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In a weight-lifting competition, the total weight of Joe's t

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In a weight-lifting competition, the total weight of Joe's t [#permalink] New post   17 Dec 2012, 08:47
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In a weight-lifting competition, the total weight of Joe's two lifts was 750 pounds. If twice the weight of his first lift was 300 pounds more than the weight of his second lift, what was the weight, in pounds, of his first lift?

(A) 225
(B) 275
(C) 325
(D) 350
(E) 400
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D
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Re: In a weight-lifting competition, the total weight of Joe's t [#permalink] New post   08 Sep 2014, 01:25
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Let the first lift = x

Second lift = 750 - x

Setting up the equation

2x = 750 - x + 300

x = 250+100 = 350

Answer = D
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Re: In a weight-lifting competition, the total weight of Joe's t [#permalink] New post   17 Dec 2012, 08:50
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Walkabout wrote:
In a weight-lifting competition, the total weight of Joe's two lifts was 750 pounds. If twice the weight of his first lift was 300 pounds more than the weight of his second lift, what was the weight, in pounds, of his first lift?

(A) 225
(B) 275
(C) 325
(D) 350
(E) 400


Let x and y be the weights of first and second lifts, respectively. Then:

x + y = 750 (the total weight of Joe's two lifts was 750 pounds);
2x = y + 300 (twice the weight of his first lift was 300 pounds more than the weight of his second lift);

Solving gives x = 350.

Answer: D.
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Re: In a weight-lifting competition, the total weight of Joe's t [#permalink] New post   21 Jun 2016, 10:34
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Walkabout wrote:
In a weight-lifting competition, the total weight of Joe's two lifts was 750 pounds. If twice the weight of his first lift was 300 pounds more than the weight of his second lift, what was the weight, in pounds, of his first lift?

(A) 225
(B) 275
(C) 325
(D) 350
(E) 400


This problem is a general word translation. We first define variables and then set up equations.

We can define the following variables:

F = the weight of the first lift

S = the weight of the second lift

We are given that the total weight of Joe's two lifts was 750 pounds. We sum the two variables to obtain:

F + S = 750

We are also given that twice the weight of his first lift was 300 pounds more than the weight of his second lift. We express this as:

2F = 300 + S

2F – 300 = S

We can now plug in (2F – 300) for S into the first equation, so we have:

F + 2F – 300 = 750

3F = 1,050

F = 350

Answer is D.
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Re: In a weight-lifting competition, the total weight of Joe's t [#permalink] New post   06 Feb 2018, 12:07
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Walkabout wrote:
In a weight-lifting competition, the total weight of Joe's two lifts was 750 pounds. If twice the weight of his first lift was 300 pounds more than the weight of his second lift, what was the weight, in pounds, of his first lift?

(A) 225
(B) 275
(C) 325
(D) 350
(E) 400


Let's solve the question using ONE VARIABLE.

The total weight of Joe's two lifts was 750 pounds.
Let x = weight of first lift
So, 750 - x = weight of second lift


...twice the weight of his first lift was 300 pounds more than the weight of his second lift
In other words, (2)(first lift) = second lift + 300
Or...(2)(x) = (750 - x) + 300
Simplify: 2x = 1050 - x
Rearrange: 3x = 1050
x = 350

Answer: D

Cheers,
Brent
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Re: In a weight-lifting competition, the total weight of Joe's t [#permalink] New post   19 Aug 2019, 11:45
Walkabout wrote:
In a weight-lifting competition, the total weight of Joe's two lifts was 750 pounds. If twice the weight of his first lift was 300 pounds more than the weight of his second lift, what was the weight, in pounds, of his first lift?

(A) 225
(B) 275
(C) 325
(D) 350
(E) 400


Just work through the options. Try the nicer numbers first.
F=350. S=(2*350)-300=400.
350+400 is 750. Works. Hence D.
You can write equations but if you have clear and easy numbers may be you should just work through options. :)

Thank you!
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Re: In a weight-lifting competition, the total weight of Joe's t [#permalink] New post   19 Aug 2019, 19:02
Walkabout wrote:
In a weight-lifting competition, the total weight of Joe's two lifts was 750 pounds. If twice the weight of his first lift was 300 pounds more than the weight of his second lift, what was the weight, in pounds, of his first lift?

(A) 225
(B) 275
(C) 325
(D) 350
(E) 400


Given: In a weight-lifting competition, the total weight of Joe's two lifts was 750 pounds.

Asked: If twice the weight of his first lift was 300 pounds more than the weight of his second lift, what was the weight, in pounds, of his first lift?

Let the weights of first and second lifts be w1 and w2 respectively

w1+w2=750
2w1-300=w2
w1+2w1-300=750
3w1=1050
w1=350

IMO D

Posted from my mobile device
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Re: In a weight-lifting competition, the total weight of Joe's t [#permalink] New post   01 Sep 2020, 12:51
Walkabout wrote:
In a weight-lifting competition, the total weight of Joe's two lifts was 750 pounds. If twice the weight of his first lift was 300 pounds more than the weight of his second lift, what was the weight, in pounds, of his first lift?

(A) 225
(B) 275
(C) 325
(D) 350
(E) 400


f + s = 750

2f - 300 = s

f + ( 2f - 300 ) = 750

Or, 3f = 1050

Or, f = 350, Answer must be (D)
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Re: In a weight-lifting competition, the total weight of Joe's t [#permalink] New post   18 Dec 2023, 11:09
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