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Updated on: 21 Sep 2019, 17:27
Originally posted by Lolaergasheva on 05 Mar 2011, 08:12.
Last edited by Bunuel on 21 Sep 2019, 17:27, edited 3 times in total.
Last edited by Bunuel on 21 Sep 2019, 17:27, edited 3 times in total.
Edited the question.
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D
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
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Question Stats:
77% (01:33) correct
23%
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wrong
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If \(y = 2^{(x+1)}\), what is the value of y – x?
(1) \(2^{(2x+2)} = 64\)
(2) \(y = 2^{(2x –1)}\)
DS57602.01
(1) \(2^{(2x+2)} = 64\)
(2) \(y = 2^{(2x –1)}\)
DS57602.01
Updated on: 05 Mar 2011, 09:40
Originally posted by beyondgmatscore on 05 Mar 2011, 08:24.
Last edited by beyondgmatscore on 05 Mar 2011, 09:40, edited 2 times in total.
Last edited by beyondgmatscore on 05 Mar 2011, 09:40, edited 2 times in total.
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Lolaergasheva
I assume that the questions reads as follows:
If y = \(2^{x+1}\), what is the value of y – x?
(1) \(2^{2x+2}\) = 64
(2) \(y = 2^{2x-1}\)
Then, 1st statement gives us 2x+2 = 6 and hence x =2 and therefore y = \(2^{2+1}\) = \(2^3\) = 8 hence y-x = 8-2 = 6, So sufficient
From 2, \(y = 2^{2x-1}\) = \(2^{x+1}\)
or 2x-1 = x+1 and hence x =2 and hence like in 1, y =8 and hence y-x = 8-2 = 6, So sufficient
Answer is D
General Discussion
05 Mar 2011, 08:45
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Lolaergasheva
Please, format the questions properly.
Original question is:
If y = 2^(x+1), what is the value of y – x?
(1) 2^(2x+2) = 64 --> \(2^{2x+2}=2^6\) --> as bases are equal we can equate the powers: \(2x+2=6\) --> \(x=2\). From the stem: \(y=2^{x+1}=2^3=8\), so \(y-x=8-2=6\). Sufficient.
(2) y = 2^(2x –1) --> as also given that \(y=2^{x+1}\) then \(2^{x+1}=2^{2x-1}\) --> \(x+1=2x-1\) --> \(x=2\), then the same way as above \(y=8\) --> \(y-x=8-2=6\). Sufficient.
Answer: D.
