible, x² could equal 0 and y could equal 11, or x could equal 11 and y could equal 0) (11 + 11)(0 – 11) = 0 or (0 + 11)(11 – 11) = 0 (Plausible) At this point we are actually done. The answer choices are always listed in order of smallest to largest and we are looking for the smallest number that would satisfy these parameters. Even if (E) gives us a plausible answer, it is a larger number than (D) and, thus, is an incorrect answer. There are a number of different kinds of problems where plugging in the answer choices are useful, but these tend to be problems where either an equation or some parameters are given and the goal is to find out which answer choice fits given what is stated in the problem. Even if plugging in an answer choice doesn’t give an immediate answer, it can shed some light onto some aspect of the problem that might not be immediately visible, as we saw above. So go ahead and use those answer choices. They are there to help you – not to hurt you!
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Re: If x and y are numbers such that (x + 11) (y – 11) = 0, what is the sm
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20 Apr 2015, 04:50



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Re: If x and y are numbers such that (x + 11) (y – 11) = 0, what is the sm
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Re: If x and y are numbers such that (x + 11) (y – 11) = 0, what is the sm
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09 Dec 2016, 11:35
Bunuel wrote: Bunuel wrote: If x and y are numbers such that (x + 11) (y – 11) = 0, what is the smallest possible value of x^2 + y^2 ?
A) 0 B) 11 C) 22 D) 121 E) 242
Kudos for a correct solution. From (x + 11)(y  11)=0 it follows that either x = 11 or y = 11. Thus either x^2 = 121 or y^2 = 121. Now, if x^2 = 121, then the least value of y^2 is 0, so the least value of x^2 + y^2 = 121 + 0 = 121. Similarly if y^2 = 121, then the least value of x^2 is 0, so the least value of x^2 + y^2 = 0 + 121 = 121. Answer: D. Love your way of thinking. Could you please confirm my understanding of these kind of questions  if (x+11)(y11) = 0, then any of the following 3 scenarios are possible  1. x= 11 and y can be anything 2. y = 11 and x can be anything 3. both x is 11 and y is 11 Please confirm. Thanks a ton.



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Re: If x and y are numbers such that (x + 11) (y – 11) = 0, what is the sm
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10 Dec 2016, 01:26
Bunuel wrote: If x and y are numbers such that (x + 11) (y – 11) = 0, what is the smallest possible value of x^2 + y^2 ?
A) 0 B) 11 C) 22 D) 121 E) 242
Kudos for a correct solution. Since, \((x + 11) (y – 11) = 0\) Either  1. \((x + 11) = 0\) or, \(x =  11\) & \(y = 0\) 2. \((y – 11) = 0 , or y = 11\) & \(x = 0\) Now, \(x^2 + y^2\) can have 2 values  1. \(11^2 + 0^2 = 121\) 2. \(0^2 + 11^2 = 121\) Thus, the smallest possible value of \(x^2 + y^2\) will be (D) \(121\)
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Re: If x and y are numbers such that (x + 11) (y – 11) = 0, what is the sm
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21 Apr 2017, 10:11
Bunuel wrote: If x and y are numbers such that (x + 11) (y – 11) = 0, what is the smallest possible value of x^2 + y^2 ?
A) 0 B) 11 C) 22 D) 121 E) 242
Kudos for a correct solution. Easy although I failed to get it what is the least value which can make below mentioned equation Zero (x+11)(y11)=0 either put x=11 or y=11 it will make the other zero and put zero for other variable so x=11,y=0 result is 0 now find value of x^2+y^2 (11)^2+(0)^2 121 choice is D
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Re: If x and y are numbers such that (x + 11) (y – 11) = 0, what is the sm &nbs
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