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If y = |2 + x| - |2 – x| and |2x – 15| < 2, how many integer values

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If y = |2 + x| - |2 – x| and |2x – 15| < 2, how many integer values  [#permalink]

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If y = |2 + x| - |2 – x| and |2x – 15| < 2, how many integer values can y take?

(A) 0
(B) 1
(C) 2
(D) 4
(E) Cannot be determined


This is Question 4 for the e-GMAT Question Series on Absolute Value.

Provide your solution below. Kudos for participation. Happy Solving! :-D

Best Regards
The e-GMAT Team

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Originally posted by EgmatQuantExpert on 20 May 2015, 10:23.
Last edited by EgmatQuantExpert on 07 Aug 2018, 06:05, edited 3 times in total.
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Re: If y = |2 + x| - |2 – x| and |2x – 15| < 2, how many integer values  [#permalink]

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New post 20 May 2015, 11:12
7
5
|2x – 15| < 2
So 6.5 < x < 8.5

In y = |2 + x| - |2 – x| for above values of X , |2+x| will be equal to 2+X and |2 – x| will be equal to x-2

Substituting
y=2+x-x+2=4

Answer 1
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Re: If y = |2 + x| - |2 – x| and |2x – 15| < 2, how many integer values  [#permalink]

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New post 20 May 2015, 14:30
3
1
EgmatQuantExpert wrote:
If y = |2 + x| - |2 – x| and |2x – 15| < 2, how many integer values can y take?

(A) 0
(B) 1
(C) 2
(D) 4
(E) Cannot be determined


This is Question 4 for the e-GMAT Question Series on Absolute Value.

Provide your solution below. Kudos for participation. The Official Answer and Explanation will be posted on 22nd May.

Till then, Happy Solving! :-D

Best Regards
The e-GMAT Team


Here's how to solve it:

First find the range of values for x:

Inequalities involving absolute values - here you have a number case again. First solve like this without the brackets:

2x – 15 < 2
2x < 17
x < 8.5

Second case (FLIP the sign and put a negative sign around the other side of the inequality):

2x – 15 > -2
x>6.5

Hence: 6.5<x<8.5 >>> since x is an integer, only 7 is possible as a value.

Now put in 7 in If y = |2 + x| - |2 – x| to see that there is only 1 solution. ANSWER CHOICE A
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Re: If y = |2 + x| - |2 – x| and |2x – 15| < 2, how many integer values  [#permalink]

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New post 20 May 2015, 22:12
3
1
Solving |2x – 15| < 2 first to get range of x
(2x – 15) < 2
x < 8.5

-(2x – 15) < 2
x > 6.5

Range of x 6.5<x<8.5

y = |2 + x| - |2 – x| to see that there is only 1 solution.

\(|2 + x| = 2 + x\) ...... is always +ve , x > 2 as (6.5<x<8.5)

\(|2 – x| = -(2 - x)\) ...... range of x > 2 , so 2-x will be negative

    \(y = |2 + x| - |2 – x|\)
    \(y = 2 + x -(-(2 - x))\)
    \(y = 4 ;\)
    constant value

Ans : A
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Re: If y = |2 + x| - |2 – x| and |2x – 15| < 2, how many integer values  [#permalink]

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New post 20 May 2015, 22:20
2
reto wrote:

Hence: 6.5<x<8.5 >>> since x is an integer, only 7 is possible as a value.

Now put in 7 in If y = |2 + x| - |2 – x| to see that there is only 1 solution. ANSWER CHOICE A


reto, want to correct one thing in your solution, there are more possible values for x that will result in y as integer

for Example : integer value 8 , and you can take x = 15/2 , 6.9, 7.2 any fraction between (6.5 - 8.5) all result in integer value for Y
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Re: If y = |2 + x| - |2 – x| and |2x – 15| < 2, how many integer values  [#permalink]

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New post 21 May 2015, 04:21
UJs wrote:
reto wrote:

Hence: 6.5<x<8.5 >>> since x is an integer, only 7 is possible as a value.

Now put in 7 in If y = |2 + x| - |2 – x| to see that there is only 1 solution. ANSWER CHOICE A


reto, want to correct one thing in your solution, there are more possible values for x that will result in y as integer

for Example : integer value 8 , and you can take x = 15/2 , 6.9, 7.2 any fraction between (6.5 - 8.5) all result in integer value for Y


Dear reto

Please note that the question doesn't mention that x is an integer. So, it would be wrong to assume that. In this case, you were able to answer the question correctly even with this wrong assumption. But in a different question, this wrong assumption would have led you to an incorrect answer.

For example, try this variation of the above question:

If y = |2 + x| - |2 – x| and |x – 1| < 1, how many integer values can y take?

(A) None
(B) 1
(C) 2
(D) 3
(E) Cannot be determined


First solve it without using the constraint that x is an integer.
Then solve the question using the constraint that x is an integer.

How does your answer change?

Best Regards

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Re: If y = |2 + x| - |2 – x| and |2x – 15| < 2, how many integer values  [#permalink]

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New post 21 May 2015, 11:33
1
Lucky2783 wrote:
|2x – 15| < 2
So 6.5 < x < 8.5

In y = |2 + x| - |2 – x| for above values of X , |2+x| will be equal to 2+X and |2 – x| will be equal to x-2

Substituting
y=2+x-x+2=4

Answer 1


Also using the graphs we can immediately see that y=4 is only solution.
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Re: If y = |2 + x| - |2 – x| and |2x – 15| < 2, how many integer values  [#permalink]

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New post 22 May 2015, 04:21
X is between 0 and 2.
y=2x
Does this mean the number of integer values of y can't be determined ? Please suggest.

EgmatQuantExpert wrote:
UJs wrote:
reto wrote:

Hence: 6.5<x<8.5 >>> since x is an integer, only 7 is possible as a value.

Now put in 7 in If y = |2 + x| - |2 – x| to see that there is only 1 solution. ANSWER CHOICE A


reto, want to correct one thing in your solution, there are more possible values for x that will result in y as integer

for Example : integer value 8 , and you can take x = 15/2 , 6.9, 7.2 any fraction between (6.5 - 8.5) all result in integer value for Y


Dear reto

Please note that the question doesn't mention that x is an integer. So, it would be wrong to assume that. In this case, you were able to answer the question correctly even with this wrong assumption. But in a different question, this wrong assumption would have led you to an incorrect answer.

For example, try this variation of the above question:

If y = |2 + x| - |2 – x| and |x – 1| < 1, how many integer values can y take?

(A) None
(B) 1
(C) 2
(D) 3
(E) Cannot be determined


First solve it without using the constraint that x is an integer.
Then solve the question using the constraint that x is an integer.

How does your answer change?

Best Regards

Japinder
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Re: If y = |2 + x| - |2 – x| and |2x – 15| < 2, how many integer values  [#permalink]

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New post 22 May 2015, 07:40
Official Explanation

Correct Answer: B

|2x – 15| < 2

Can also be written as |x – 7.5| < 1

Image

The expression |x - 7.5| represents the distance between x and 7.5 on the number line.

The inequality |x - 7.5| < 1 means that the distance between x and 7.5 on the number line is less than 1.

This means, x lies between 6.5 and 8.5, exclusive.

Now, y = |2+x| - | 2 – x |

Rewriting this as
y = |x + 2| - | x – 2|

Here |x+2| represents the distance of x from -2 on the number line
And, |x-2| represents the distance of x from 2 on the number line.


Representing these 2 distances on number line:

Image

It’s easy to see that y = 4.

So, only 1 possible value of y.

Note: the question is asking about HOW MANY values y can have, not WHAT values y can have.
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Re: If y = |2 + x| - |2 – x| and |2x – 15| < 2, how many integer values  [#permalink]

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New post 22 May 2015, 07:49
1
1
csirishac wrote:
X is between 0 and 2.
y=2x
Does this mean the number of integer values of y can't be determined ? Please suggest.

EgmatQuantExpert wrote:

For example, try this variation of the above question:

If y = |2 + x| - |2 – x| and |x – 1| < 1, how many integer values can y take?

(A) None
(B) 1
(C) 2
(D) 3
(E) Cannot be determined




Dear csirishac

You are right that the highlighted part in the quote above gives us: 0 < x < 2

You're also right that for this range of x, y = 2x

Now, the question is: how many integer values can y have?

Note that we are not given that x is an integer. So, x can take any decimal values as well.

When x = 0.5, y = 1
When x = 1, y = 2
When x = 1.5, y = 3

Thus, y can take 3 integer values only. So, for this question, the correct answer will be D.

Does this clarify your doubt?

Best Regards, Japinder
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Re: If y = |2 + x| - |2 – x| and |2x – 15| < 2, how many integer values  [#permalink]

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New post 02 Dec 2015, 16:24
EgmatQuantExpert wrote:
Official Explanation

Correct Answer: B

|2x – 15| < 2

Can also be written as |x – 7.5| < 1

Image

The expression |x - 7.5| represents the distance between x and 7.5 on the number line.

The inequality |x - 7.5| < 1 means that the distance between x and 7.5 on the number line is less than 1.

This means, x lies between 6.5 and 8.5, exclusive.

Now, y = |2+x| - | 2 – x |

Rewriting this as
y = |x + 2| - | x – 2|

Here |x+2| represents the distance of x from -2 on the number line
And, |x-2| represents the distance of x from 2 on the number line.


Representing these 2 distances on number line:

Image

It’s easy to see that y = 4.

So, only 1 possible value of y.

Note: the question is asking about HOW MANY values y can have, not WHAT values y can have.


Hi Japinder,

Everything is clear to me untill the point you say that clearly y=4. Can you pls show me how we derive that y=4?

Thanks.

Regards.
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Re: If y = |2 + x| - |2 – x| and |2x – 15| < 2, how many integer values  [#permalink]

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New post 02 Dec 2015, 18:25
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elisabettaportioli wrote:


Hi Japinder,

Everything is clear to me untill the point you say that clearly y=4. Can you pls show me how we derive that y=4?

Thanks.

Regards.


Let me try to answer your question.

I am assuming that you were able to understand how you got 6.5<x<8.5 from |2x-15|<2.

Once you get this, you realize that for the interval 6.5 < x < 8.5, |2 + x| = 2+x and 2-x = -(2-x) = -2+x ....as |x-a| = x-a for x \(\geq\) a and = -(x-a) for x < a

So putting the above values in the equation for y, you get,

y = |2+x|-|2-x| = 2+x - (x-2) = 2+x -x +2 = 4

Hope this helps.
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Re: If y = |2 + x| - |2 – x| and |2x – 15| < 2, how many integer values  [#permalink]

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New post 04 Dec 2015, 02:23
1
Engr2012 wrote:
elisabettaportioli wrote:


Hi Japinder,

Everything is clear to me untill the point you say that clearly y=4. Can you pls show me how we derive that y=4?

Thanks.

Regards.


Let me try to answer your question.

I am assuming that you were able to understand how you got 6.5<x<8.5 from |2x-15|<2.

Once you get this, you realize that for the interval 6.5 < x < 8.5, |2 + x| = 2+x and 2-x = -(2-x) = -2+x ....as |x-a| = x-a for x \(\geq\) a and = -(x-a) for x < a

So putting the above values in the equation for y, you get,

y = |2+x|-|2-x| = 2+x - (x-2) = 2+x -x +2 = 4

Hope this helps.


ok, let me see If I got it right...

If 6.5<x<8.5, then x is positive.

Now, with this understanding we try to calculate the following equation y=|2+x|-|2-x| and to do so we need to know the value of |2+x| and |2-x| but since we know that x>0, we can consider only the positive case for |2+x| that leads to 2+x and the positive case for |2-x| that leads to 2-x.

Now we can substitute the values for the mods in the equation and we get

y=2+x-(2-x)=2+x-2+x=2x

The outcome I get is not 4 as it you should be. I only get 4 if I rearrange the sign inside the second mod, and precisely:
|2-x|=|x-2|

indeed y=2+x-(x-2)=2+x-x+2=4

Now my question is WHY SHOULD WE ASSUME THAT TO GET THE CORRECT ANSWER WE NEED TO ARRANGE THE SIGN IN |2-x|??

Please advise. Your contitube is pure gold!

Thanks.
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Re: If y = |2 + x| - |2 – x| and |2x – 15| < 2, how many integer values  [#permalink]

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New post 04 Dec 2015, 05:42
1
elisabettaportioli wrote:
Engr2012 wrote:

Let me try to answer your question.

I am assuming that you were able to understand how you got 6.5<x<8.5 from |2x-15|<2.

Once you get this, you realize that for the interval 6.5 < x < 8.5, |2 + x| = 2+x and 2-x = -(2-x) = -2+x ....as |x-a| = x-a for x \(\geq\) a and = -(x-a) for x < a

So putting the above values in the equation for y, you get,

y = |2+x|-|2-x| = 2+x - (x-2) = 2+x -x +2 = 4

Hope this helps.


ok, let me see If I got it right...

If 6.5<x<8.5, then x is positive.

Now, with this understanding we try to calculate the following equation y=|2+x|-|2-x| and to do so we need to know the value of |2+x| and |2-x| but since we know that x>0, we can consider only the positive case for |2+x| that leads to 2+x and the positive case for |2-x| that leads to 2-x.

Now we can substitute the values for the mods in the equation and we get

y=2+x-(2-x)=2+x-2+x=2x

The outcome I get is not 4 as it you should be. I only get 4 if I rearrange the sign inside the second mod, and precisely:
|2-x|=|x-2|

indeed y=2+x-(x-2)=2+x-x+2=4

Now my question is WHY SHOULD WE ASSUME THAT TO GET THE CORRECT ANSWER WE NEED TO ARRANGE THE SIGN IN |2-x|??

Please advise. Your contitube is pure gold!

Thanks.


Ok. Couple of things. Text in red above is not correct. Second, you need to brush up your knowledge of absolute values. Look here math-absolute-value-modulus-86462.html

Once you get that 6.5<x<8.5, this means that x is not just positive but this range of 'x' will also give you |2-x| = -(2-x) and NOT 2-x

This is because, |a-b| = -(a-b) if a < b. So in our example as all values of 'x' will be >2 , |2-x| = -(2-x).

Text in greegn above "WHY SHOULD WE ASSUME THAT TO GET THE CORRECT ANSWER WE NEED TO ARRANGE THE SIGN IN |2-x|??" is absolutely the wrong way of looking at the correct logic behind this question. We are not assuming anything. We are going by the rules of absolute values.

Hope this helps.
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Re: If y = |2 + x| - |2 – x| and |2x – 15| < 2, how many integer values  [#permalink]

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New post 16 May 2017, 10:32
EgmatQuantExpert wrote:
If y = |2 + x| - |2 – x| and |2x – 15| < 2, how many integer values can y take?

(A) 0
(B) 1
(C) 2
(D) 4
(E) Cannot be determined


This is Question 4 for the e-GMAT Question Series on Absolute Value.

Provide your solution below. Kudos for participation. Happy Solving! :-D

Best Regards
The e-GMAT Team

Image


Hey..i got it in 1:49:)

from mod(2x+15)<2 we get
lx+7.5l<1 i.e. distance of x from -7.5 or 7.5 is less than 1

therefore -8.5<x<-6.5 or 6.5<x<8.5 ....as the question is screaming integer...test first the integer value say 7
wwe get y = 4

now test any decimal value say 8.4 and 6.6...we get non integer value
just to be sure try another non integer value say -8.3 and -6.6 we get no integer vakue

so only one integer value...

But i need a concept clarity
it is said that one should interpret lxl as distance of x from zero i.e. lx-0l..so drawing a parallel we can interpret lx-7l as distance of x from 7
my question, so should we interpret lx+7l as distance of x from (-) 7??...had i been sure about it..i would not have tried above question from both positive and negative values..

Pl help:)
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Re: If y = |2 + x| - |2 – x| and |2x – 15| < 2, how many integer values  [#permalink]

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New post 13 Jul 2017, 08:25
1
reto wrote:
EgmatQuantExpert wrote:
If y = |2 + x| - |2 – x| and |2x – 15| < 2, how many integer values can y take?

(A) 0
(B) 1
(C) 2
(D) 4
(E) Cannot be determined


This is Question 4 for the e-GMAT Question Series on Absolute Value.

Provide your solution below. Kudos for participation. The Official Answer and Explanation will be posted on 22nd May.

Till then, Happy Solving! :-D

Best Regards
The e-GMAT Team


Here's how to solve it:

First find the range of values for x:

Inequalities involving absolute values - here you have a number case again. First solve like this without the brackets:

2x – 15 < 2
2x < 17
x < 8.5

Second case (FLIP the sign and put a negative sign around the other side of the inequality):

2x – 15 > -2
x>6.5

Hence: 6.5<x<8.5 >>> since x is an integer, only 7 is possible as a value.

Now put in 7 in If y = |2 + x| - |2 – x| to see that there is only 1 solution. ANSWER CHOICE A



integer values possible are 7 and 8.
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Re: If y = |2 + x| - |2 – x| and |2x – 15| < 2, how many integer values  [#permalink]

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New post 26 Jul 2017, 13:59
elisabettaportioli wrote:
EgmatQuantExpert wrote:
Official Explanation

Correct Answer: B

|2x – 15| < 2

Can also be written as |x – 7.5| < 1

Image

The expression |x - 7.5| represents the distance between x and 7.5 on the number line.

The inequality |x - 7.5| < 1 means that the distance between x and 7.5 on the number line is less than 1.

This means, x lies between 6.5 and 8.5, exclusive.

Now, y = |2+x| - | 2 – x |

Rewriting this as
y = |x + 2| - | x – 2|

Here |x+2| represents the distance of x from -2 on the number line
And, |x-2| represents the distance of x from 2 on the number line.


Representing these 2 distances on number line:

Image

It’s easy to see that y = 4.

So, only 1 possible value of y.

Note: the question is asking about HOW MANY values y can have, not WHAT values y can have.


Hi Japinder,

Everything is clear to me untill the point you say that clearly y=4. Can you pls show me how we derive that y=4?

Thanks.

Regards.


hi

as far as the number line is concerned, just subtract -2 from 2, a difference revealing the number of numbers y can take...

hope this helps ...
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Re: If y = |2 + x| - |2 – x| and |2x – 15| < 2, how many integer values  [#permalink]

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New post 13 Jul 2019, 12:56
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Question 1: If y = |2 + x| - |2 – x| and |2x – 15| < 2, how many integer values can y take?
|2x – 15| < 2 --> 6.5<x<8.5

Take x = 6.5
y = |2+6.5| - |2-6.5| = 8.5 - 4.5 = 4
MIN y = 4

Take x = 8.5
y = |2+8.5| - |2-8.5| = 10.5 - 6.5 = 4
MAX y = 4
So y can only have 1 value, or for any value of x in the range, y = 4

Image

Question 2: If y = |2 + x| - |2 – x| and |x – 1| < 1, how many integer values can y take?
|x – 1| < 1 --> 0<x<2

Take x = 0
y = |2+0| - |2-0| = 2 - 2 = 0
MIN y = 0

Take x = 2
y = |2+2| - |2-2| = 4 - 0 = 4
MAX y = 4
So y can have 3 int values, 1,2 & 3 for the range 0<x<2

Image

EgmatQuantExpert is it OK to consider the problem as finding the MIN/MAX of y?
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Re: If y = |2 + x| - |2 – x| and |2x – 15| < 2, how many integer values  [#permalink]

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New post 14 Jul 2019, 10:10
reto wrote:
EgmatQuantExpert wrote:
If y = |2 + x| - |2 – x| and |2x – 15| < 2, how many integer values can y take?

(A) 0
(B) 1
(C) 2
(D) 4
(E) Cannot be determined


This is


Provide your solution below. Kudos for participation. The Official Answer and Explanation will be posted on 22nd May.

Till then, Happy Solving! :-D

Best Regards
The e-GMAT Team


[b]Here's how to solve it:

First find the range of values for x:

Inequalities involving absolute values - here you have a number case again. First solve like this without the brackets:

2x – 15 < 2
2x < 17
x < 8.5

Second case (FLIP the sign and put a negative sign around the other side of the inequality):

2x – 15 > -2
x>6.5

Hence: 6.5<x<8.5 >>> since x is an integer, only 7 is possible as a value.

Now put in 7 in If y = |2 + x| - |2 – x| to see that there is only 1 solution. ANSWER CHOICE A


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"Hence: 6.5<x<8.5 >>> since x is an integer, only 7 is possible as a value."

Why is 8 not possible as a value? Integers less than 8.5 and greater 6.5 are 7 and 8, is it not?
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Wizard of Oddz
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GMAT Club Bot
Re: If y = |2 + x| - |2 – x| and |2x – 15| < 2, how many integer values   [#permalink] 14 Jul 2019, 10:10
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If y = |2 + x| - |2 – x| and |2x – 15| < 2, how many integer values

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