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Re: Is the negative number x less than –1? [#permalink]
Bunuel wrote:
Is the negative number x less than –1?

(1) 1/x < 1/2
(2) 1/x^2 < 1/2


E

1. stmt 1 will hold true for x=-2 and for x=-0.5
insufficient

2. for x<-2, the given condition holds true
for -2<x<-1, the given condition fails,
for -1<x<0, the condition condition fails
insufficient

1&2 clearly insufficient
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Re: Is the negative number x less than –1? [#permalink]
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IMO B

x has to be less than -1from statetment 2

waiting for the OA
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Re: Is the negative number x less than –1? [#permalink]
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IMO its B -

1- \(1/x < 1/2\)
\(2/x < 1\)
\(x < 2\) -- we flip signs because we know X is negative and we're taking negative to the other side, or so I think we should do.

2- \(1/x^2 < 1/2\)

flipping sides, sign remains the same since we're dealing with \(x^2\)

\(x^2 > 2\) taking under root, we will be flipping the sign since we know x is negative.
\(x < 1.41\) - Not sufficient.


Combining both, we know x < 2 and and less than 1.41 but its still not sufficient to determine if X is less than -1. Answer should be E IMO. I may be making a dumb mistake so would love it if someone can correct me.
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Re: Is the negative number x less than –1? [#permalink]
gmatexam439 wrote:
Bunuel wrote:
Is the negative number x less than –1?

(1) 1/x < 1/2
(2) 1/x^2 < 1/2


E

1. stmt 1 will hold true for x=-2 and for x=-0.5
insufficient

2. for x<-2, the given condition holds true
for -2<x<-1, the given condition fails,
for -1<x<0, the condition condition fails
insufficient

1&2 clearly insufficient



I understand it should be "B" and not "E".
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Re: Is the negative number x less than –1? [#permalink]
1- 1/x < 1/2
Using -1/2 and -3/2 both satisfy the inequality, so insufficient.

2- 1/x^2 < 1/2
x^2 > 2 -> |x| > sqrt(2) -> x > sqrt(2) or x < -sqrt(2)
As we know also that x is negative, sufficient.

Answer: B
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Re: Is the negative number x less than –1? [#permalink]
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