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Math Expert
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Re: M19-18 [#permalink]
I think this is a high-quality question and I agree with explanation. Assume a = 0
(x)2+(x−4)2

-1 --- 10
0 --- 16
2 --- 8
3 --- 10
5 ---- 26

So the answer is option C
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Re: M19-18 [#permalink]
I think this is a high-quality question and I agree with explanation.
Math Expert
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Re: M19-18 [#permalink]
Expert Reply
I have edited the question and the solution by adding more details to enhance its clarity. I hope it is now easier to understand.
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Re: M19-18 [#permalink]
We are give \((x-a)^2-(x-b)^2\), and since both are squared values, the least possible value for the whole expression can be 0.
Now doing \((x-a)^2-(x-b)^2=0\). Now \((x-a)^2=-(x-b)^2\).
Ignore this -ve sign(as LHS is square number and RHS can't be -ve), and take square root on both sides.
There can be 2 cases:-
1) \(x-a=x-b=0\) (this does not give us any value of x, thus ignore this case.)
2) \(x-a=b-x\) , we get \(2x=b+a\), replace b with a+4 as given, we get \(x=a+2\).
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Re: M19-18 [#permalink]
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