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Re: M28-42 [#permalink]
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fitzpratik wrote:
can someone please explain why mean of set A is 3?
thanks a ton


\(A=\{ 3-2x, \ 3-x, \ 3, \ 3+x, \ 3+2x\}\),

Mean = (the sum of the terms)/(the number of the terms) = (3 -2x + 3 - x + 3 + 3 + x + 3 + 2x)/5 = 15/5 = 3.

Hope it helps.
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Re: M28-42 [#permalink]
fitzpratik wrote:
can someone please explain why mean of set A is 3?
thanks a ton


I understood, As the terms are equally spaced out, Median = Mean. so as median is 3, Mean is 3. Am I right?
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Re: M28-42 [#permalink]
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fitzpratik wrote:
I understood, As the terms are equally spaced out, Median = Mean. so as median is 3, Mean is 3. Am I right?


Yes, you're right. It's an equally spaced set (going up by x from one term to the next), so the median, which is 3, must also be the mean.
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Re: M28-42 [#permalink]
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Re: M28-42 [#permalink]
I think this is a high-quality question and I agree with explanation.
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Re: M28-42 [#permalink]
This is a great question. I was able to eliminate A but while solving B i assumed that x is not equal to 0. I think it is important to move on from statement to statement otherwise there is a high probability of making a mistake.
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Re: M28-42 [#permalink]
I think this is a high-quality question and I agree with explanation.
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Re: M28-42 [#permalink]
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I have edited the question and the solution by adding more details to enhance its clarity. I hope it is now easier to understand.
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Re: M28-42 [#permalink]
Hello from the GMAT Club BumpBot!

Thanks to another GMAT Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).

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Re: M28-42 [#permalink]
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