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06 Jun 2020, 23:54
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EgmatQuantExpert
Asked: If y = |2 + x| - |2 – x| and |2x – 15| < 2, how many integer values can y take?
-2 <2x - 15< 2
13<2x<17
-2<2<6.5<x<8.5
y = |2 + x| - |2 – x|
y = (2 + x) - (x-2) = 4; 1 integer value of y
IMO B
10 Jun 2020, 06:08
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I was solving this question and I noted down the question as |2x-5|<2 and not |2x – 15| < 2 which changed my range for x as : 1.5<x<3.5
While solving for y = |2 + x| - |2 – x|
I realized that |2+x| will always be positive for 1.5<x<3.5 but |2-x| will have two separate cases for 1.5<x<3.5
I solved and I found the values for y to be 4 and 6
Can anyone tell me if I was right or wrong? (Note: Use |2x-5|<2)
While solving for y = |2 + x| - |2 – x|
I realized that |2+x| will always be positive for 1.5<x<3.5 but |2-x| will have two separate cases for 1.5<x<3.5
I solved and I found the values for y to be 4 and 6
Can anyone tell me if I was right or wrong? (Note: Use |2x-5|<2)
19 Aug 2021, 10:50
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Since, |2x-15|<2, we can derive that 6.5<x<8.5.
Also, y = |2+x| - |2-x|.
Now, sub any value of "x" from the range we derived in the eqn of y. Any number will give you the answer y=4.
Also, y = |2+x| - |2-x|.
Now, sub any value of "x" from the range we derived in the eqn of y. Any number will give you the answer y=4.
