In a weight-lifting competition, the total weight of Joe's t

Question

In a weight-lifting competition, the total weight of Joe's two lifts was 750 pounds. If twice the weight of his first lift was 300 pounds more than the weight of his second lift, what was the weight, in pounds, of his first lift?

(A) 225
(B) 275
(C) 325
(D) 350
(E) 400

(A) 225
(B) 275
(C) 325
(D) 350
(E) 400

Bunuel · Answer

Let x and y be the weights of first and second lifts, respectively. Then:

x + y = 750 (the total weight of Joe's two lifts was 750 pounds);
2x = y + 300 (twice the weight of his first lift was 300 pounds more than the weight of his second lift);

Solving gives x = 350.

Answer: D.

PareshGmat · Answer

Let the first lift = x

Second lift = 750 - x

Setting up the equation

2x = 750 - x + 300

x = 250+100 = 350

Answer = D

JeffTargetTestPrep · Answer

This problem is a general word translation. We first define variables and then set up equations.

We can define the following variables:

F = the weight of the first lift

S = the weight of the second lift

We are given that the total weight of Joe's two lifts was 750 pounds. We sum the two variables to obtain:

F + S = 750

We are also given that twice the weight of his first lift was 300 pounds more than the weight of his second lift. We express this as:

2F = 300 + S

2F – 300 = S

We can now plug in (2F – 300) for S into the first equation, so we have:

F + 2F – 300 = 750

3F = 1,050

F = 350

Answer is D.

BrentGMATPrepNow · Answer

Let's solve the question using ONE VARIABLE.

The total weight of Joe's two lifts was 750 pounds . 
Let  x  = weight of first lift
So,  750 - x  = weight of second lift

...twice the weight of his  first lift  was 300 pounds more than the weight of his  second lift   
In other words, (2)( first lift ) =  second lift  + 300
Or...(2) (x)  =  (750 - x)  + 300
Simplify: 2x = 1050 - x
Rearrange: 3x = 1050
x = 350

Answer: D

Cheers,
Brent

TheNightKing · Answer

Just work through the options. Try the nicer numbers first. F=350. S=(2*350)-300=400. 350+400 is 750. Works. Hence D. You can write equations but if you have clear and easy numbers may be you should just work through options.

Thank you!

Kinshook · Answer

Given: In a weight-lifting competition, the total weight of Joe's two lifts was 750 pounds.

Asked: If twice the weight of his first lift was 300 pounds more than the weight of his second lift, what was the weight, in pounds, of his first lift?

Let the weights of first and second lifts be w1 and w2 respectively

w1+w2=750
2w1-300=w2
w1+2w1-300=750
3w1=1050
w1=350

IMO D

Posted from my mobile device

Abhishek009 · Answer

f + s = 750

2f - 300 = s

f + ( 2f - 300 ) = 750

Or, 3f = 1050

Or, f = 350, Answer must be (D)

totaltestprepNick · Answer

D https://www.youtube.com/watch?v=2OX1Jv3K6Ug Nick Slavkovich, GMAT/GRE tutor with 20+ years of experience tutoring@totaltestprep.net

In a weight-lifting competition, the total weight of Joe's t

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