Last visit was: 22 May 2025, 11:59 It is currently 22 May 2025, 11:59
Close
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track
Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Close
Request Expert Reply
Confirm Cancel
User avatar
Bunuel
User avatar
Math Expert
Joined: 02 Sep 2009
Last visit: 22 May 2025
Posts: 101,654
Own Kudos:
726,301
 [9]
Given Kudos: 93,600
Products:
Expert
Expert reply
Active GMAT Club Expert! Tag them with @ followed by their username for a faster response.
Posts: 101,654
Kudos: 726,301
 [9]
Kudos
Add Kudos
9
Bookmarks
Bookmark this Post
User avatar
Bunuel
User avatar
Math Expert
Joined: 02 Sep 2009
Last visit: 22 May 2025
Posts: 101,654
Own Kudos:
726,301
 [1]
Given Kudos: 93,600
Products:
Expert
Expert reply
Active GMAT Club Expert! Tag them with @ followed by their username for a faster response.
Posts: 101,654
Kudos: 726,301
 [1]
Kudos
Add Kudos
1
Bookmarks
Bookmark this Post
User avatar
Spartan85
Joined: 31 Jan 2017
Last visit: 16 Jul 2018
Posts: 53
Own Kudos:
99
 [11]
Given Kudos: 25
Location: India
Concentration: Strategy, Leadership
GMAT 1: 680 Q49 V34
GPA: 4
WE:Project Management (Energy)
Products:
GMAT 1: 680 Q49 V34
Posts: 53
Kudos: 99
 [11]
5
Kudos
Add Kudos
6
Bookmarks
Bookmark this Post
avatar
KSANDEEPREDDY
Joined: 08 Dec 2017
Last visit: 20 Oct 2020
Posts: 2
Given Kudos: 1
Location: India
Concentration: Marketing, Strategy
GMAT 1: 620 Q48 V27
GRE 1: Q168 V150
GPA: 3.9
WE:Marketing (Education)
GMAT 1: 620 Q48 V27
GRE 1: Q168 V150
Posts: 2
Kudos: 0
Kudos
Add Kudos
Bookmarks
Bookmark this Post
I think this is a high-quality question and I agree with explanation. Assume a = 0
(x)2+(x−4)2

-1 --- 10
0 --- 16
2 --- 8
3 --- 10
5 ---- 26

So the answer is option C
User avatar
RenanBragion
User avatar
Current Student
Joined: 01 Jun 2020
Last visit: 13 Apr 2025
Posts: 129
Own Kudos:
Given Kudos: 12
Location: Brazil
GMAT 1: 760 Q48 V46
Products:
GMAT 1: 760 Q48 V46
Posts: 129
Kudos: 13
Kudos
Add Kudos
Bookmarks
Bookmark this Post
I think this is a high-quality question and I agree with explanation.
User avatar
Bunuel
User avatar
Math Expert
Joined: 02 Sep 2009
Last visit: 22 May 2025
Posts: 101,654
Own Kudos:
Given Kudos: 93,600
Products:
Expert
Expert reply
Active GMAT Club Expert! Tag them with @ followed by their username for a faster response.
Posts: 101,654
Kudos: 726,301
Kudos
Add Kudos
Bookmarks
Bookmark this Post
I have edited the question and the solution by adding more details to enhance its clarity. I hope it is now easier to understand.
User avatar
rickyric395
Joined: 07 Mar 2020
Last visit: 22 May 2025
Posts: 114
Own Kudos:
Given Kudos: 55
GMAT 1: 680 Q49 V34
Products:
GMAT 1: 680 Q49 V34
Posts: 114
Kudos: 86
Kudos
Add Kudos
Bookmarks
Bookmark this Post
We are give \((x-a)^2-(x-b)^2\), and since both are squared values, the least possible value for the whole expression can be 0.
Now doing \((x-a)^2-(x-b)^2=0\). Now \((x-a)^2=-(x-b)^2\).
Ignore this -ve sign(as LHS is square number and RHS can't be -ve), and take square root on both sides.
There can be 2 cases:-
1) \(x-a=x-b=0\) (this does not give us any value of x, thus ignore this case.)
2) \(x-a=b-x\) , we get \(2x=b+a\), replace b with a+4 as given, we get \(x=a+2\).
User avatar
bumpbot
User avatar
Non-Human User
Joined: 09 Sep 2013
Last visit: 04 Jan 2021
Posts: 36,918
Own Kudos:
Posts: 36,918
Kudos: 991
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Hello from the GMAT Club BumpBot!

Thanks to another GMAT Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).

Want to see all other topics I dig out? Follow me (click follow button on profile). You will receive a summary of all topics I bump in your profile area as well as via email.
Moderators:
Math Expert
101653 posts
Founder
40717 posts