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# M19-18

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Math Expert
Joined: 02 Sep 2009
Posts: 93698
Own Kudos [?]: 632363 [9]
Given Kudos: 82304
Math Expert
Joined: 02 Sep 2009
Posts: 93698
Own Kudos [?]: 632363 [1]
Given Kudos: 82304
Manager
Joined: 31 Jan 2017
Posts: 55
Own Kudos [?]: 94 [10]
Given Kudos: 25
Location: India
GMAT 1: 680 Q49 V34
GPA: 4
WE:Project Management (Energy and Utilities)
Intern
Joined: 08 Dec 2017
Posts: 2
Own Kudos [?]: 0 [0]
Given Kudos: 1
Location: India
Concentration: Marketing, Strategy
GMAT 1: 620 Q48 V27
GRE 1: Q168 V150
GPA: 3.9
WE:Marketing (Education)
I think this is a high-quality question and I agree with explanation. Assume a = 0
(x)2+(x−4)2

-1 --- 10
0 --- 16
2 --- 8
3 --- 10
5 ---- 26

So the answer is option C
Current Student
Joined: 01 Jun 2020
Posts: 131
Own Kudos [?]: 8 [0]
Given Kudos: 12
Location: Brazil
GMAT 1: 760 Q48 V46
I think this is a high-quality question and I agree with explanation.
Math Expert
Joined: 02 Sep 2009
Posts: 93698
Own Kudos [?]: 632363 [0]
Given Kudos: 82304
I have edited the question and the solution by adding more details to enhance its clarity. I hope it is now easier to understand.
Manager
Joined: 07 Mar 2020
Posts: 113
Own Kudos [?]: 67 [0]
Given Kudos: 52
GMAT 1: 680 Q49 V34
We are give $$(x-a)^2-(x-b)^2$$, and since both are squared values, the least possible value for the whole expression can be 0.
Now doing $$(x-a)^2-(x-b)^2=0$$. Now $$(x-a)^2=-(x-b)^2$$.
1) $$x-a=x-b=0$$ (this does not give us any value of x, thus ignore this case.)
2) $$x-a=b-x$$ , we get $$2x=b+a$$, replace b with a+4 as given, we get $$x=a+2$$.