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In the xy-coordinate system, line k passes through points (-5m, 0) and

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Bunuel
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In the xy-coordinate system, line k passes through points (-5m, 0) and [#permalink] New post   26 Mar 2015, 04:39
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In the xy-coordinate system, line k passes through points (-5m, 0) and (0, 2m). Which of the following is a possible equation of line k?

A. y = -5/2*x + 2m
B. y = 2/5*x - 5m
C. y = 5/2*x + 2m
D. y = 2/5*x + 2m
E. y = -2/5*x - 5m


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D
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Re: In the xy-coordinate system, line k passes through points (-5m, 0) and [#permalink] New post   26 Mar 2015, 07:20
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Bunuel wrote:
In the xy-coordinate system, line k passes through points (-5m, 0) and (0, 2m). Which of the following is a possible equation of line k?

A. y = -5/2*x + 2m
B. y = 2/5*x - 5m
C. y = 5/2*x + 2m
D. y = 2/5*x + 2m
E. y = -2/5*x - 5m


Kudos for a correct solution.


METHOD 2:

points are (-5m, 0) and (0, 2m)

Slope = (Y2-Y1) / (X2-X1) = (2m - 0) / (0 - (-5m) ) = 2m / 5m = 2/5

OPTION A, C and E can be Ruled out as they have a different slope

Among Option B and D, check the option by substituting any point

Option B - y = 2/5*x - 5m
Checking point (0, 2m) --- at x=0, we get y is NOT equal to 2m so a NOT a possible answer (Ruled Out)

i.e. Option
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D
is Correct Option
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Re: In the xy-coordinate system, line k passes through points (-5m, 0) and [#permalink] New post   26 Mar 2015, 07:16
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Bunuel wrote:
In the xy-coordinate system, line k passes through points (-5m, 0) and (0, 2m). Which of the following is a possible equation of line k?

A. y = -5/2*x + 2m
B. y = 2/5*x - 5m
C. y = 5/2*x + 2m
D. y = 2/5*x + 2m
E. y = -2/5*x - 5m


Kudos for a correct solution.


Method 1:

USE OPTIONS

Correct option will satisfy both the given points (-5m, 0) and (0, 2m)

A. y = -5/2*x + 2m
Checking point (0, 2m) --- at x=0, we get y = 2m so a possible answer
Checking point (-5m, 0) --- at y=0, we get x is NOT equal to -5m so a NOT a possible answer (Ruled Out)


B. y = 2/5*x - 5m
Checking point (0, 2m) --- at x=0, we get y is NOT equal to 2m so a NOT a possible answer (Ruled Out)


C. y = 5/2*x + 2m
Checking point (0, 2m) --- at x=0, we get y = 2m so a possible answer
Checking point (-5m, 0) --- at y=0, we get x is NOT equal to -5m so a NOT a possible answer (Ruled Out)


D. y = 2/5*x + 2m
Checking point (0, 2m) --- at x=0, we get y = 2m so a possible answer
Checking point (-5m, 0) --- at y=0, we get x = -5m so THE CORRECT ANSWER


E. y = -2/5*x - 5m
Checking point (0, 2m) --- at x=0, we get y is NOT equal to 2m so a NOT a possible answer (Ruled Out)
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Re: In the xy-coordinate system, line k passes through points (-5m, 0) and [#permalink] New post   25 Apr 2016, 02:10
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OPTION D is the OA.. for the people who are having difficulty in getting the Y-intercept, it is already given in the question where we have a point (0 , 2m) --> which means that the value of x is 0 and the line intersects the Y axis at 2m.
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In the xy-coordinate system, line k passes through points (-5m, 0) and [#permalink] New post   26 Mar 2015, 06:18
Bunuel wrote:
In the xy-coordinate system, line k passes through points (-5m, 0) and (0, 2m). Which of the following is a possible equation of line k?

A. y = -5/2*x + 2m
B. y = 2/5*x - 5m
C. y = 5/2*x + 2m
D. y = 2/5*x + 2m
E. y = -2/5*x - 5m


Kudos for a correct solution.



Answer D
Slope =\(\frac{2}{5}\)
Y intercept is given to us as 2m .

equation of line \(y= \frac{2}{5}x+ 2m\)

if m is -ive line will go through \(1^s^t, 3^r^d and 4^t^h\) quadrants
if m is +ive line will go through \(1^s^t, 2^n^d and 3^r^d\) quadrants
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Re: In the xy-coordinate system, line k passes through points (-5m, 0) and [#permalink] New post   30 Mar 2015, 03:39
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Bunuel wrote:
In the xy-coordinate system, line k passes through points (-5m, 0) and (0, 2m). Which of the following is a possible equation of line k?

A. y = -5/2*x + 2m
B. y = 2/5*x - 5m
C. y = 5/2*x + 2m
D. y = 2/5*x + 2m
E. y = -2/5*x - 5m


Kudos for a correct solution.


MAGOOSH OFFICIAL SOLUTION:
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In the xy-coordinate system, line k passes through points (-5m, 0) and [#permalink] New post   14 Jul 2016, 07:27
Bunuel wrote:
In the xy-coordinate system, line k passes through points (-5m, 0) and (0, 2m). Which of the following is a possible equation of line k?

A. y = -5/2*x + 2m
B. y = 2/5*x - 5m
C. y = 5/2*x + 2m
D. y = 2/5*x + 2m
E. y = -2/5*x - 5m


Kudos for a correct solution.


The fastest and easiest way to look for a line is to look for its slope .. more often than not the slope gives a pretty good idea of what one should look for
Slope (M)= \(\frac{y2-y1}{x2-x1}\)

slope= \(\frac{2m-0}{0-(-5m)}\)

Slope = \(\frac{2m}{5m} ==>\frac{2}{5}\)

SO our line will have a slope of \(\frac{2}{5}\)

which option corresponds to your slope of \(\frac{2}{5}\)

OPTION E

E is the correct answer
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Re: In the xy-coordinate system, line k passes through points (-5m, 0) and [#permalink] New post   23 Oct 2019, 19:07
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Bunuel wrote:
In the xy-coordinate system, line k passes through points (-5m, 0) and (0, 2m). Which of the following is a possible equation of line k?

A. y = -5/2*x + 2m
B. y = 2/5*x - 5m
C. y = 5/2*x + 2m
D. y = 2/5*x + 2m
E. y = -2/5*x - 5m


Kudos for a correct solution.



First, we determine the slope of line k:

(2m - 0)/(0 - (-5m)) = 2m/(5m) = 2/5

Next, we substitute (0, 2m) into the slope-intercept form of a line to determine the y-intercept.

2m = 2/5(0) + b

2m = b

So, the equation for line k is y = (2/5)x + 2m

Answer: D
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Re: In the xy-coordinate system, line k passes through points (-5m, 0) and [#permalink] New post   14 Apr 2022, 00:40
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Re: In the xy-coordinate system, line k passes through points (-5m, 0) and [#permalink]
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